UPSC Exam  >  UPSC Tests  >  Famous Books for UPSC Exam (Summary & Tests)  >  Test: Gravitation - UPSC MCQ

Test: Gravitation - UPSC MCQ


Test Description

10 Questions MCQ Test Famous Books for UPSC Exam (Summary & Tests) - Test: Gravitation

Test: Gravitation for UPSC 2024 is part of Famous Books for UPSC Exam (Summary & Tests) preparation. The Test: Gravitation questions and answers have been prepared according to the UPSC exam syllabus.The Test: Gravitation MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Gravitation below.
Solutions of Test: Gravitation questions in English are available as part of our Famous Books for UPSC Exam (Summary & Tests) for UPSC & Test: Gravitation solutions in Hindi for Famous Books for UPSC Exam (Summary & Tests) course. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free. Attempt Test: Gravitation | 10 questions in 15 minutes | Mock test for UPSC preparation | Free important questions MCQ to study Famous Books for UPSC Exam (Summary & Tests) for UPSC Exam | Download free PDF with solutions
Test: Gravitation - Question 1

If an apple is taken to mountain top then its weight is

Detailed Solution for Test: Gravitation - Question 1

The reasoning behind this is that the force of gravity is weaker at higher altitudes compared to sea level. As you move higher up a mountain, you are farther away from the center of the Earth, which results in a slightly reduced gravitational pull. Since weight is the force exerted on an object due to gravity, the weight of the apple would decrease.

Therefore, if option A) decreased is considered correct, then the weight of an apple taken to the top of a mountain would decrease.

Test: Gravitation - Question 2

2 lead spheres having mass of 1000 kg each are placed with their centres 1 m apart. gravitational force with which they attract to each other will be

Detailed Solution for Test: Gravitation - Question 2

The gravitational force between two objects can be calculated using Newton's law of universal gravitation:

F = (G * m1 * m2) / r2

Where: F is the gravitational force between the objects, G is the gravitational constant (approximately 6.673 × 10^-11 Nm2/kg2), m2 and m2 are the masses of the two objects, and r is the distance between their centers.

In this case, we have two lead spheres with masses of 1000 kg each, and their centers are 1 meter apart. Plugging these values into the formula, we get:

F = (6.673 × 10-11 * 1000 * 1000) / 12

F = 6.673 × 10-11 * 106

F = 6.673 × 10-5

So, the gravitational force with which the lead spheres attract each other is approximately 6.673 × 10-5 Newtons.

Therefore, the correct answer is option D) 6.673 × 10-5.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Gravitation - Question 3

 The Force of Gravitation is inversely related to

Detailed Solution for Test: Gravitation - Question 3

According to Newton's law of universal gravitation, the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers. Mathematically, it can be represented as:

F = G * (m1 * m2) / r2

Where:

  • F represents the force of gravity between the two masses,
  • G is the gravitational constant,
  • m1 and m2 are the magnitudes of the masses of the objects, and
  • r is the distance between the centers of the objects.

So, as the distance between the masses increases, the gravitational force between them decreases, following the inverse square relationship.

Test: Gravitation - Question 4

What is the value of Universal Gravitational Constant (G) in C.G.S unit?

Detailed Solution for Test: Gravitation - Question 4

The value of the Universal Gravitational Constant (G) in CGS (Centimeter-Gram-Second) units is approximately 6.67 * 10(-8) cm3 g(-1) s(-2).

So, the correct option from the provided choices is C) 6.67 * 10(-8) cgs unit.

Test: Gravitation - Question 5

What is the gravitational force between two objects?

Detailed Solution for Test: Gravitation - Question 5

According to Newton's law of universal gravitation, every object with mass exerts an attractive force on every other object with mass. This gravitational force is always attractive, regardless of the distance between the objects. It decreases with distance, becoming weaker as the distance between the objects increases, but it is still attractive at all distances.

Test: Gravitation - Question 6

The distance between two bodies becomes 6 times more than the usual distance. The the F becomes

Detailed Solution for Test: Gravitation - Question 6

The gravitational force between two bodies is inversely proportional to the square of the distance between them. If the distance between two bodies becomes 6 times more than the usual distance, it means the new distance is 6 times the original distance.

The gravitational force is inversely proportional to the square of the distance, so if the distance becomes 6 times more, the gravitational force will be (1/6)2 = 1/36 times the original force.

Therefore, the correct option is D) 1/36 times.

Test: Gravitation - Question 7

In which region of earth the weight of a body is slightly greater?

Detailed Solution for Test: Gravitation - Question 7

The weight of a body is slightly greater at the poles, so the correct option is A) At Polar region.

This is because the Earth is not a perfect sphere but is slightly flattened at the poles and bulges at the equator due to its rotation. As a result, the distance from the center of the Earth to a point at the poles is slightly shorter compared to the distance at the equator. Since weight is directly proportional to the distance from the center of the Earth, objects weigh slightly more at the poles than at the equator.

Test: Gravitation - Question 8

Value of gravitation on moon's surface is 1.6 ms-1. weight of a 100 kg body on moon's surface will be

Detailed Solution for Test: Gravitation - Question 8

The weight of a body can be calculated using the formula:

Weight = Mass × Acceleration due to gravity

On the Moon's surface, the acceleration due to gravity is approximately 1.6 m/s2, as given in the question. So, let's calculate the weight of a 100 kg body on the Moon's surface:

Weight = 100 kg × 1.6 m/s2 = 160 N

Therefore, the correct option is D) 160 N.

Test: Gravitation - Question 9

As we go farther away from Earth, gravitational force becomes

Detailed Solution for Test: Gravitation - Question 9

As we go farther away from Earth, the gravitational force becomes weaker.

According to Newton's law of universal gravitation, the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

As the distance between two objects increases, the gravitational force decreases. Therefore, the correct option is C) weaker.

Test: Gravitation - Question 10

Every body in universe attracts every other body with force which is directly proportional to product of their masses and inversly proportional to square of distance between their centres, this statement is known as

Detailed Solution for Test: Gravitation - Question 10

The statement "Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers" is known as the law of gravitation.

Therefore, the correct option is B) law of gravitation. This law is derived from Newton's law of universal gravitation, which describes the gravitational interaction between two objects.

728 videos|1212 docs|628 tests
Information about Test: Gravitation Page
In this test you can find the Exam questions for Test: Gravitation solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Gravitation, EduRev gives you an ample number of Online tests for practice

Top Courses for UPSC

Download as PDF

Top Courses for UPSC