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# Test: Power Electronics- 7

## 10 Questions MCQ Test RRB JE for Electrical Engineering | Test: Power Electronics- 7

Description
This mock test of Test: Power Electronics- 7 for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Power Electronics- 7 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Power Electronics- 7 quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Power Electronics- 7 exercise for a better result in the exam. You can find other Test: Power Electronics- 7 extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### A three phase bridge inverter is fed from a 500 V dc source. The inverter is operated in 180° conduction mode and it is supplying a purely resistive, star – connected load. The RMS value of the output (line) voltage is

Solution: = 0.816 × 500 = 408 V

QUESTION: 2

### In a three phase voltage source inverter operating in square wave mode, the output line voltage is free from

Solution:

The rms nth component of the line voltage is where Vdc is the input source voltage for n = 3, line voltage Third harmonic component would not appear in the output

*Answer can only contain numeric values
QUESTION: 3

### In single pulse modulation of PWM inverter, 3rd harmonic can be eliminated if pulse width is equal to______ (in degrees)

Solution:

Pulse width for eliminating

nth harmonic *Answer can only contain numeric values
QUESTION: 4

A three – phase bridge inverter delivers power to a resistive load from a 450 V dc source. for a star connected load if 10Ω per phase. What is the load power for 180° conduction mode ______________ (in kW)

Solution: QUESTION: 5

A 3 ϕ bridge inverter delivers power to a resistive load from a 400 V dc. For a star – connected load of 15 Ω per phase, determine load power and R.M.S value of thyristor current for 120° mode

Solution:  load power = 3I2or R = 3 × (10.87)2 × 15 = 5.317kW

*Answer can only contain numeric values
QUESTION: 6

A 3 phase MOSFET inverter is connected between a balanced star connected resistive load with RL = 10 Ω and a 250 V dc supply. The inverter frequency is set at 33 Hz, and the switches have 120° conduction periods. Calculate the load power _______ (in kW)

Solution: = 3.13 kW

*Answer can only contain numeric values
QUESTION: 7

for a single pulse – width modulation of a single phase inverter, The distortion factor for pulse width of π/2 is ___________

Solution:

given, 2d = π/2

single pulse modulation output for pulse width 2d = π/2 is shown below. from Fourier series, fundamental output voltage is from output voltage wave form QUESTION: 8

For a load of R = 10 Ω and L = 0.03 H, Find the RMS value of the fundamental component of inverter output current in case inverter of part Quasi-square output with 120° pulse width. The source voltage is 230 V and frequency 50 Hz

Solution:

Concept:

The output voltage is controlled by varying the pulse-width 2d. This shape of the output voltage is called Quasi-square wave. Fourier series of this wave from is Fundamental component of output voltage Calculation:
Load impedance at Fundamental Frequency is For Quasi-square wave or single-pulse modulated wave where pulse width, 2d = 120° or d = 60° ∴ R.M.S value of fundamental current *Answer can only contain numeric values
QUESTION: 9

The inverter is operated at 50 Hz. In 180° square wave mode. Find the peak to peak inductor i0 in the circuit shown in figure. Solution: at, t = 0, i0 = -ip and t = t1, i0 = ip *Answer can only contain numeric values
QUESTION: 10

For the symmetrical two pulse modulation with pulse width 36°. Find the percentage of 3rd harmonic in the output voltage is_______

Solution:

Concept:

In multiphase pulse modulation, several equidistant pulses per half cycle are used.

Fourier series of multiple pulse modulation is N = pulse per half cycle

Calculation: 