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Test: Sinusoidal Steady‐State Analysis - 2 - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Network Theory (Electric Circuits) - Test: Sinusoidal Steady‐State Analysis - 2

Test: Sinusoidal Steady‐State Analysis - 2 for Electrical Engineering (EE) 2024 is part of Network Theory (Electric Circuits) preparation. The Test: Sinusoidal Steady‐State Analysis - 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Sinusoidal Steady‐State Analysis - 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Sinusoidal Steady‐State Analysis - 2 below.
Solutions of Test: Sinusoidal Steady‐State Analysis - 2 questions in English are available as part of our Network Theory (Electric Circuits) for Electrical Engineering (EE) & Test: Sinusoidal Steady‐State Analysis - 2 solutions in Hindi for Network Theory (Electric Circuits) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Sinusoidal Steady‐State Analysis - 2 | 10 questions in 30 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Network Theory (Electric Circuits) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Sinusoidal Steady‐State Analysis - 2 - Question 1

The circuit is as shown in fig. P1.7.17-18

Q.i2(t) = ?

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Test: Sinusoidal Steady‐State Analysis - 2 - Question 2

I x = ?

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 2


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Test: Sinusoidal Steady‐State Analysis - 2 - Question 3

Vx = ?

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Let Vo be the voltage across current source

Test: Sinusoidal Steady‐State Analysis - 2 - Question 4

Determine the complex power for the given values in question.
Q. P = 269 W, Q = 150 VAR (capacitive)

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 4

S = P - jQ = 269 - j150 VA

Test: Sinusoidal Steady‐State Analysis - 2 - Question 5

Determine the complex power for the given values in question.
Q. Q = 2000 VAR, pf = 0.9 (leading)

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Test: Sinusoidal Steady‐State Analysis - 2 - Question 6

Determine the complex power for the given values in question.
Q. S = 60 VA, Q = 45 VAR (inductive)

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Test: Sinusoidal Steady‐State Analysis - 2 - Question 7

Determine the complex power for the given values in question.
Q. Vrms = 220 V, P = 1 kW, |Z| = 40 Ω (inductive)

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Test: Sinusoidal Steady‐State Analysis - 2 - Question 8

Determine the complex power for the given values in question.
Q. Vrms = 21∠ 200V, Vrms = 21∠200V, I rms = 8.5∠500A

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 8


= 61+ j167.7VA

Test: Sinusoidal Steady‐State Analysis - 2 - Question 9

Determine the complex power for the given values in question.
Q. Vrms = 120∠ 300V, Z = 40 + j 80Ω

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Test: Sinusoidal Steady‐State Analysis - 2 - Question 10

Vo = ?

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