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Chapter Test: Friction - 2 - JEE MCQ


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30 Questions MCQ Test - Chapter Test: Friction - 2

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Chapter Test: Friction - 2 - Question 1

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Chapter Test: Friction - 2 - Question 2

In the arrangement shown in the figure mass of the block B and A are 2m and 8m respectively. Surface between B and floor is smooth. The block B is connected to block C by means of a pulley. If a whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is (Co-efficient of friction between A and B is µ)-



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Chapter Test: Friction - 2 - Question 3


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Chapter Test: Friction - 2 - Question 4


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Chapter Test: Friction - 2 - Question 5

A parabolic bowl with its bottom at origin has the shape y = x2/20. Here x and y are in metres, the maximum height at which a small mass m can be placed on the bowl without slipping (coefficient of static friction is 0.5) is

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Chapter Test: Friction - 2 - Question 6


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Chapter Test: Friction - 2 - Question 7

A conveyer belt of length l is moving with velocity v. A block of mass m is pushed against the motion of conveyer belt with velocity v0 form end B. Co-efficient of friction between block and belt is μ. The value of v0 so that the amount of heat liberated as a result of retardation of the block by conveyer belt is maximum is


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Chapter Test: Friction - 2 - Question 8


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Chapter Test: Friction - 2 - Question 9

A body of mass m is hauled up the hill with constant speed v by a force such that the force at each point is directed along the tangent to the path. The length of base of hill is L and its height is h. The coefficient of friction between the body and path is μ. Then which of the following statement is incorrect when body moves from bottom to top -


Detailed Solution for Chapter Test: Friction - 2 - Question 9

Conceptual

Chapter Test: Friction - 2 - Question 10

A block A of mass 200 kg rests on a block B of mass 300 kg. A is tied with a horizontal string to a wall. Coefficient of friction between A and B is 0.25 and that between B and floor is 0.2. The horizontal force F needed to move the

block B is (g = 10 ms–2)


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Chapter Test: Friction - 2 - Question 11

A parabolic bowl with its bottom at origin has the shape y = x2/20. Here x and y are in metres. The maximum height at which a small mass m can be placed on the bowl without slipping (coefficient of static friction is 0.5) is :


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Chapter Test: Friction - 2 - Question 12

Two identical blocks are kept on rough inclined plane (μ = 0.5). The blocks are connected with light string. If mg < F < 2mg, then -


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Chapter Test: Friction - 2 - Question 13

A rod AB of mass 10 kg tied with a string at C such that AC = BC and rod remains in equilibrium then friction force by horizontal surface will be –


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Chapter Test: Friction - 2 - Question 14

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and the floor (taking g = 10 ms–2) is -


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Chapter Test: Friction - 2 - Question 15

A ring of mass 200 gram is attached to one end of a light spring of force constant 100 N/m and natural length 10 cm. The ring is constrained to move on a rough wire in the shape of quarter ellipse of major axis 24 cm and minor axis 16 cm with its centre at origin. The plane of ellipse is vertical and wire is fixed at points A and B as shown in figure. Initially ring is at A with other end of spring fixed at origin. Ring is given a horizontal velocity of 10 m/s towards right so that it just reaches point B, then select the correct alternative (s) 

(g = 10 m/s2)



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Chapter Test: Friction - 2 - Question 16

A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction co-efficient between the block and the surface is μ.Maximum velocity of the block will be –

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Chapter Test: Friction - 2 - Question 17

A body of mass 40 kg resting on a rough horizontal surface is subjected to a force P which is just enough to start the motion of body.
If µs = 0.5, µk = 0.4, g = 10 m/s2 and the force P is continuously applied on the body, then the acceleration of the body is -

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Chapter Test: Friction - 2 - Question 18


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Chapter Test: Friction - 2 - Question 19


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Chapter Test: Friction - 2 - Question 20

A block A of mass 2 kg rests on another block B of mass 8 kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2 while between B and floor is 0.5. When a horizontal force 25 N is applied on B, the0 frictional force acting between A and B is -

Detailed Solution for Chapter Test: Friction - 2 - Question 20

Limiting friction on block B = 0.5 × (2 + 8) × 10 = 50 N

∴ block B will not move.

