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Integral Calculus -3 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Integral Calculus -3

Integral Calculus -3 for Mathematics 2024 is part of Topic-wise Tests & Solved Examples for Mathematics preparation. The Integral Calculus -3 questions and answers have been prepared according to the Mathematics exam syllabus.The Integral Calculus -3 MCQs are made for Mathematics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Integral Calculus -3 below.
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Integral Calculus -3 - Question 1

The integral  equals:

Detailed Solution for Integral Calculus -3 - Question 1

We have


So, 
implies

Integral Calculus -3 - Question 2

 is equal to:

Detailed Solution for Integral Calculus -3 - Question 2


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Integral Calculus -3 - Question 3

Detailed Solution for Integral Calculus -3 - Question 3


Integral Calculus -3 - Question 4

 is equal to:

Detailed Solution for Integral Calculus -3 - Question 4

Integral Calculus -3 - Question 5

 is equal to:

Detailed Solution for Integral Calculus -3 - Question 5



Integral Calculus -3 - Question 6

The value of definite integral   is equal to:

Detailed Solution for Integral Calculus -3 - Question 6

Integral Calculus -3 - Question 7

Let sin2 ucos2 udu, then:

Detailed Solution for Integral Calculus -3 - Question 7

Integral Calculus -3 - Question 8

 is equal to:

Detailed Solution for Integral Calculus -3 - Question 8


Integral Calculus -3 - Question 9

 is equal to:

Detailed Solution for Integral Calculus -3 - Question 9

Integral Calculus -3 - Question 10

Detailed Solution for Integral Calculus -3 - Question 10

Integral Calculus -3 - Question 11

The moment of inertia of a hollow sphere about a diameter is:

Detailed Solution for Integral Calculus -3 - Question 11

Moment of Inertia of a Hollow Sphere about the Diameter

Suppose the mass of a hollow sphere is M, ρ is the density, inner radius R2 and outer radius R1

 ∴ M = 4/3π(R1− R23

 Moment of inertia of a hollow sphere (I) = Moment of inertia of a solid sphere of radius R1 - Moment of inertia of a solid sphere of radius R2 

Integral Calculus -3 - Question 12

The area bounded by the curve  from x = 0 to x = 1, the x -axis and the ordinate at x = 1 is:

Detailed Solution for Integral Calculus -3 - Question 12


Integral Calculus -3 - Question 13

The area of the closed curve x = a cos t, y = b sint is given by:

Detailed Solution for Integral Calculus -3 - Question 13


Integral Calculus -3 - Question 14

The area bounded by the curves y = ex, y = e-x and the line x = 1, is: 

Detailed Solution for Integral Calculus -3 - Question 14

Given curves are
y = ex
y = e-
From eqn (i) and (ii), we get

Integral Calculus -3 - Question 15

The intrinsic equation of the curve p = r sin α is given by: 

Detailed Solution for Integral Calculus -3 - Question 15

Given curve is p = r sin α   ....(i)
Hence  



or, 

Integral Calculus -3 - Question 16

The area of surface of the solid generated by the revolution of the line segment y = 2x from x = 0 to x = 2, about x-axis is equal to:

Detailed Solution for Integral Calculus -3 - Question 16

Required surface area is

Integral Calculus -3 - Question 17

The perimeter of the curve r = 2 cos θ is:

Detailed Solution for Integral Calculus -3 - Question 17

The curve is r = 2 cos θ
Changing it into Cartesian coordinate, we get 
x2 + y2 = 2x
or, (x - l)2 + y2 = 1,
which is a circle with centre (1,0) and radius 1.
Hence
Perimeter = 2πr = 2π · 1 = 2π

Integral Calculus -3 - Question 18

The length of the arc of the parabola x2 = 4ay from the vertex to the extremity of the latus rectum is given by:

Detailed Solution for Integral Calculus -3 - Question 18

Given curve is x2 = 4ay
Differentiating, w.r. to y, we get

implies 
implies 
Hence Length of the arc between vertex and extremity of latus rectum

Integral Calculus -3 - Question 19

The area bounded by the curve y = x3, x -axis and the line x = 1 and x = 4 is given by:

Detailed Solution for Integral Calculus -3 - Question 19

Given curve is y = x3

The required area = Area ABCD =

Integral Calculus -3 - Question 20

The length of the arc of the curve y = log sec x between x = 0 and x = π/6 is equal to:

Detailed Solution for Integral Calculus -3 - Question 20

Given curve is y = log sec x
So, 
Hence Required length is given by


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