MCQ: Clock and Calendar - 2 - SSC CGL MCQ

# MCQ: Clock and Calendar - 2 - SSC CGL MCQ

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## 15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Clock and Calendar - 2

MCQ: Clock and Calendar - 2 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Clock and Calendar - 2 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Clock and Calendar - 2 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Clock and Calendar - 2 below.
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MCQ: Clock and Calendar - 2 - Question 1

### Directions: Complete the sentences given below sing the correct alternative. A month can have _____ days.

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 1

A month can have 28, 29, 30 or 31 days.
So, all the options are true.
Hence, the correct answer is "More than one of the above".

MCQ: Clock and Calendar - 2 - Question 2

### Directions: Complete the sentences given below sing the correct alternative. If today is Wednesday, day after tomorrow will be

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 2

Key Points

• The concept of days succeeding each other is based on a seven-day cycle in which each day follows the next in a fixed order.
• If today is Wednesday, tomorrow would be Thursday.
• Thus, the day after tomorrow would be Friday, a day not listed among the options.
• Therefore, given the context and the understanding of the sequence of days in a week, 'none of the above' is the correct answer.

Therefore, the correct answer is Option 4, 'None of the above'.

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MCQ: Clock and Calendar - 2 - Question 3

### Which of the following is a leap year?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 3

1076 → 1076 is completely divisible by 4.
1675 → 1675 is not completely divisible by 4.
1354 → 1354 is not completely divisible by 4.
1998 → 1998 is not completely divisible by 4.

Therefore, 1076 is a leap year.
Hence, ‘1076’ is the correct answer.

MCQ: Clock and Calendar - 2 - Question 4

You are given a question and two statements I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

On which date of month was Harish born in February 2000?

Statements:
I. Harish was born on an even date of the month.
II. Harish’s birth date was a prime number.

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 4

Statements:
I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28
II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
But we know that 2 is the smallest even prime number.
According to both statements we can say that on 2nd February 2000 Harish was born.
Hence, Option (1) is correct.

MCQ: Clock and Calendar - 2 - Question 5

The dates 3rd April, 2005; 6th August, 2010 and 5th December, 2013 when written in Date-Month-Year Form have a unique mathematical property. The Indian Independence Day of which year among the following has the same property?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 5

Logic: If we see carefully we can find that these dates have property yy= dd+ mm2
3rd April, 2005 - 03/04/05
(05)2 = (03)2 + (04)2
6th August, 2010 - 06/08/10
(10)2 = (06)+ (08)2
5th December, 2013 - 05/12/13
(13)2 = (05)2 + (12)2
Similarly,
Independence day 2017 - 15 August 2017 - 15/08/17
By above logic: (17)2 = (15)2 + (08)2
No other option satisfy the above condition. So, Indian Independence Day of 2017 has the same property.
Hence, option 1) is the correct answer.

MCQ: Clock and Calendar - 2 - Question 6

15th October 1984 will fall on which of the following days?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 6

The logic followed here is:
1600 years contain 0 odd day, 300 years contain 1 odd day. Also, 83 years contain 20 leap years and 63 ordinary years and therefore (40+0) odd days i.e., 5 odd days.
∴ 1983 years contain (0 + 1 + 5) i.e., 6 odd days.
Number of days from Jan. 1984 to 15th Oct. 1984
= (31 + 29 + 31 + 30 + 31 + 30 +31+ 31 + 30 + 15)
= 289 days = 2 odd days
∴ Total number of odd days = 6 + 2 = 1 odd days.
So, 15th Oct, 1984 was Monday.
Hence, the correct answer is "Monday".

MCQ: Clock and Calendar - 2 - Question 7

What is the measure of the angle formed by the hands of the clock at 2'o clock?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 7

Calculation:
The angle between two digits = 30°
⇒ At 2'o clock one hand will be on 12 and second hand will be on 2 So, 30° × 2 = 60°
∴ At 2'o clock angles between hands will be 60°.
The correct option is 3 i.e. 60°

MCQ: Clock and Calendar - 2 - Question 8

How much angle will rotate from Evening 9 PM to Morning 6 AM ?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 8

From 9 pm to 12 am angle rotated = 90°
⇒ Angle rotated from 12 am to 6 am = 180°
⇒ Therefore , total angle rotated = (90 + 180)°
⇒ 270°
Hence Total angle rotated = 270°

MCQ: Clock and Calendar - 2 - Question 9

Directions: Complete the sentences given below sing the correct alternative.

