Test: Coupled Circuits - 1 | 10 Questions MCQ Test Network Theory (Electric Circuits) Electrical Engineering (EE)

QUESTION: 1

In the circuit of given figure = 4 sin2 A, and i₂ = 0.

Q. v₁ = ?

A.
-16 cos 2 t V
B.
16 cos 2 t V
C.
4 cos2 t V
D.
-4 cos2 t V

Solution:

QUESTION: 2

In the circuit of given figure i₁ = 4 sin2 A, and i₂ = 0.

Q. v₂ =?

A.
2 cos2 t V
B.
-2 cos2 t V
C.
8 cos2 t V
D.
-8 cos2 t V

Solution:

QUESTION: 3

Consider the circuit shown in given figure:

If i₁ = 0 and i₂ = 2 sin4 A, the voltage v₁ is:

A.
24 cos 4 t V
B.
-24 cos 4 t V
C.
1.5cos 4 t V
D.
-1.5cos 4 t V

Solution:

QUESTION: 4

Consider the circuit shown in given figure:

If i₁ = e^-2tV and i₂ = 0, the voltage v₂ is:

A.
-6e^-2t V
B.
1.5 e^-2tV
C.
6e^-2t V
D.
-1.5 e^-2tV

Solution:

QUESTION: 5

Consider the circuit shown in given figure.

If current i₁ = 3 cos4 A and i₂ = 0, then voltage v₁ and v₂ are:

A.
v₁ = -24 sin 4t V, v₂= -24sin 4t V
B.
v₁ = 24 sin 4t V, v₂= -36sin 4t V
C.
v₁ = -1.5 sin 4t V, v₂= sin 4t V
D.
v₁ = -15 sin 4t V, v₂= -sin 4t V

Solution:

QUESTION: 6

Consider the circuit shown in the given figure.

If current i₁ = 0 and i₂ = 4sin3tA, then voltage v₁ and v₂ are:

A.
v₁ = 24 cos 3t V, v₂= 36cos 3t V
B.
v₁ = 24 cos 3t V, v₂= -36cos 3t V
C.
v₁ = -24 cos 3t V, v₂= - 36cos 3t V
D.
v₁ = -24 cos 3t V, v₂= 36cos 3t V

Solution:

= 3di₂/dt
= 36cos 3t V

QUESTION: 7

In the circuit shown in the given figure i₁= 3 cos3t A and i₂= 4 sin3 A.

Q. v₁ = ?

A.
6(2cos t - 3 sint) V
B.
6(2cos t + 3 sint) V
C.
-6(2cos t + 3 sint) V
D.
6( -2cos t + 3 sint) V

Solution:

=-18 sin t + 12 cost = 6 (2 cos t - 3 sin t) V

QUESTION: 8

In the circuit shown in the given figure i₁= 3 cos3t A and i₂= 4 sin3 A.

Q. v₂ =?

A.
3(8cos 3t - 3 sin3t) V
B.
6(2cos t + 3 sint) V
C.
3(8cos 3t + 3 sin 3t) V
D.
6(2cos t - 3 sint) V

Solution:

= 24 cos 3t - 9 sin 3t = 3 ( 8 cos 3t - 3 sin 3t) V

QUESTION: 9

In the circuit shown in the given figure i₁= 5 sin3 A and i₂= 3 cos3t A

Q. v₁ =?

A.
9(5cos 3t + 3 sin 3t) V
B.
9(5cos 3t - 3 sin 3t) V
C.
9(4cos 3t + 5 sin 3t) V
D.
9(5cos 3t + sin 3t) V

Solution:

= 45 cos 3t + 27 sin 3t = 9 (5cos 3t + 3sin 3t) V

QUESTION: 10

In the circuit shown in the given figure i₁= 5 sin3 A and i₂= 3 cos3t A.

Q. v₂ = ?

A.
9( -4sin 3t + 5 cos 3t) V
B.
9(4sin 3t - 5 cos 3t) V
C.
9( -4sin 3t - 5 cos 3t) V
D.
9(4sin 3t + 5 cos 3t) V

Solution:

= 36 sin 3t + 45 cos 3t = 9 (4sin 3t + 5 cos 3t) V

Test: Coupled Circuits - 1

10 Questions MCQ Test Network Theory (Electric Circuits) | Test: Coupled Circuits - 1

In the circuit of given figure = 4 sin2 A, and i₂ = 0.

Q. v₁ = ?

In the circuit of given figure i₁ = 4 sin2 A, and i₂ = 0.

Q. v₂ =?

Consider the circuit shown in given figure:

If i₁ = 0 and i₂ = 2 sin4 A, the voltage v₁ is:

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