BITSAT Mock Test - 3 - JEE MCQ

The magnitude of the induced electric field at point P at a distance r from the centre of the circular region decreases as ^.

Total resistance = 4 + 1 + 0.5 + 0.5 = 6 Ω
Net voltage in the circuit is 18 V. Current I = 18/6 = 3 A in the anti-clockwise direction
Current is being forced into the 6 V battery in the opposite direction.
Hence, V₆ = E + Ir = 6 + 3 1 = 9 V
Hence, the correct choice is (3).

Solving for v in terms of t, we get
.
Applying the initial conditions at t = 0 and v = 0 (as the object is dropped), we get .
Thus, the expression for v is equal to , where the velocity is constant and acceleration is zero.
Hence, v =
Substituting for the value of v and solving for 't', we get the value of t as infinity.

Magnetic field at a distance 'r' along the axis of a circular wire having radius R is given by,

For r >> R,

or,

A compound is soluble in water when its hydration enthalpy is greater than its lattice enthalpy.

Potassium metabisulphite and potassium sulphite are used as a source of sulphur dioxide, which reacts with H₂O to form sulphurous acid.
Sulphurous acid inhibits the growth of bacteria, fungi, yeast and moulds.
K₂S₂O₅ → K₂SO₃ + SO₂
SO₂ + H₂O → H₂SO₃

In case of nitrogen,
N₂ → N₂⁺ + e^-
An electron is lost from bonding MO and the bond order decreases from 3 to 2.5. As a result, bond dissociation energy decreases and the bond length increases.
The bond order of the nitrogen-oxygen bond in NO⁺ is three (triple bond), whereas in NO, the one additional electron is located in an antibonding MO. Therefore, the bond order in NO is 2.5. Thus, bond length in NO⁺ is less than in NO because bond length is inversely proportional to bond order.
Bond orders of and O₂ are 1 and 2, respectively. Therefore, O₂ bond must be shorter as bond length is inversely proportional to bond order.

8% sulphur by mass means 8 g of sulphur is present in 100 g of compound.
Therefore, 32 g of sulphur (1 mole atom) will be present in x 32 = 400 g of compound.
[∵ Compound must have at least one atom of sulphur]
^⇒ Minimum molecular mass = 400 g

G lives at the right end of the horizontal block. A lives at the top of the vertical block. D is at the point where the horizontal and vertical blocks meet.

F is third from the left end in the horizontal row. B is third from the bottom in the vertical column.

As the residing place for C and E is not defined, there are two possibilities:

D's position is 1^st from the bottom end.

From Problem Figure (1) to (2), the figure on the bottom left position is eliminated and a new figure is formed on top of the bottom right figure. From figure (2) to (3), figure shifts to half-side in clockwise direction and one new figure is added on top of the right figure. The same method is repeated in the subsequent figures.

Etiquette' means 'the customs or rules governing behaviour regarded as correct or acceptable in social or official life'.
'Protocol' means 'the official procedure or system of rules governing affairs of state or diplomatic occasions'.

The first and third letters of the first term are each moved five steps forward, while the second letter is moved three steps forward to obtain the corresponding letters of the second term.
K + 5 = P
N + 3 = Q
O + 5 = T
Hence, option (2) is correct.

The line with dot at the end alternately rotates 90^o and 135^o in the clockwise direction. Hence, the correct option is (4).

Out of statements D, A and C, only C makes the beginning as it talks about the joint venture which is explained in all the rest statements. As B starts with "this" and gives the names of two companies, it follows C. Now, we are left with A and D; as A explains proton cars, it follows B. This makes (4) as the best possible answer.

This passage is about the effects of highway bypass. 'The new road' in S refers to the 'highway bypass' in sentence 1. So, S is placed first in the sequence. 'This' in R refers to the 'new road' in S - new road would lead to more vehicles. Therefore, R follows S and we get the first pair SR.
The word 'finally' in P gives a clue that it should be the last in the sequence. That means Q precedes P and we get the pair QP. Moreover, 'increase vehicles' in R leads to 'increased noise and pollution' in Q.
Hence, we get the right sequence as SRQP. Option (1) is the correct answer.

g(x) = xf(x), where f(x) = x sin
at x = 0
g(0) = 0 f(0)
= 0 (0) = 0
g'(0) =
=
=
also g'(x) = xf'(x) + f(x)
g'(x) = [xf' (x) + f(x)]
= 0 + f(0) = 0 + 0 = g'(0)
∴ g'(x) = g'(0)
Hence g' is continuous and g(x) is differentiable.

Required area
=
=
=
= 1 sq. unit