SRMJEE Mock Test - 10 (Engineering) - JEE MCQ

For the given reaction , we have
¹⁴N₇ + ⁴He₂ ¹⁶O₈ + ¹p₁
Hence proton is emitted.

If M is the mass of the earth, the gain in potential energy is given by

Hence the correct choice is (2). Remember, the expression PE = mgh is an approximate one which is valid if h << R.

From Einstein equation,
K = hc/λ - W
So,
2K = hc/λ₂ - W
Hence, we get
2hc/λ₁ - 2W = hc/λ₂ - W
W = hc[2/λ₁ - 1/λ₂]
= (6.62 × 10^-34) × (3 × 10⁸) [2/400 - 1/310] × 10⁹
= 3.52 × 10^-19 J
= 2.2 eV

From the hysteresis curve of soft iron we know Soft iron has high retentivity and low coercive force therefore the loop (i) is for soft iron and the loop (ii) is for steel.

i) In this case of current will flow from B top A. No current will flow through branch C, E (as marked in figure)

ii) Here current will flow from A to B so no current will flow in branch D

iii) Here also current will flow from A to B, so R_eq =  R same as (ii)
⇒   Rii = Riii < Ri

The resistance of a conductor is, 

Here, V = Al is the volume of the wire. As both the wires are made of copper, their densities are same.
Hence, mass of the wire is directly proportional to the volume.
Let l₁ & l₂ be the lengths of the two wires and m₁ & m₂ be their masses, respectively.

Given that, 

From equation (1)1, we can write,

The convection is process of heat transfer via medium but when glass surface is heated due to filament of bulb, it heated only due to radiation. It is because when glass bulb is manufactured, inside glass bulb, vacuum is maintained means there is no medium inside the bulb.

FBD of 1kg Block

Consider FBD of blocks as shown in fig
for 1 kg block and 2 kg block

Using Newtons 2nd law, acceleration of 2 kg block

acceleration of 1 kg block

Relative acceleration of 1 kg block with respect to 2 kg block is

Time taken for 1 kg block to fall off the planck

We know that 
Stress = Y × (strain)
where, Y is Young's modulus 
and stress = F/A and strain =Δl/l
and for linear expansion 
Δl = l× ΔT

We are given with, stress is same for both rods and ΔT is also same and α₁ / α₂ = 2 : 6
∴ for rod 1

For rod 2

taking ratio of (3) and (4) 

A parallel plate capacitor is connected to a battery of emf V₀. The separation between the plates at any time is given as x. The speed at which the plates are being pulled apart dx/dt = V is constant.

Electrostatic energy stored in the capacitor is 

Also, the capacitance is

C ∝ 1/x

From the above two equations,

U  ∝ 1/x

Hence, the rate of change of stored energy is 

SInce V is a constant, the rate of change of stored energy ∝ x⁻².

Reduction of one mole of to Cr⁺³ involves the transfer of six moles of electrons.
Required charge = 6 F = 6 × 96500 C [ one F = 96500 C]

Co₂(CO)₈ -  Oxidation no. of Co is zero

We know that antipyretics are those compounds that are applied to reduce the body temperature in fever.
Ex. Aspirin (acyl salicylic acid), paracetamol, phenacetin, novalgin, and analgin.

=
=
= 2 =2f(x)

f(x) = 5 - |x - 2|
f(x) attains maximum value when
|x - 2| = 0
x = 2 = α
g(x) = |x + 1|
g(x) attains minimum value when x = -1 = β

It is given that cos^-1 (1/x) = θ.
Hence, cos θ =
Now, in triangle ABC,

tan θ =

Let the equation of the ellipse be 

We have b² = a² (1-e²) = a² (1 - 2/5) = 3a²/5
Since it passes through the point (-3 , 1)

⇒ a² = 9 + 5/3 = 32.3 ⇒ b² = 32/5
So the required equation is 

For a particular class total number of different tickets from first intermediate station = 5

Similarly, number of different tickets from second intermediate station = 4

Similarly, for three, two and one intermediate stations.

So total number of different tickets

= 5 + 4 + 3 + 2 + 1 = 15

And there are a same number of tickets for another class

⇒⇒ Total number of different tickets = 2 × 15 = 30.

Therefore, number of different sets of tickets they may have = ³⁰C₁₀.

We have,

Now

(1 + α + α²)(1 + β + β²)

Given 

For g(x) to be differentiable at x = c, f'(c) must be 0. Else, it is non-differentiable.

We have,

Applying componendo and dividendo, we get

⇒ tan²B = tanAtanC

tan A, tan B & tan C are in G.P.

If z = r e^(iθ) = r (cosθ + i sinθ), then

i z = i r (cosθ + i sinθ)
= −r sinθ + i r cosθ

Thus,

e^(iz) = e^{(-r sinθ + i r cosθ)}
= e^{(-r sinθ)} e^{(i r cosθ)}

Taking the modulus:

|e^(iz)| = |e^{(-r sinθ)} e^{(i r cosθ)}|
= |e^{(-r sinθ)}| [cos(r cosθ) + i sin(r cosθ)]
= e^{(-r sinθ)} [cos²(r cosθ) + sin²(r cosθ)]^(1/2)
= e^{(-r sinθ)}.

In ΔABC,
tan 60° = tan ∠ACB = AB/BC

BC = 10 cm
In ΔCDE,
tan 30° = tan ∠ECD =
_{CD =}
BD = BC + CD = 10 cm + 15 cm = 25 cm

A man is facing South. He turns 135 degrees in the anticlockwise direction and then 180 degrees in the clockwise direction.

According to the question, the man turns in the anticlockwise direction, which means he is turning towards the northeast.
He turns 135°, which is  90° + 45.
On turning 90°90°, he would face east and on further turning 45°, he would face the exact centre line between north- east.
And Finally, he turns 180° in the clockwise direction, he would face the exact centre line in the South-west direction.
So, he is facing in the South-west direction at the final position.
Hence, this is the correct answer.

Let the ten's digit be x and units digit be y.
Then, (10x + y) – (10y + x) = 63 ⇔ 9 (x – y) = 63 ⇔ x – y =7|
We can only find the difference of x and y, not about number.
Thus, none of the numbers can be determined.