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JEE Exam  >  JEE Tests  >  SRMJEEE Subject Wise & Full Length Mock Tests 2025  >  SRMJEE Aptitude Mock Test - 5 - JEE MCQ

SRMJEE Aptitude Mock Test - 5 - JEE MCQ


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20 Questions MCQ Test SRMJEEE Subject Wise & Full Length Mock Tests 2025 - SRMJEE Aptitude Mock Test - 5

SRMJEE Aptitude Mock Test - 5 for JEE 2025 is part of SRMJEEE Subject Wise & Full Length Mock Tests 2025 preparation. The SRMJEE Aptitude Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The SRMJEE Aptitude Mock Test - 5 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SRMJEE Aptitude Mock Test - 5 below.
Solutions of SRMJEE Aptitude Mock Test - 5 questions in English are available as part of our SRMJEEE Subject Wise & Full Length Mock Tests 2025 for JEE & SRMJEE Aptitude Mock Test - 5 solutions in Hindi for SRMJEEE Subject Wise & Full Length Mock Tests 2025 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt SRMJEE Aptitude Mock Test - 5 | 20 questions in 25 minutes | Mock test for JEE preparation | Free important questions MCQ to study SRMJEEE Subject Wise & Full Length Mock Tests 2025 for JEE Exam | Download free PDF with solutions
SRMJEE Aptitude Mock Test - 5 - Question 1
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If the price of a pen decreases by 20%, then a man can buy 10 more pens for Rs. 100. What is the new price (in Rs.) of each pen?

Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 1

Let the number of pens brought originally be x and the cost of each pen be y.
Therefore, according to the question,
x × y = 100 ... (1)
And (0.8*y) × (x + 10) = 100 ... (2)
From equation (2),
(0.8) × x × y + 8 × y = 100
Using equation (1),
(0.8) × (100) + 8 × y = 100
8 × y = 20
⇒ y = 2.5
Therefore, new price = (0.8) × y = 0.8 × 2.5 = Rs. 2

SRMJEE Aptitude Mock Test - 5 - Question 2
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The equation ax + 3y = 6 has slope -(2/3). What is the value of a?

Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 2

In general, y = mx + c, where m is the slope of the equation.
In the given question, the slope is -2/3.

a = 2
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SRMJEE Aptitude Mock Test - 5 - Question 3
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ΔABC ~ ΔEDF, and AB = 5 cm, BC = 8 cm and AC = 10 cm. If ar(ΔABC) : ar(ΔDEF) = 9 : 4, then DF is equal to:

Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 3

If two triangles are similar, then all corresponding sides are in the same proportion, while the ratio of their areas is equal to the square of this proportion.
Here, triangles ABC and EDF are similar.
Thus, by the above property,

Taking square root of both sides, we get
DF = 16/3 cm

SRMJEE Aptitude Mock Test - 5 - Question 4
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If a : b = 3 : 2, then (5a + 2b) : (3a + 4b) is equal to:
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 4

a : b = 3 : 2
Then, (5a + 2b) : (3a + 4b)
a/b = 3/2
So, a = 3 and b = 2
(5 × 3 + 2 × 2) : (3 × 3 + 4 × 2)
= 19 : 17

SRMJEE Aptitude Mock Test - 5 - Question 5
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If the six digit number 4x573y is divisible by 72, then the value of (x + y) is
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 5

The number has to be divisible by 9 and by 8.
So, divisible by 8 means that the last three digits of given number are divisible by 8.
73y is divisible by 8 only when y = 6.
So, using the standard test for divisibility by 9, 4 + x + 5 + 7 + 3 + 6 has to be divisible by 9.
Or (25 + x) has to be divisible by 9 only when x = 2.
Thus, x = 2 and y = 6.
So, (x + y) = (2 + 6) = 8
Check: = 5,913

SRMJEE Aptitude Mock Test - 5 - Question 6
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A dealer buys an article at a discount of 20% on its list price and marks it at 25% above the list price. If he allows a 20% discount on the new list price, then his profit percent is:
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 6

Let the marked price be Rs. 100.
The dealer buys at a discount of 20%.
Hence, his cost price = 100 – 20% of 100 = Rs. 80
New marked price = 100 + 25% 100 = 125
Hence, his selling price = 125 - 20% of 125 = Rs. 100
Profit % =

SRMJEE Aptitude Mock Test - 5 - Question 7
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If x2 - 4x + 4 = 0, then the value of 16is:
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 7

x2 - 4x + 4 = 0
x2 - 2x - 2x + 4 = 0
x(x - 2) - 2(x - 2) = 0
(x - 2)(x - 2) = 0
x = 2
Now,

= 162 - 1 = 255
Hence, answer option 4 is correct.

SRMJEE Aptitude Mock Test - 5 - Question 8
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A shopkeeper fixes the price of an article in such a way that after allowing 32% discount, he wants a gain of 14%. If the marked price is Rs. 342, then the cost price of the article is:
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 8

Marked price = Rs. 342
Selling price = Rs. 342 × = Rs. = Rs. 232.56
Let the cost price of the article be 100%.
Selling price = 100% + 14% = 114%
114% = Rs. 232.56
100% = Rs. = Rs. 204
Cost price of the article = Rs. 204
Hence, answer option 1 is correct.

