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Chemical Bonding - 2 - JEE MCQ


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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Chemical Bonding - 2

Chemical Bonding - 2 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Chemical Bonding - 2 questions and answers have been prepared according to the JEE exam syllabus.The Chemical Bonding - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chemical Bonding - 2 below.
Solutions of Chemical Bonding - 2 questions in English are available as part of our Chemistry for JEE Main & Advanced for JEE & Chemical Bonding - 2 solutions in Hindi for Chemistry for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Chemical Bonding - 2 | 30 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
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TeF5¯, XeF2 , I3+ , XeF4 , PCl3 

Which of the following shape does not describe to any of the above species ?
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In a 1:1 complex of BF₃ and NH₃, the coordination geometry and hybridization around the N and B atoms are as follows:

  • Nitrogen (N) in NH₃: The nitrogen atom in NH₃ is sp³ hybridized in a tetrahedral arrangement, with one lone pair of electrons and three bonding pairs with hydrogen atoms.

  • Boron (B) in BF₃: The boron atom in BF₃ is sp² hybridized with a trigonal planar geometry. However, when it forms a complex with NH₃, it accepts a lone pair of electrons from nitrogen, forming a dative bond. This results in boron adopting a tetrahedral geometry and undergoing sp³ hybridization in the complex.

So, in the BF₃-NH₃ complex:

  • Nitrogen (N): Tetrahedral geometry, sp³ hybridization.
  • Boron (B): Tetrahedral geometry, sp³ hybridization.
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