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This mock test of Electric Field And Potential MCQ Level - 2 for IIT JAM helps you for every IIT JAM entrance exam.
This contains 10 Multiple Choice Questions for IIT JAM Electric Field And Potential MCQ Level - 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Two point charges placed at a distance * r* in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant

Solution:

The correct answer is:

QUESTION: 2

Two isolated, charged conducting spheres of radii * a* and

Solution:

The correct answer is: *a*/*b*

QUESTION: 3

Twenty seven drops of water of the same size are equally and similarly charged. They are then united to from a bigger drop. By what factor will the electrical potential changes.

Solution:

The correct answer is: 9 times

QUESTION: 4

Electric potential at any point x, y, z in the space is given V=4x^{2}−3x. Find electric field

Solution:

V = 4x^{2} - 3x

E_{x} = ∂V/∂x = 8x - 3

E_{y} = ∂V/∂y = 0

E_{z} = ∂V/∂z = 0

So, E = -(8x - 3)

QUESTION: 5

An electric dipole consisting of two opposite charge of 2 × 10^{–6}*C* each separated by a distance of 0.03*m* is placed in an electric field of 2 × 10^{5}*NC*^{–1}. The maximum torque on the dipole will be

Solution:

*q* = 2 × 10^{–6} *C*

2*l* = 0.03 *m
E = 2 × 10*

τ = ρE sin θ Where

For maximum torque, sin*θ =* 1 and τ = ρE * *

Max. Torque = *q* × 2*l* × *E* = 2 × 10^{–6} × 0.03 × 2 × 10^{5} *N**m
=* 12 × 10

The correct answer is: 12 × 10

QUESTION: 6

Two identical point charge are placed at a separation of * r*.

Solution:

The correct answer is:

QUESTION: 7

A spherical charged conductor has surface density σ of charge. The electric field on its surface is * E*. If the radius of the sphere is doubled keeping the surface density of charged unchanged then the electric field on the surface of the new sphere will be

Solution:

E = KQ/R^{2}

= Kσ(4πR^{2})/R^{2}

= σ/ε_{0}

R ----> 2R and σ = unchanged

E' = Kσ[4π(2R)^{2}]/(2R)^{2}

=> σ/ε_{0} = E

QUESTION: 8

A charge * q* is divided into two parts

Solution:

*F* = *k*(*q*_{1})(*q* – *q*_{1})

*F* will be maximum. If *q*_{1}(*q* – *q*_{1}) is maximum

∴ * q*_{1 }=_{ }(*q* – *q*_{1})

⇒ *q* = 2*q*_{1}

⇒ *q*/*q*_{1} = 2:1

The correct answer is: 2 : 1

QUESTION: 9

Two concentric thin metallic sphere of radii ** R_{1}** and

Solution:

The observation point is at a distance* r* from the centre of the inner sphere of radius

The correct answer is:

QUESTION: 10

Two equal negative charge (**– q** each) are fixed at point

Solution:

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