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Olympiad Test: Achieves Section-2 - Class 8 MCQ


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10 Questions MCQ Test - Olympiad Test: Achieves Section-2

Olympiad Test: Achieves Section-2 for Class 8 2025 is part of Class 8 preparation. The Olympiad Test: Achieves Section-2 questions and answers have been prepared according to the Class 8 exam syllabus.The Olympiad Test: Achieves Section-2 MCQs are made for Class 8 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Achieves Section-2 below.
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Olympiad Test: Achieves Section-2 - Question 1

What is the value of 

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 1

Olympiad Test: Achieves Section-2 - Question 2

9x2 + 25 - 30x is the square of

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 2

9x2 + 25 - 30x
= (3x)2 + (5)2 - 2 (3x) (5)
= (3x - 5)2

Olympiad Test: Achieves Section-2 - Question 3

One of the factor of x2 + 17x + 60 is

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 3

 x2 + 17x + 60
=x2 +5x +12x + 60
=x(x+5) +12(x+5)
=(x+5) + (x+12)

Olympiad Test: Achieves Section-2 - Question 4

The perimeter of a rectangle is 54 cm. If its width is 2 cm more than one-fourth of its length. What is its length?

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 4

Let the length be x.

Olympiad Test: Achieves Section-2 - Question 5

One of the letters from the word SOCIOLOGY is chosen at random. What is the probability that this letter is O? 

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 5

Total number of letters = 9
Number of letter ‘O’ = 3
Required probability 

Olympiad Test: Achieves Section-2 - Question 6

What is the value of 

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Olympiad Test: Achieves Section-2 - Question 7

The product of two numbers is 1575 and their quotient is 9/7. What is the difference of the numbers?

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 7

Let the numbers be x and y. 

Olympiad Test: Achieves Section-2 - Question 8

The diagonal of a square is  What is its perimeter?

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 8


Olympiad Test: Achieves Section-2 - Question 9

What is the simplified value of  

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 9

Given expression:

Step 1: Simplify inside the square brackets

4/9 + (−8/13)
= 4/9 − 8/13

To calculate this, first find the LCM of 9 and 13:

  • LCM of 9 and 13 = 117

Convert both fractions to have denominator 117:

  • 4/9 = (4 × 13) / 117 = 52 / 117

  • 8/13 = (8 × 9) / 117 = 72 / 117

Now subtract:

  • 52/117 - 72/117 = -20 / 117

Step 2: Multiply this result with (169/2)

Now compute:

(-20/117) × (169/2)

Multiply numerators and denominators:

  • Numerator: -20 × 169 = -3380

  • Denominator: 117 × 2 = 234

So the result is -3380 / 234

Now simplify this:

  • GCD of 3380 and 234 is 26

Divide both by 26:

  • Numerator: 3380 ÷ 26 = 130

  • Denominator: 234 ÷ 26 = 9

So the result is -130 / 9

Step 3: Add 1/3 to this

Now compute:

1/3 + (-130/9)
= 1/3 - 130/9

Convert 1/3 to denominator 9:

  • 1/3 = 3/9

Now subtract:

  • 3/9 - 130/9 = -127 / 9

Final Answer:

-127 / 9

Olympiad Test: Achieves Section-2 - Question 10

A well with internal diameter 8m is dug 7m deep. The earth taken out of it is spread at around to a width of 2 m to form an embankment. The height of embankment will be :

Detailed Solution for Olympiad Test: Achieves Section-2 - Question 10

Volume of earth dug out

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