Practice Test: Averages - 2 - UPSC MCQ

# Practice Test: Averages - 2 - UPSC MCQ

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## 10 Questions MCQ Test CSAT Preparation - Practice Test: Averages - 2

Practice Test: Averages - 2 for UPSC 2024 is part of CSAT Preparation preparation. The Practice Test: Averages - 2 questions and answers have been prepared according to the UPSC exam syllabus.The Practice Test: Averages - 2 MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Averages - 2 below.
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Practice Test: Averages - 2 - Question 1

### A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?

Detailed Solution for Practice Test: Averages - 2 - Question 1

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs. [ (6500 x 6) - 34009 ]

= Rs. (39000 - 34009)

= Rs. 4991.

Practice Test: Averages - 2 - Question 2

### The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?

Detailed Solution for Practice Test: Averages - 2 - Question 2

Let A, B, C represent their respective weights. Then, we have:

A + B + C = (45 x 3) = 135 .... (i)

A + B = (40 x 2) = 80 .... (ii)

B + C = (43 x 2) = 86 ....(iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)

Subtracting (i) from (iv), we get : B = 31.

B's weight = 31 kg.

Practice Test: Averages - 2 - Question 3

### If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?

Detailed Solution for Practice Test: Averages - 2 - Question 3

Practice Test: Averages - 2 - Question 4

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?

Detailed Solution for Practice Test: Averages - 2 - Question 4

Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (20 * 2 + 5 * 2) years = 50 years.
Husband's present age = (90 - 50) years
= 40 years

Practice Test: Averages - 2 - Question 5

The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?

Detailed Solution for Practice Test: Averages - 2 - Question 5

The average weight of 8 persons increases by 2.5 kg
Total weight of 8 persons increased = 8 × 2.5 kg = 20 kg.
New person comes in place of one of them weighing 65 kg.
Hence the increase of weight of 8 persons together is because of new person replacing the person having 65 kg weight. Accordingly
Weight of new person = 65 + 20 kg = 85 kg
Thus the person replacing the 65 kg person should have 85 kg weight, which causes increase of weight of the group together by 2.5 kg .

Practice Test: Averages - 2 - Question 6

There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?

Detailed Solution for Practice Test: Averages - 2 - Question 6

Weighted Average=[(Weight of Group 1) * (Average of Group 1) + (Weight of Group 2) * (Average of Group 2)]/Total Weight

In this case, Group 1 is Division A and Group 2 is Division B.

Given information:

• Weight of Division A (Weight of Group 1Weight of Group 1) = 36 students
• Average weight of Division A (Average of Group 1Average of Group 1) = 40 kg
• Weight of Division B (Weight of Group 2Weight of Group 2) = 44 students
• Average weight of Division B (Average of Group 2Average of Group 2) = 35 kg

Now, plug these values into the formula:

Weighted Average=[(36 students×40 kg)+(44 students×35 kg)]/36+44

Weighted Average=37.25kg

So, the average weight of the whole class is 37.25 kg.

Practice Test: Averages - 2 - Question 7

A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?

Detailed Solution for Practice Test: Averages - 2 - Question 7

Practice Test: Averages - 2 - Question 8

A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?

Detailed Solution for Practice Test: Averages - 2 - Question 8

As, Mean = Total Sum of Observations / No. of Observations

Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.

or  137 + x = 144

⇒ x = 144 - 137 = 7.

Practice Test: Averages - 2 - Question 9

Arun obtained 76, 65, 82, 67 and 85 marks (out in 100) in English, Mathematics, Chemistry, Biology and Physics. What is his average mark?

Detailed Solution for Practice Test: Averages - 2 - Question 9

Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 =  75.

Practice Test: Averages - 2 - Question 10

Three classes X, Y and Z take an algebra test.
The average score in class X is 83.
The average score in class Y is 76.
The average score in class Z is 85.
The average score of all students in classes X and Y together is 79.
The average score of all students in classes Y and Z together is 81.
What is the average for all the three classes?

Detailed Solution for Practice Test: Averages - 2 - Question 10

Let x , y and z be no. of students in class X, Y ,Z respectively.
From 1st condition we have
83*x+76*y = 79*x+79*y which give 4x = 3y.
Next we have 76*y + 85*z = 81(y+z) which give 4z = 5y .
Now overall average of all the classes can be given as

Substitute the relations in above equation we get,
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