SRMJEE Mock Test - 3 (Engineering) - JEE MCQ

The magnitude of the induced current can be increased by rapidly increasing or decreasing the number of magnetic field lines passing through a closed coil.
The magnitude of the induced current can be increased by:

1. Taking the conductor in the form of a coil of many turns of insulated wire.
2. Increasing the strength of the magnetic field used.
3. Increasing the rate of change of magnetic flux associated with the coil.

The first minimum occurs at the angle θ\thetaθ where:
asin⁡θ = λ
where:

• a is the width of the slit,
• λ is the wavelength of the light.

At this first minimum, the phase difference between the light waves coming from the two edges of the slit is π\piπ, which corresponds to the condition for destructive interference.
Conclusion: At the first minimum, the phase difference between the rays coming from the two edges of the slit is: C: π.

As the electric potential of both the spheres is same,

If σ be the surface charge density,

Using the concept of escape velocity,

v_e = 11.2 x 10³ m/s

The effective resistance between A and B (combination of four resistors) is given by:

The two resistances in the mixed combination are in series and their resultant resistance is then parallel.
So,

⇒ R' = R
∴ Total effective resistance of the network = R + R = 2R

As given,

VP² = k (constant)

By ideal gas equation, 

PV = μRT
⇒ P = (μRT) / V

Hence,

⇒T₂ = 9T

Apply Snell's law between medium A and B,
μ₁sini₁ = μ₂sini₂, where i₁ and i₂ are incidence and refracting angle respectively.

From the above diagram,

because  are unit vectors.
Hence,  μ₁a = μ₂α.

or 

Therefore, strain produced in the two wires will be in the ratio 1:2.

In Hoffmann degradation, an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide to give primary amines. The amine so formed contains one carbon less than that present in the amide.
Benzamide is an aromatic amide containing seven carbon atoms. Hence, the amine formed from benzamide is aromatic primary amine containing six carbon atoms (Aniline).

The product is aniline (C₆H₅NH₂​)

The plot of total vapour pressure as a function of mole fraction will be a straight line for an ideal solution.
Moreover, the total pressure will not be zero even when the mole fraction of 'X' is zero because of the presence of the vapours of 'Y'.
Hence, option (2) is correct.

The greater the valency, the more the coagulation of colloidal solution.
So, the correct order is: Al³⁺ > Ba²⁺ > Na⁺

Let the unit distance along the X-axis = 4 Å
Let the unit distance along the Y-axis = 3 Å
Let the unit distance along the Z-axis = 2 Å
Lattice parameters are (4, 3, 2).
Ratio by factoring out common factors: (4/2, 3/3, 2/4) = (2, 1, 1/2).
Multiplying by 2 to get whole numbers: (4, 2, 1).
Thus, the Miller indices are (4, 2, 1).

Rate = K [Conc]ᵒʳᵈᵉʳ

Taking the logarithm on both sides:

log(Rate) = logK + order × log[Conc]

Since the slope of the graph log(Rate) vs. log(Conc) represents the order of reaction, a greater slope indicates a higher reaction order.

Thus, the correct order of reaction is: c > a > b > d

Iron oxide is basic impurity which is removed by adding acidic flux silica.
FeO + SiO₂ → FeSiO₃ (slag)

Cupellation is a refining process in metallurgy where the ores or alloyed metals are treated under very high temperatures and have controlled operations to separate noble metals, like gold (Au) and silver (Ag) from base metals, like lead, copper, zinc, arsenic, antimony, or bismuth, present in the ore.

| + |² + | - |² = 2 (||² + ||²)
25 + | - |² = 2(9 + 16)
⇒ | - |² = 50 - 25 = √25
⇒ | - | = 5

Let E₁ be the event that a screw is drawn from box A, E₂ be the event that a screw is drawn from box B, and E₃ be the event that a screw is drawn from box C.
Then, P(E₁) = P(E₂) = P(E₃) = 1/3
Let D be the event that a defective screw is drawn.
Then, , and
Then, the probability that a defective screw came from box A is:

Let ABCDEF be a regular hexagon with centre O.
Then AB = BC = CD = DE = EF = FA

λ = 3

The range of cosx is [−1,1].
−1 ≤ cos3x ≤ 1 ⇒ −1 ≤ − cos3x ≤ 1
1 ≤ 2 −cos3x ≤ 3

and 

Since,   a₁a₂ = b₁b₂

⇒   α + β + γ = π − β < π

Adding above three, we have 

Again 

From (1) and (5)

∴ From (4), the expression

There are two circles in the figure.

Given:

Area of the inner circular lawn = 154 m²

⇒ πr² = 154
⇒ (22/7) × r² = 154
⇒ r² = (154 × 7) / 22
⇒ r² = 49
⇒ r = √49 = 7 m

Given: Width of the path = 7 m

Radius of the circular lawn including the path (R) =
Radius of the circular lawn (r) + Width of the path
⇒ 7 + 7 = 14 m

Area of the circular lawn including the path
= πR²
= (22/7) × 14²
= (22/7) × 196
= 616 m²

The passage focuses on public float in the context of securities (shares), stating: “The larger the public float, the less is the scope for price manipulation of shares” and “preventing undesirable transactions in securities.” Option A incorrectly refers to “commodities,” which is unrelated to the passage’s discussion of share prices. Options B, C, and D align with the passage’s points on preventing manipulation, dissuading private companies, and wealth redistribution, respectively. Correct option: A.

In the passage, “averse” describes promoters’ reluctance to share capital: “promoters ... are generally averse to giving a large share in the capital/benefits to the public.” ‘Hesitant’ (unwilling or reluctant) matches this meaning. ‘Agreeable’ is an antonym, ‘disputable’ means debatable, and ‘indebted’ means owing gratitude, none of which fit.

The passage uses “susceptible” to describe securities vulnerable to manipulation: “prices of the securities are not susceptible to manipulation.” ‘Susceptible’ means prone to being affected. ‘Resistant’ (not affected or harmed) is the opposite. ‘Prone’ is a synonym, ‘indifferent’ means unconcerned, and ‘uncaring’ implies lack of emotion, none of which are opposites.
Correct option: D.