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A man sells a TV set for Rs. 33000 and makes a profit of 10%. He sells another TV at a loss of 20%. If on the whole, he neither gains nor loses, find the selling price of the second TV set.
Here, the selling price = 33000
profit made = 10%
therefore original price =»x+10% of x = 33000
x = 33000  10% of x
x = 33000 1/10 of x
10x = 3300001x
11x = 330000
x = 330000/
= 30000
therefore profit = 3300030000 = 3000
here, he sells another tv for a loss of 20%
which is selling price  20%of original price
= 33000  20% of 30000
= 30000 ( 20 × 30000)
100
= 33000  6000 = 27000
So option C is correct
By selling a cap for Rs. 29.75, a man gains 6.25%. What will be the CP of the cap?
SP = 106.25% of the CP.
Thus, CP = 29.75/1.0625 = Rs. 28
So option D is correct
E sells a car priced at Rs. 1,80,000. He gives a discount of 5% on the first Rs. 1,00,000 and 12.5% on the remaining Rs. 80,000. His competitor R sells a car on the same market priced at Rs. 1,80,000. If he wants to be competitive what percent discount should R offer on the marked price.
The total discount offered by E = 5% on 1,00,000 + 12.5% on 80,000 = 5,000 + 10,000 = 15,000.
If R wants to be as competitive, he should also offer a discount of Rs. 15,000 on 1,80,000.
Discount percentage = (15000/180000) x 100= 8.33% discount.
So option B is correct
A feeding bottle is sold for Rs. 150. Sales tax accounts for onefifth of this and profit onethird of the remainder. Find the cost price of the feeding bottle.
Sales tax = 150 / 5 = 30
∵ SP contains Rs. 30 component of sales tax.
Of the remainder (150 – 30 = 120) 1/3rd is the profit.
Thus, the profit = 120 / 3 = 40
Hence, Cost price = 120 – 40 = 80
So option B is correct
E owns a house worth Rs. 20,000. He sells it to R at a profit of 25%. After some time, R sells it back to E at 25% loss. Find E’s loss or gain per cent.
CP = 20000
Profit = 25/100 of 20000 = 5000
SP = Profit + CP = 25000
New transaction
CP= 25000
Loss = 25% of 25000 = 6250
SP = CP  Loss = 18750
P's gain = 1250
TOTAL gain = 6250
Total gain % = 6250/20000 × 100 = 625/20 = 31.25%
So option C is correct
A machine costs Rs. 1025. If it is sold at a loss of 25%, what will be its cost price as a percentage of its selling price?
A loss of 25% means a cost price of 100 corresponding to a selling price of 75. CP as a percentage of the SP would then be 133.33%
Alternatively,
Cost price = 1025
Loss% = 25%
SP = 1025  (1025 * 25/100) = 768.75
⇒ 768.75 * (x/100) = 1025
⇒ 768.75x = 102500
⇒ x = 102500/768.75 = 133.33%
So option D is correct
A man sells an article at 10% above its cost price. If he had bought it at 15% less than what he paid for it and sold it for Rs. 33 less, he would have gained 10%. Find the cost price of the article.
S.P. at 10% profit = Rs.(110y/100) = 11y/10
New C.P. of article = 85y/100 = 17y/20
S.P. = Rs.(17y/20 * 110/100)
New S.P. of article = Rs. 187/200
According to Question,
11y/10  187y/200 = 33
33y/200 = 33
y = 200
So option B is correct
A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the cus tomer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper.
While buying, he buys 1100 grams instead of 1000 grams (due to his cheating).
Suppose he bought 1100 grams for Rs. 1000
While selling, he sells only 900 grams when he takes the money for 1 kg.
According to the problems
He sells at 8% profit (20% markup and 10% discount).
Hence his selling price is Rs. 1080 for 900 grams.
To calculate profit percentage, we either equate the goods or the money.
In this case, let us equate the money as follows:
Buying:1100 grams for Rs. 1000
Hence 1188 grams for Rs. 1080
Selling: 900 grams for Rs. 1080
Hence, profit% = 288/900 = 32%
(using goods left by goods sold formula)
So option D is correct
E sold at table to R at a profit of 25%.R sold the same table to S for Rs. 90 thereby making a profit of 20%. Find the price at which E bought the table from Z if it is known that Z gained 25% in the transaction.
R sold the table at 20% profit at Rs. 90. Thus R's cost price x 1.2 = 90
R’s Cost price = Rs. 75
We also know that E sold it to R at 25% profit.
Thus, E’s Cost price x 1.25 = 75
⇒ E’s cost price = 60
So option D is correct
125 toffees cost Rs. 75. Find the cost of one million toffees if there is a discount of 40% on the selling price for this quantity.
The cost per toffee = 75 / 125 = Rs. 0.6 = 60 paise.
Cost of 1 million toffees = 600000.
∵ There is a discount of 40% offered on this quantity.
Thus, the total cost for 1 million toffees is 60% of 600000 = 360000
So option C is correct
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