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Hence, Option (a) and option (b) are true for the Dimensional equation. Thus, It is not correct for the given questions.
Hence, option C is the correct answer as it is an incorrect statement.
Find the option with 3 significant figures.
The significant figures in any number are all certain digits plus one doubtful digit. Certain rules are followed which are as under:
1) All one zero digits in a number are significant.
2) The zeroes between two nonzero digits are always significant.
3) The zeros written to the left of the first nonzero digit in a number are nonsignificant. They simply indicate the position of the decimal point.
4) All zeros placed to the right of a decimal point in a number are significant.
Since, 0.0268 has three significant figures whereas 2.608 cm, 26.08 mm and 2.068 cm have four significant figures, A is the correct answer.
Which of the following physical quantity has different dimension than others?
Dimension of work and energy are the same i.e. [ML²T⁻²].
Power = Energy/Time,
Energy = Power × Time (in terms of hour instead of second),
Energy = Watt × Hour,
= [ML²T⁻³] [T],
= [ML²T⁻²].
But, Momentum(p) = Mass × Velocity,
p = [M] [LT⁻¹],
p = [MLT⁻¹].
Hence the Dimension of work, energy and watthour is the same i.e. [ML²T⁻²] but the dimension of momentum is different ([MLT⁻¹]).
If radian correction is not considered in specific heat measurement. The measured value of specific heat will be ______.
S_{P}(Heat) = mcΔt
If radian correction is not considered then Δt will increase.
So, S_{P} will also increase.
Hence option 'A' is correct.
Two gold pieces, each of mass 0.035g, are placed in a box of mass 2.3 g. The total mass of the box with gold pieces is:
Mass of Gold pieces = 2 × 0.035 = 0.070 g
Mass of box = 2.3 g
Total mass of box with gold pieces = 0.070 + 2.3 = 2.370 g
Since the answer should be in 2 significant digits, therefore, on rounding off, we get 2.4 g.
Thus, the required answer will be 2.4 g.
What is the number of significant figures in 0.310×10^{3} ?
The number of significant figures is 3 because 10^{3} is a decimal multiplier.
So. after calculating this number, we will get 0310 which is also a 3 significant figure number.
The number of significant figures in the distance of one light year , 9.4605 × 10^{15} m is:
As the power of 10 is irrelevant in the determination of significant figures hence, the numbers of significant figures are 5 i.e. 9,4,6,0,5
The numbers of significant figures in 1.84 x10^{27} kg are:
As the power of 10 is irrelevant to the determination of significant figures hence, the numbers of significant figures are 3 (1, 8 and 4).
The multiplication of 10.610 with 0.210 upto correct number of significant figure is:
The multiplication of the numbers:
10.610 × 0.210 = 2.2281
Since, the numbers 10.610 and 0.210 have 5 and 3 significant digits, respectively. So, the final result must also have 3 significant digits.
The final answer is 2.23 after rounding off 2.2281.
Numbers of significant figures in the volume of a cube of side 6.103 m are:
Therefore, the correct answer is 4.
Magnitude of force F experienced by a certain object moving with speed v is given by F = Kv^{3}, where K is a constant. The dimensions of K are:
The order of magnitude of a number expressed in scientific notation is ______.
The numbers of significant figures in 9.1 x10^{31} kg are:
As the power of 10 is irrelevant to the determination of significant figures hence, the numbers of significant figures are 2 (9 and 1).
Among all the given quantities, work, force and area can be expressed as products of some quantities which have nonzero dimensions, but the angle is defined as the ratio of arc length to the radius which is dimensionless because both arc length and radius have the same dimensions which when taken a ratio of, will get cancelled out.
Additional Information: A dimensionless quantity is the one for which no physical dimension is assigned. It is also known as a bare, pure, or scalar quantity or also as a quantity of dimension one.
Three students measured length of a needle with meter rod and recorded as :
(i) 0.2145m
(ii) 0.21m
(iii) 0.214m
Which one is correct record?
the correct answer should be C because a meter rod can only read upto two decimal points
After a decimal point, the number is less than 5 which is to be neglected, then retained number:
In rounding off numbers, the last figure kept should be unchanged if the first figure dropped is less than 5.
Example: If only one decimal is to be kept, then 6.422 becomes 6.4.
Hence the correct answer is C.
Mary bought a tank whose dimensions are 5.6cm, 8.2cm and 12.8 cm. The volume of water (in cm³) that can be stored in tank (correct up to four significant figures) is:
Volume of water = Volume of the tank = Length * breadth * height = 5.6 * 8.2 * 12.8 = 587.776
Volume, correct up to 4 significant figure = 587.8
Three physical quantity having dimensions [ML^{1}T^{2}] are:
Pressure = Force/Area = ML^{1}T^{2}/ L^{2} = [M L^{1} T^{2}]
Stress = Force/Area = ML^{1}T^{2}/ L^{2} = [ML^{1}T^{2}]
Coefficient of elasticity = Stress/Strain = [ML^{1}T^{2}]
Hence, the correct answer is C.
Find the option with 5 significant figures:
In option a, b and c, we only have 4 significant figures in the number
In option d, the number has 5 significant figures.
Therefore, the correct answer is D.
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