SRMJEE Aptitude Mock Test - 5 - Question 9
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If 27N4 is divisible by 11, then what is the value of N?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 9
As per the condition, the difference between sum of digits at odd places and the sum at even places should be either 0 or divisible by 11.
So, N + 2 - (7 + 4) = N - 9 is equal to 0 or divisible by 11.
Thus, N = 9
SRMJEE Aptitude Mock Test - 5 - Question 10
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The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 – 8)}] ÷ (9 ÷ 3 × 2) is:
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 10


SRMJEE Aptitude Mock Test - 5 - Question 11
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As per the data in the table, what is the percentage of students who got 20 or more marks?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 11

Number of students who got 20 or more marks = 14 + 19 + 6 + 3 = 42
Total students = 13 + 15 + 18 + 12 + 14 + 19 + 6 + 3 = 100
Percentage of students who got 20 or more marks
Hence, option (4) is correct.

SRMJEE Aptitude Mock Test - 5 - Question 12
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A dishonest milkman added some water to milk and sold it at cost price. If he gained 20%, then what percentage of water did he add to milk? (It is to be assumed that adding water to milk costs him nothing.)
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 12

Let the CP of one litre of milk be Rs. 10.
Then, SP of one litre of mixture = Rs. 10
The gain is 20%.
Then, CP of one litre of mixture
By the rule of alligation,

Ratio of milk to water = : 25/3 : 5/3 = 5 : 1
Therefore, percentage of water added in the mixture

SRMJEE Aptitude Mock Test - 5 - Question 13
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For an article, the profit is 170% of the cost price. If the cost price increases by 20%, but the selling price remains same; then what will be the new profit percentage?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 13
Let the price of the article be Rs. 100.
Then, selling price = Rs. 270
Now, the price of the article turns Rs. 120, but the selling price remains Rs. 270.
Therefore, the profit becomes Rs. 150.
Profit percentage = 125%
SRMJEE Aptitude Mock Test - 5 - Question 14
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The slope of ax + 5y = 8 is -4/3. What is the value of a?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 14
ax + 5y = 8
⇒ 5y = -ax + 8
⇒ y = (-a/5)x + (8/5)
Slope equation of line, y = mx + c; where m = slope
ATQ,

⇒
SRMJEE Aptitude Mock Test - 5 - Question 15
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What is the simplified value of 1 + tan A tan (A/2)?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 15


SRMJEE Aptitude Mock Test - 5 - Question 16
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How many shoes are there of the Reebok brand?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 16

Number of shoes of the Reebok brand

SRMJEE Aptitude Mock Test - 5 - Question 17
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What is the difference between the number of shoes of Puma and Vans?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 17

Number of shoes of Puma = × 1200 = 252
Number of shoes of Vans = × 1200 = 156
Thus, difference = 252 - 156 = 96

SRMJEE Aptitude Mock Test - 5 - Question 18
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The difference between the number of shoes of Reebok and Nike is the same as the difference between the number of shoes of
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 18

Difference between the number of shoes of Reebok and Nike = (23 - 18)% of 1200 = 5% of 1200 = 60
(i) Puma and Adidas: Difference between the number of shoes of Puma and Adidas = (25 - 21)% of 1200 = 48
(ii) Reebok and Adidas: Difference between the number of shoes of Reebok and Adidas = (25 - 23)% of 1200 = 24
(iii) Vans and Nike: Difference between the number of shoes of Vans and Nike = (18 - 13)% of 1200 = 60
(iv) Nike and Adidas: Difference between the number of shoes of Nike and Adidas = (25 - 18)% of 1200 = 84
Thus, the difference between the number of shoes of Reebok and Nike is the same as the difference between the number of shoes of Vans and Nike.

SRMJEE Aptitude Mock Test - 5 - Question 19
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By what percent is the number of Puma shoes more than the number of of Nike shoes?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 19

Number of Nike shoes = × 1200 = 216
Number of Puma shoes = × 1200 = 252
Therefore, difference = 252 - 216 = 36
⇒ Required difference = × 100 = 16.66%

SRMJEE Aptitude Mock Test - 5 - Question 20
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When 2 is subtracted from each of the given n numbers, then the sum of the numbers so obtained is 102. When 5 is subtracted from each of them, then the sum of the numbers so obtained is 12. What is the average of the given n numbers?
Detailed Solution for SRMJEE Aptitude Mock Test - 5 - Question 20
Let the sum of the numbers be S and let there be n numbers.
Now, when 2 is subtracted from each of the numbers, their sum is 102.
Thus, S - 2n = 102
Or, S = 102 + 2n ... (i)
Also, when 5 is subtracted from each of the numbers, their sum is 12.
Thus, S - 5n = 12
Or, S = 12 + 5n ... (ii)
Now, equating the RHS of equations (i) and (ii), we get 102 + 2n = 12 + 5n
Or, n = 30
Now, replugging in n as 30 in equation (i), we get S = 102 + 2 × 30 = 162
Now, the average of the numbers = S/n = 162/30 = 5.4
Hence, answer option 3 is correct.
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