If today is the 12th of December, the next month will be

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 9

Given:
Today is 12th of December.
So, this month is December and according to the calendar, next month after December is January.
Hence, the correct answer is "January".

MCQ: Clock and Calendar - 2 - Question 10

Which of the following was a leap year?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 10

Concept:
A leap year is a year that has 366 days instead of the usual 365 days. It occurs every four years, except for years that are divisible by 100 but not by 400.

1998 is not a leap year because it is not divisible by 4.
2002 is not a leap year because it is divisible by 100 but not by 400.
2014 is not a leap year because it is not divisible by 4.
2004 is a leap year because it is divisible by 4.
Therefore, 2004 is the only leap year.

MCQ: Clock and Calendar - 2 - Question 11

If 3 March 2020 was Tuesday, then what was the day of the week on 3 February 2019?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 11

The logic followed here is:
3 march 2020 was Tuesday
First of all we will check is 2020 is a leap year 2020/4
so, 2020 is a leap year therefore February has 29 days.
Now, we will check days between 4 Feb 2020 - 3 march 2020
i.e. 26 + 3 odd days
= 29/7( because week has 7 days )
remainder is 1 by dividing it
so we will -1 in Tuesday i.e. Monday
therefore 3 Feb 2020 is Monday
but, we have to find 3 Feb 2019
then we will do -1 in Monday
so, on 3 February 2019 is Sunday
Hence, Sunday is the correct answer.

MCQ: Clock and Calendar - 2 - Question 12

January 1, 2018 was Monday. Then January 1, 2019 falls on the day:

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 12

Given -
January 1, 2018 was Monday

Concept used -
in a normal year number of days = 365
number of odd days = (365/7) = + 1

1 January 2018 = Monday
1 January 2019 = Monday + 1 = Tuesday
∴ January 1, 2019 = Tuesday

MCQ: Clock and Calendar - 2 - Question 13

Directions: Question below is followed by two statements, I and II. Read the statements given and mark the answer.

Is it Friday today?
I. February 15 of this year was a Wednesday.
II. Today is March 12.

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 13

Statement I: February 15 of this year was a Wednesday: We cannot get what is today’s date.
Statement II: Today is March 12: We can’t tell which day today is, it can be any day.
Taking both the statements together: We cannot tell whether it is Friday or not because we don’t know if the year is leap year or not.
Hence both the statements were not enough to give the answer.

MCQ: Clock and Calendar - 2 - Question 14

If on January 20, 2030 is Sunday, then which day will be on January 4, 2028?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 14

Given:
⇒ January 20, 2030 = Sunday
⇒ January 22, 2030 = Tuesday
As, for each month dates 1, 8, 15, 22 and 29 comes on same week day.
⇒ January 1, 2030 = Tuesday
⇒ January 4, 2030 = Friday
⇒ January 4, 2029 = Thursday
As after every leap year, dates will move two days further and 2028 is a leap year. Leap year is a year which is divisible by 4 and having 366 days.
∴ January 4, 2028 = Tuesday

MCQ: Clock and Calendar - 2 - Question 15

It is observed that January 1, 2023 is a Sunday. In which year again the January 1st will on a Sunday?

Detailed Solution for MCQ: Clock and Calendar - 2 - Question 15

An ordinary year has 1 odd day and a leap year has 2 odd days.
January 1, 2023 – Sunday
January 1, 2024 – Monday
January 1, 2025 – Wednesday
January 1, 2026 – Thursday
January 1, 2027 – Friday
January 1, 2028 – Saturday
January 1, 2029 - Monday
January 1, 2030 - Tuesday
January 1, 2031 - Wednesday
January 1, 2032 - Thursday
January 1, 2033 - Saturday
January 1, 2034 - Sunday
Clearly, in year 2034 again the January 1st will on a Sunday.
Hence, ‘2034’ is the correct answer.

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## Quantitative Aptitude for SSC CGL

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