Test: Hydrogen spectrum - JEE MCQ
15 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Hydrogen spectrum
The wavelength of Hα line of Balmer series is X Å. What is the wavelength of Hβ line of Balmer series.
A dye absorbs a photon of wavelength 
and reemits the same energy into two photons of wavelength 
and 
respectively. The wavelength 
is related with 
and 
as:
and reemits the same energy into two photons of wavelength and respectively. The wavelength is related with and as:
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The energy of an electromagnetic radiation is 19.875 × 10−13 ergs. What is its wave number in cm−1 ? (h = 6.625 × 10−27 erg sec, c = 3 × 1010 cmsec−1)
What is the maximum wavelength line in the Lyman series of 
ion?
Find the value of wave number 
in terms of Rydberg's constant, when transition of electron takes place between two levels of 
ion whose sum is 4 and difference is 2 .
The electron energy in hydrogen atom is given by E = (−21.7 × 10−12)/n2 ergs. By calculating the energy required to remove an electron completely from the n = 2 orbit, find out the longest wavelength (in cm) of light that can be used to cause this transition?
ergs 
The 
of 
line of Balmer series is 
. What is the 
of 
line of Balmer series?
lines of Balmer series 
line of Balmer series 
...(1)
...(2)
A near UV photon of 
is absorbed by a gas and then re-emitted as two photons. One photon is red with wavelength 
. Hence, wavelength of the second photon is
What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series?
(h = Planck's constant, c = velocity of light, R = Rydberg's constant).
The figure indicates the energy level diagram of an atom and the origin of six spectral lines in emission (e.g. line no. 5 arises from the transition from level B to A). The following spectral lines will also occur in the absorption spectrum
The frequency of light emitted for the transition n = 4 to n = 2 of the He+ is equal to the transition in H atom corresponding to which of the following ?
In hydrogen atomic spectrum, a series limit is found at 
. Then it belong to
If the wavelength of the first line in Balmer series is 656 nm, then the wavelength of its second line and limiting line respectively are
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