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Test: Super Node Analysis - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Network Theory (Electric Circuits) - Test: Super Node Analysis

Test: Super Node Analysis for Electrical Engineering (EE) 2024 is part of Network Theory (Electric Circuits) preparation. The Test: Super Node Analysis questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Super Node Analysis MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Super Node Analysis below.
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Test: Super Node Analysis - Question 1

Find the value of the current (A) in the equivalent current source of the voltage source shown below.
Find the value of the current (A) in the equivalent current source of the voltage source

Detailed Solution for Test: Super Node Analysis - Question 1

The value of the current (A) in the equivalent current source of the voltage source the short circuit current at the terminals A and B is I = 60/30 = 2A.

Test: Super Node Analysis - Question 2

Find the power absorbed by 5Ω resistor in the following figure.
Find the voltage (V) at node 3 in the figure

Detailed Solution for Test: Super Node Analysis - Question 2

The current through 5Ω resistor = V3/5 = 18.11/5 = 3.62A. The power absorbed by 5Ω resistor = (3.62)2) × 5 = 65.52W.

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Test: Super Node Analysis - Question 3

Consider the figure shown below. Find the voltage (V) at node 2.
The voltage (V) at node 1 in the given circuit is 19

Detailed Solution for Test: Super Node Analysis - Question 3

The equation at node 1 is 10 = V1/3 + (V- V2)/2
According to super Node analysis, (V- V2)/2 = V2/1 + (V- 10)/5 + V3/2V- V= 20.
On solving, we get, V= 11.5V.

Test: Super Node Analysis - Question 4

Consider the figure shown below. Find the power (W) delivered by the source 6A.
Find the voltage (V) at node 1 in the figure

Detailed Solution for Test: Super Node Analysis - Question 4

The term power is defined as the product of voltage and current and the power delivered by the source (6A) = Vx 6 = 3.72 × 6 = 22.32W.

Test: Super Node Analysis - Question 5

Consider the figure shown below. Find the voltage (V) at node 2.
Find the voltage (V) at node 1 in the figure

Detailed Solution for Test: Super Node Analysis - Question 5

Applying Super Node Analysis, the combined equation of node 1 and node 2 is (V- V3)/3 + 3 + (V- V3)/1 - 6 + V2/5 = 0.
At node 3, (V- V1)/3 + (V- V2)/1 + V3/2 = 0.
Also V- V2=10.
On solving above equations, we get V2 = 3.72V ≈ 4V.

Test: Super Node Analysis - Question 6

Find the value of the voltage (V) in the equivalent voltage source of the current source shown below.
Find the value of the voltage (V) in the equivalent voltage source of the current source

Detailed Solution for Test: Super Node Analysis - Question 6

The value of the voltage (V) in the equivalent voltage source of the current source the voltage across the terminals A and B is (6)(5) = 30V.

Test: Super Node Analysis - Question 7

Find the voltage (V) at node 3 in the figure shown below.
Find the voltage (V) at node 3 in the figure

Detailed Solution for Test: Super Node Analysis - Question 7

At node 1, (V- 40 - V3)/4 + (V- V2)/6 - 3 - 5 = 0.
Applying Super Node Analysis at node 2 and 3, (V- V1)/6 + 5 + V2/3 + V3/5 + (V+ 40 - V1)/4 = 0.
Also, V- V= 20.
On solving above equations, V3 = 18.11V ≈ 18V.

Test: Super Node Analysis - Question 8

Find the voltage (V) at node 1 in the circuit shown below.
The voltage (V) at node 1 in the given circuit is 19

Detailed Solution for Test: Super Node Analysis - Question 8

The equation at node 1 is 10 = V1/3+(V- V2)/2.
According to super Node analysis, (V- V2)/2 = V2/1 + (V- 10)/5 + V3/2V- V= 20.
On solving, we get, V= 19V.

Test: Super Node Analysis - Question 9

Consider the figure shown below. Find the voltage (V) at node 3.
Find the voltage (V) at node 1 in the figure

Detailed Solution for Test: Super Node Analysis - Question 9

Applying Super Node Analysis, the combined equation of node 1 and node 2 is (V- V3)/3 + 3 + (V- V3)/1 - 6 + V2/5 = 0.
At node 3, (V- V1)/3 + (V- V2)/1 + V3/2 = 0.
Also V- V= 10.
On solving above equations, we get V3 = 4.5V.

Test: Super Node Analysis - Question 10

Consider the figure shown below. Find the voltage (V) at node 1.
Find the voltage (V) at node 1 in the figure

Detailed Solution for Test: Super Node Analysis - Question 10

Applying Super Node Analysis, the combined equation of node 1 and node 2 is (V- V3)/3 + 3 + (V- V3)/1 - 6 + V2/5 = 0.
At node 3, (V- V1)/3 + (V- V2)/1 + V3/2 = 0.
Also V- V= 10.
On solving above equations, we get V1 = 13.72V ≈ 14V.

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