A particle moving along xaxis has acceleration f, at time t, given by , where f_{0} and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle’s velocity (v_{x}) is
[2007]
The distance travelled by a particle starting from rest and moving with an acceleration 4/3ms^{2} , in the third second is:
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A particle shows distance  time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point: [2008]
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms^{–1} to 20 ms^{–1} while passing through a distance 135 m in t second. The value of t is: [2008]
A bus is moving with a speed of 10 ms^{–1} on a straight road. A scooterist wishes to overtake the bus in 100 s. If the bus is at a distance of 1 km from the scooterist, with what speed should the scooterist ch ase the bus? [2009]
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S_{1} and that covered in the first 20 seconds is S_{2}, then: [2009]
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s^{2})
A particle h as in itial velocity and has acceleration . It's speed after 10 s is:
A particle moves a distance x in time t according to equation x = (t + 5)^{1}. The acceleration of particle is proportional to [2010]
A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be:
A boy standing at the top of a tower of 20m height drops a stone. Assuming g = 10 ms^{–2}, the velocity with which it hits the ground is [2011]
A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]
A particle covers half of its total distance with speed v_{1} and the rest half distance with speed v_{2}. Its average speed during the complete journey is
The motion of a particle along a straight line is described by equation : [2012] x = 8 + 12t – t^{3} where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
A stone falls freely under gravity. It covers distances h_{1}, h_{2} and h_{3} in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h_{1}, h_{2} and h_{3} is [NEET 2013]
The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = . The displacement of the particle when its velocity is zero, will be [NEET Kar. 2013]
102 videos411 docs121 tests

Solved Examples: Uniform Motion  2 Video  46:41 min 
Quick Revision: Basic Concepts of Motion in a Straight Line Video  12:59 min 
Test: Motion in a Straight Line Test  30 ques 
Test: Motion in a Straight Line  2 Test  30 ques 
DPP for NEET: Daily Practice Problems, Ch 4: Motion in a Straight Line 2 Doc  4 pages 
102 videos411 docs121 tests

Solved Examples: Uniform Motion  2 Video  46:41 min 
Quick Revision: Basic Concepts of Motion in a Straight Line Video  12:59 min 
Test: Motion in a Straight Line Test  30 ques 
Test: Motion in a Straight Line  2 Test  30 ques 
DPP for NEET: Daily Practice Problems, Ch 4: Motion in a Straight Line 2 Doc  4 pages 