MCQ: Unitary Method - 3 - SSC CGL MCQ

# MCQ: Unitary Method - 3 - SSC CGL MCQ

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## 15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Unitary Method - 3

MCQ: Unitary Method - 3 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Unitary Method - 3 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Unitary Method - 3 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Unitary Method - 3 below.
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MCQ: Unitary Method - 3 - Question 1

### If in a hostel 45 days, food is available food is available for 50 students, for how many days will this food be sufficient for 75 students ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 1

For 50 students, food is sufficient for 45 days
∴ For 1 student, food is sufficient for 45 x 50 days
and for 75 students, food is sufficient for (45 x 50)/75 days. i,e., for 30 days.

MCQ: Unitary Method - 3 - Question 2

### 12 men can do a piece of work in 24 days. How many days are needed to complete the work, if 8 men are engaged in the same work ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 2

Let the required number of days be N.
Let men, More days (indirect proportion)
8 : 12 : : 24 : N
∴ N = (12 x 24)/8 = 36 days

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MCQ: Unitary Method - 3 - Question 3

### Shantanu completes 5/8 of a job in 20 days. At this rate, how many more days will he take to finish the job ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 3

Let the required number of days be N.
Remaining work = 1 - 5/8 = 3/8
Less work, Less days (Direct proportion)
5/8 : 3/8 : : 20 : N
⇒ N = (3/8) x 20 x 8/5
∴ N = 12 days

MCQ: Unitary Method - 3 - Question 4

If price of m articles is ₹ n, then what is the price of 5 articles ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 4

∵ Price of m articles = ₹ n
∴ Price of 1 article = ₹ n/m
∴ Price of 5 articles = ₹ 5n/m

MCQ: Unitary Method - 3 - Question 5

Maganlal, a worker, makes an article in every 2/3h. If he works for 71/2h, then how many articles will he make ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 5

∵ In 2/3h, 1 article is made.
∴ In 1h, 3/2 article are made.
∴ In 71/2 = 15/2h, 3/2 x 15/2 = 45/4 article are made.
∴ Required articles = 45/4 = 112/4

MCQ: Unitary Method - 3 - Question 6

20 men can build 56 m long wall in 6 days. What length of a similar wall can be built by 70 men in 3 days ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 6

Let the required length be L m.
More men, More length (Direct proportion)
Less days, Less length (Direct proportion)
Men 20 : 70
Days 6 : 3
∴ (20 x 6 x L) = (70 x 3 x 56)
∴ L = (70 x 3 x 56) / (20 x 6) = 98 m

MCQ: Unitary Method - 3 - Question 7

If 30 men working 9 h per day can reap a field in 16 days, in how many days, will 36 men reap the field working 8 h per day ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 7

Here M1 = 30, D1 = 16,
T1 = 9, M2 = 36 and T2 = 8
By formula, M1D1T1 = M2D2T2
30 x 16 x 9 = 36 x D2 x 8
∴ D2 = (30 x 16 x 9)/(36 x 8) = 15 days

MCQ: Unitary Method - 3 - Question 8

If 12 persons working 16 h per day earn ₹ 33600 per week, then how much will 18 persons earn working 12 h per day ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 8

M1 = 12 H1 = 16, W1 = 33600
M2 = 18, H2 = 12, W2 = ?
By formula, M1H1/W1 = M2H2/W2
(12 x 16)/33600 = (18 x 12)/W2
⇒ W2 = (33600 x 18)/16
⇒ W2 = 2100 x 8
∴ W2 = 37800

MCQ: Unitary Method - 3 - Question 9

22 men can complete a job in 16 days. In how many days, will 32 men complete that job ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 9

∵ 22 men do the work in 16 days.
∴ 1 man will do the work in 16 x 22 days.
∴ 32 men will do the job in = (16 x 22)/32 days
∴ Required number of days = (16 x 22)/32 = 11 days

MCQ: Unitary Method - 3 - Question 10

A garrison of 1000 men had provisions for 48 days. However, a reinforcement of 600 men arrived. How long will now food last for ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 10

∵ For 1000 men, provision lasts for 48 days.
∴ For 1 men, provision lasts for (48 x 1000) days.
∴ For (1000 + 600) men, provision will last for (48 x 1000)/1600 days.
∴ Required number of days = (48 x 1000)/1600 = 3 x 10 = 30

MCQ: Unitary Method - 3 - Question 11

If 10 spiders can catch 10 files in 10 min, then how many flies can 200 spiders catch in 200 min ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 11

Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)
∴ 10 x 10 x N = 200 x 200 x 10
∴ N = (200 x 200 x 10)/(10 x 10) = 4000 flies

MCQ: Unitary Method - 3 - Question 12

If in a hostel, food is available for 45 days for 50 students. For how many soldiers for 75 students ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 12

∵ For 50 students, food is sufficient for 45 days.
∴ For 1 students, food is sufficient for 45 x 50 days.
∴ For 75 students, food is sufficient for (45 x 50)/75 days i.e., for 30 days .

MCQ: Unitary Method - 3 - Question 13

3 men can do a piece of work in 18 days. 6 boys can also do the same work in 18 days. In how many days, 4 men and 4 boys together will finish the work ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 13

3 men ≡ 6 boys
⇒ 1 man ≡ 2 boys
∴ 4 men + 4 boys ≡ 4 men + 2 men = 6 men
∵ 3 men can do a work in 18 days.
∴ 1 man can do a work in 18 x 3 days.
∴ Required number of days = (18 x 3)/6 = 9 days

MCQ: Unitary Method - 3 - Question 14

2000 sodiers in a fort had enough food for 20 days. But some soldiers were transferred to another fort and the food lasted for 25 days. How many soldiers were transferred ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 14

Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
⇒ 2000 - N = (2000 x 20)/25
⇒ 2000 - N = 1600
∴ N = 2000 - 1600 = 400

MCQ: Unitary Method - 3 - Question 15

A garrison is provided with ration for 72 soldiers to last for 54 days. Find how long would the same amount of food last for 90 soldiers, if the individual ration is reduced by 10 % ?

Detailed Solution for MCQ: Unitary Method - 3 - Question 15

Let the required number of days be N.
More men, Less days (indirect proportions)
Soldiers 90 : 72
Ratio 9 : 10
N = (72 x 54 x 10)/(90 x 9) = 48 days

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## Quantitative Aptitude for SSC CGL

314 videos|170 docs|185 tests