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Test: Shear Force & Bending Moment - 3 - Mechanical Engineering MCQ


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10 Questions MCQ Test Strength of Materials (SOM) - Test: Shear Force & Bending Moment - 3

Test: Shear Force & Bending Moment - 3 for Mechanical Engineering 2024 is part of Strength of Materials (SOM) preparation. The Test: Shear Force & Bending Moment - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Shear Force & Bending Moment - 3 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Shear Force & Bending Moment - 3 below.
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Test: Shear Force & Bending Moment - 3 - Question 1

In figure the maximum bending moment at the fixed end of the cantilever caused by the UDL is M.

The bending moment at a section //5 from the free end is

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 1

Test: Shear Force & Bending Moment - 3 - Question 2

The shear force along the beam shown in the figure is

Test: Shear Force & Bending Moment - 3 - Question 3

The correct shear force diagram for the beam shown in the figure is

Test: Shear Force & Bending Moment - 3 - Question 4

A simply supported beam of span l is loaded (as shown) with a udl of intensity w1 per unit length at A and w2 per unit length at B the shear force at the support B is given by

Test: Shear Force & Bending Moment - 3 - Question 5

The beam shown in the given figure has a design value of bending moment of

Test: Shear Force & Bending Moment - 3 - Question 6

A cantilever beam is subjected to moments as shown in the given figure. The BM diagram for the beam will be

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 6


The bending moment due to 50 kNm moment would be hogging. Similarly the bending moment due to 30 kNm would be sagging. Therefore the bending moment diagram is,

Test: Shear Force & Bending Moment - 3 - Question 7

The fixed end moment MA of the beam shown in the given figure is

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 7


∑FV = 0
⇒ RA + RC = 20
MB = 0 [from right]
∴ RC x 4 - 20 x 6 = 0
⇒ Rc x 4 = 20 x 6 

MB = 0 [from left]
RA x 4 - MA = 0
⇒ MA = RA x 4 = -10 x 4
= - 40 kNm
The fixed end moment at A will be in clockwise direction, opposite to the direction shown in the figure.
∴ MA = -40 kNm

Test: Shear Force & Bending Moment - 3 - Question 8

A simply supported beam with equal overhang ori both sides is loaded as shown in the figure. If the bending moment at mid-span is zero, then the percentage overhang on each side will be

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 8

Let the overhang percentage in 100p.
So overhang = pl
The shear force diagram will be,

For B.M. at mid point to be zero, area of shear force diagram under (1) should be equal to that of (2),
1/2w(pl)2 = 1/2w[(0.5 - P)l]2
or p2 = (0.5 - p)2 = 0.25 - p + p2
∴ p = 0.25 or 25%

Test: Shear Force & Bending Moment - 3 - Question 9

A propped cantilever beam shown in the figure given is having interna! hinge at its mid-span. Which one of the following is the shape of bending moment diagram for the given loading?

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 9

Due to hinge at C the part CB of beam be have s as simply supported beam. Thus reaction at B will be in upward direction and equals half of the load in span BC.
Span CA be haves as a cantilever beam. There fore B.M.D. will be sagging in BC and hogging in AC and it will be parabolic.
For a cantiiever B.M.D. will be as shown below.

Combining all the arguments answer will be (d) which is given with BM plotted on tension side.

Test: Shear Force & Bending Moment - 3 - Question 10

In the case of l-section, the web resists mainly

Detailed Solution for Test: Shear Force & Bending Moment - 3 - Question 10

In the case of (-section, nearly 80-90% shear force, is resisted by web and only 10-20% is resisted by flanges, whereas in bending. 80-90% moment is resisted by flanges and only 10-20% by the web.

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