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Olympiad Test: Coding-Decoding - 4 - Class 6 MCQ


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10 Questions MCQ Test Science Olympiad Class 6 - Olympiad Test: Coding-Decoding - 4

Olympiad Test: Coding-Decoding - 4 for Class 6 2024 is part of Science Olympiad Class 6 preparation. The Olympiad Test: Coding-Decoding - 4 questions and answers have been prepared according to the Class 6 exam syllabus.The Olympiad Test: Coding-Decoding - 4 MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Coding-Decoding - 4 below.
Solutions of Olympiad Test: Coding-Decoding - 4 questions in English are available as part of our Science Olympiad Class 6 for Class 6 & Olympiad Test: Coding-Decoding - 4 solutions in Hindi for Science Olympiad Class 6 course. Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free. Attempt Olympiad Test: Coding-Decoding - 4 | 10 questions in 15 minutes | Mock test for Class 6 preparation | Free important questions MCQ to study Science Olympiad Class 6 for Class 6 Exam | Download free PDF with solutions
Olympiad Test: Coding-Decoding - 4 - Question 1
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In a certain code language 'Cow' is called 'Goat', 'Goat' is called 'Lion', 'Lion' is called 'Dog', then which of the following animals is the king of the forest?

Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 1

Following the given codes, 'Lion' is termed as 'Dog'. Thus, 'Dog' is the king of the forest.

Olympiad Test: Coding-Decoding - 4 - Question 2
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If code for 'H' = '8', then code for 'A' = ...

Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 2
If 'H' corresponds to '8', the pattern seems to be using the positions of the letters in the alphabet in reverse. 'A' holds the position '1' in the alphabet, so the code for 'A' is '1'.
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Olympiad Test: Coding-Decoding - 4 - Question 3
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Find the code for 'FLMT' if the code for 'DGPT' is 'EFQS'.

Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 3

If 'DGPT' translates to 'EFQS', it appears that there is a shifting pattern. For example, 'D' becomes 'E', 'G' becomes 'H', 'P' becomes 'Q', and 'T' becomes 'S'. Following this pattern, 'F' becomes 'G', 'L' becomes 'K', 'M' becomes 'N', and 'T' becomes 'S'. Therefore, the code for 'FLMT' is 'KGNS'.

Olympiad Test: Coding-Decoding - 4 - Question 4
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If 'E' is coded as 'H', then how will 'D' be coded?
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 4

If 'E' is coded as 'H', this suggests that each letter is shifted 3 positions forward in the alphabet (E to H is three letters forward: E → F → G → H).

Using the same pattern:

  • 'D' (shifted 3 positions forward) becomes 'G' (D → E → F → G).

So, 'D' will be coded as G.

Olympiad Test: Coding-Decoding - 4 - Question 5
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In a certain code language '3' is coded as 'Z', '4' is coded as 'Y', '5' is coded as 'X', '6' is coded as 'W', and '7' is coded as 'V', then find the code for '5734'.
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 5

The given pattern suggests a reverse coding with numbers and letters. As per the provided codes, '5' corresponds to 'X', '7' corresponds to 'V', '3' corresponds to 'Z', and '4' corresponds to 'Y'. Hence, '5734' translates to 'XVZY'.

Olympiad Test: Coding-Decoding - 4 - Question 6
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In a certain code language 'beautiful girl' is written as 'su ko' and 'beautiful name' is written as 'po su', then code for 'girl' is...
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 6
Analyzing the given codes, 'beautiful' corresponds to 'su'. 'Name' in both sentences corresponds to 'po'. So, 'girl' is represented as 'ko'.
Olympiad Test: Coding-Decoding - 4 - Question 7
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If code for 'KING' = 'GNIK', then code for 'PINK' = '?'.
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 7
The pattern seems to involve reversing the letters. Applying the same pattern to 'PINK', it will be coded as 'NIKP'.
Olympiad Test: Coding-Decoding - 4 - Question 8
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If the code for 'JH' is '18', then how will 'CH' be coded?
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 8
Considering the code for 'JH' as '18', it's possible that the code is generated by concatenating the positions of the letters in the alphabet. 'J' is the 10th letter, and 'H' is the 8th letter. So, '10' + '8' = '18'. Applying the same logic to 'CH' where 'C' is the 3rd letter and 'H' is the 8th letter, the code would be '3' + '8' = '38'.
Olympiad Test: Coding-Decoding - 4 - Question 9
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If code for 'XY' = '1', then the code for 'UW' = '?'.
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 9
Considering 'XY' corresponds to '1', it might be possible that the code is derived from the sum of the positions of the letters. 'X' is the 24th letter, and 'Y' is the 25th letter. So, '24' + '25' = '49'. Applying the same logic to 'UW', 'U' is the 21st letter, and 'W' is the 23rd letter. Therefore, '21' + '23' = '44'.
Olympiad Test: Coding-Decoding - 4 - Question 10
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Find the code of 'CDEF' if the code for 'LMNO' is 'MOOQ'.
Detailed Solution for Olympiad Test: Coding-Decoding - 4 - Question 10
Analyzing the given codes, it appears that there is a shifting pattern. 'L' becomes 'M', 'M' becomes 'O', 'N' becomes 'O', and 'O' becomes 'Q'. Following the same pattern, 'C' becomes 'D', 'D' becomes 'F', 'E' becomes 'F', and 'F' becomes 'H'. Hence, the code for 'CDEF' is 'DFFH'.
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