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Test: Preparation of Amines - NEET MCQ


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10 Questions MCQ Test Chemistry Class 12 - Test: Preparation of Amines

Test: Preparation of Amines for NEET 2024 is part of Chemistry Class 12 preparation. The Test: Preparation of Amines questions and answers have been prepared according to the NEET exam syllabus.The Test: Preparation of Amines MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Preparation of Amines below.
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Test: Preparation of Amines - Question 1

Propanamide on treatment with bromine in an aqueous solution of sodium hydroxide gives:

Detailed Solution for Test: Preparation of Amines - Question 1

Test: Preparation of Amines - Question 2

We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

Detailed Solution for Test: Preparation of Amines - Question 2

The correct answer is option C
CH3​CH2​CONH2​ (A)⟶ CH3​ − CH2 ​− NH2​ (B)⟶ ​CH3​ − CH2 ​− OH
In the above sequence A & B respectively are Br2​/KOH and HNO2
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine  (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
 

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Test: Preparation of Amines - Question 3

 Nitro compounds are reduced to amines. The catalyst that is preferred is:

Detailed Solution for Test: Preparation of Amines - Question 3

Fe + HCl is preferred due to the following reasons:
- Scrap iron i.e Fe is cheap and commercially easily available
- FeCl2 formed will get hydrolysed and release HCl, so, HCl which is required in the reaction will be produced by itself
- Hence only small amount of HCl is required to initiate the reaction.

Test: Preparation of Amines - Question 4

Aniline can be prepared by:

Detailed Solution for Test: Preparation of Amines - Question 4

Aniline is prepared commercially by the catalytic hydrogenation of nitrobenzene or by the action of ammonia on chlorobenzene. The reduction of nitrobenzene can also be carried out with iron borings in aqueous acid. A primary aromatic amine, aniline is a weak base and forms salts with mineral acids.

Test: Preparation of Amines - Question 5

 is a tertiary amine having IUPAC name as:

Test: Preparation of Amines - Question 6

Which reaction can be used for the direct conversion of amides into 10 amine ?

Detailed Solution for Test: Preparation of Amines - Question 6

The correct answer is option A
Reduction with LiAlH4

 

Test: Preparation of Amines - Question 7

 What is the end product in the following sequence of reactions ?
Acetamide  A   B

Detailed Solution for Test: Preparation of Amines - Question 7

The correct answer is Option D.

Test: Preparation of Amines - Question 8

 When Primary amide is treated with an aqueous solution of KOH and bromine, it gives a primary amine. The name of the reaction is:

Detailed Solution for Test: Preparation of Amines - Question 8

Hoffmann Bromamide reaction is Treatment of alkylamide with KOH and Bromine gas which converts it into alkylamine with one less carbon atom, this reaction is generally helpful in converting Carboxylic acids to amines with one less carbon atom . For reaction you may refer to internet but i can give you a hint .

 

Acetamide + KOH + Bromine gas —-> Alkylamine+ KBr + K2CO3 + H20 ( not sure about the products)

Test: Preparation of Amines - Question 9

 Gabriel phthalimide synthesis is used in the preparation of :

Detailed Solution for Test: Preparation of Amines - Question 9

The correct answer is option D
The chemical reaction used for transforming primary alkyl halides into primary amines is called Gabriel phthalimide synthesis. It uses potassium phthalimide. Therefore, Gabriel phthalimide synthesis is used in the preparation of 1o
amide.

Test: Preparation of Amines - Question 10

To convert methyl cyanide to ethylamine we use:

Detailed Solution for Test: Preparation of Amines - Question 10

LiAlH4 reduces all oxiginated functional groups to alcohol and all nitrogenated functional groups to amine thus cyanide is a nitrogenated functional group and to convert cyanide to amine LiAlH4 can be used.

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