Chapter Test: Friction - 2 - Question 21


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Chapter Test: Friction - 2 - Question 22

A particle moves on a rough horizontal ground with some initial velocity say v0. If 3/4th of its kinetic energy is lost in friction in time t0. Then coefficient of friction between the particle and the ground is -

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Chapter Test: Friction - 2 - Question 23

A suitcase is gently dropped on a conveyor belt moving at 3 m/s. If the coefficient of friction between the belt and the suitcase is 0.5, find the displacement of the suitcase relative to conveyor belt before the slipping between the two is stopped : (g = 10 m/s2)

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Chapter Test: Friction - 2 - Question 24

A box weighing 20 kg is being pulled along a wooden floor with a force of 500 N. If µk = 0.5, the acceleration of the block is [g = 10 m/s2]

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Chapter Test: Friction - 2 - Question 25

Two blocks of masses m and 2 m placed one over the other as shown in figure. The coefficient of friction between m and 2m is µ and between 2m and ground is µ/3. If a horizontal force F is applied on upper block and T is tension developed in string then choose the incorrect alternative.



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Chapter Test: Friction - 2 - Question 26

Which one of the following species of earthworm is not recommended for vermicomposting?

Detailed Solution for Chapter Test: Friction - 2 - Question 26
Explanation:

The species of earthworm that is not recommended for vermicomposting is Pheretima posthuma.


Here is a detailed explanation:


Eudrilus eugeniae:
- This species of earthworm is commonly known as the African nightcrawler.
- It is highly recommended for vermicomposting.
- It has a high reproductive rate and can consume large amounts of organic waste.
Eisenia fetida:
- This species of earthworm is commonly known as the red wiggler or redworm.
- It is one of the most popular earthworm species used for vermicomposting.
- It has a rapid reproduction rate and can efficiently decompose organic waste.
Pheretima posthuma:
- This species of earthworm, also known as the Indian blue worm, is not recommended for vermicomposting.
- It is a large earthworm that requires specific environmental conditions and does not thrive well in a vermicomposting system.
- Pheretima posthuma is more suited for soil improvement and not specifically for vermicomposting.
Perionyx excavatus:
- This species of earthworm, commonly known as the Indian blue worm or blue perionyx, is highly recommended for vermicomposting.
- It has a high tolerance for a wide range of environmental conditions and can efficiently decompose organic waste.
In summary, while all other options (A, B, and D) are suitable for vermicomposting, the species Pheretima posthuma is not recommended for this purpose.
Chapter Test: Friction - 2 - Question 27

After the body starts moving, the friction involved with motion is

Detailed Solution for Chapter Test: Friction - 2 - Question 27

When the body is in rest it is under static friction but when it starts moving (neither rolling nor sliding), the static friction slowly chngs to kinetic friction as the coefficient of static friction start decreasing and that of kinetic friction starts increasing. In case it starts rolling motion then the friction is rolling friction & if it slides then sliding fiction.

Chapter Test: Friction - 2 - Question 28

Impending motion of a body is opposed by

Detailed Solution for Chapter Test: Friction - 2 - Question 28

The impending motion refers to the state of a body when it is on the verge of slipping. In such cases, the static friction has reached its upper limit and is given by the equation, F=μsN

Chapter Test: Friction - 2 - Question 29

A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 ms-2, the frictional force acting on the block is

Detailed Solution for Chapter Test: Friction - 2 - Question 29

Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N

Applied force = F = ma = 1 × 5 = 5 N

As F < f, so force of friction = 5 N

Chapter Test: Friction - 2 - Question 30

A particle moves in a circle with a constant speed of 6m /s. Its centripetal acceleration is 120 m/s2, The radius of the circle is

Detailed Solution for Chapter Test: Friction - 2 - Question 30

We know that centripetal acceleration, c = v2/r
Thus we get r = v2/c
= 36 / 120
= .3 /m

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