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Test: Specific Weight & Specific Gravity - Civil Engineering (CE) MCQ


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10 Questions MCQ Test Fluid Mechanics for Civil Engineering - Test: Specific Weight & Specific Gravity

Test: Specific Weight & Specific Gravity for Civil Engineering (CE) 2024 is part of Fluid Mechanics for Civil Engineering preparation. The Test: Specific Weight & Specific Gravity questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Specific Weight & Specific Gravity MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Specific Weight & Specific Gravity below.
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Test: Specific Weight & Specific Gravity - Question 1

One litre of water occupies a volume of:

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 1
  • 1 litre is equal to 1 cubic decimetre.
  • That is the volume of a cube 10 centimetres × 10 centimetres × 10 centimetres.
  • 1 L ≡ 1 dm3 ≡ 1000 cm3
  • 1 L ≡ 0.001 m3 ≡ 1000 cm3
Test: Specific Weight & Specific Gravity - Question 2

Which of the following instrument is used to measure the specific gravity of liquid ?

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 2

The hydrometer is a device which is used to measure specific gravity.
Various devices/equipment and their use is described in the table below:

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Test: Specific Weight & Specific Gravity - Question 3

Hydrometer is an instrument for measuring 

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 3

The hydrometer is a device which is used to measure specific gravity.
Various devices/equipments and their use is described in the table below:

Test: Specific Weight & Specific Gravity - Question 4

An increase in pressure of a liquid from 7.5 MPa to 15 MPa results into 0.2 percent decrease in its volume. The coefficient of compressibility of the liquid in m2/N is

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 4

Concept:
In thermodynamics and Fluid Engineering, compressibility is a measure of the relative volume change of a fluid as a response to pressure (or mean stress) change.
Compressibility in Fluid Engineering is expressed as follows:

where, ∂p = change of pressure, ∂v = change in the volume
K = bulk modulus
(-ve) sign indicates, there is a decrease in volume due to an increase in pressure.

Calculation:
Given:

dV = 0.2%, δP = 15 - 7.5 = 7.5 MPa 

Test: Specific Weight & Specific Gravity - Question 5

A liquid compressed in cylinder has a volume of 0.04 m3 at 50 kg/cm2 and a volume of 0.039 m3 at 150 kg/cm2. The bulk modulus of liquid is

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 5

Concept:
When a body is submerged in a fluid, it undergoes hydraulic stress (equal in magnitude to the hydraulic pressure); This leads to a decrease in the volume of the body thus producing a strain called volume strain

  • The ratio of hydraulic stress to the corresponding hydraulic strain is called bulk modulus

Calculation:
Given:

P1 = 50 kg/cm2, P2 = 150 kg/cm2, V1 = 0.04 m3, V2 = 0.039 m3

= 4000 kg/cm2

Test: Specific Weight & Specific Gravity - Question 6

A reservoir of capacity 0.01 m3 is completely filled with a fluid of coefficient of compressibility 0.75 × 10-9 m2/N. The amount of fluid that will spill over (in m3), if pressure in the reservoir is reduced by 2 × 107 N/m2 is

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 6

Concept:
In thermodynamics and Fluid Engineering, compressibility is a measure of the relative volume change of a fluid as a response to pressure (or mean stress) change.
Compressibility in Fluid Engineering is expressed as follows:

where, ∂p = change of pressure, ∂v = change in the volume
K = bulk modulus
(-ve) sign indicates, there is a decrease in volume due to an increase in pressure.

Calculation:
Given:
β = 0.75× 10-9 m2/N, V = 0.01 m3, dP = 2 × 107 Pa
Compressibility (β)


dV = 1.5 × 10-4

Test: Specific Weight & Specific Gravity - Question 7

The volume of a fluid occupied by a unit mass of the fluid is called -

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 7

Specific Volume

  • The specific volume of the fluid is defined as the volume of the fluid occupied by a unit mass or volume per unit mass of a fluid is called a specific volume.
  • Specific volume is reciprocal of mass density.

Viscosity

  • Viscosity – the property of the fluid which offers resistance to the movement of one layer of fluid over another layer.
  • SI unit of viscosity is 
  • CGS unit of viscosity also called poise 
  • 1 poise =

Specific weight:

  • Specific weight is defined as weight per unit volume.
  • Its unit is N/m3.

Specific gravity is the ratio of the specific weight of the liquid to the specific weight of a standard fluid. In the case of liquids standard fluid is taken as water with specific gravity 1.

Test: Specific Weight & Specific Gravity - Question 8

Specific gravity of marble stone which weighs 400 N in air and 300 N in water is ________

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 8

Concept:
Specific gravity of the body is given by:

Calculation:
Given:
weight in air = 400 N, weight in water = 300 N
weight loss = 400 - 300 = 100 N
Specific gravity of marble stone is:

Test: Specific Weight & Specific Gravity - Question 9

Specific volume is reciprocal of:

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 9
  • The reciprocal of the mass density is known as Specific volume.
  • The Specific volume of a material is the ratio of the volume of the material to its mass.
  • It is both the inverse of mass and the intrinsic property of matter.
  • Specific volume is defined as the number of cubic meters occupied by one kilogram of a substance.
  • The normal unit shall be the cubic meter per kilogram (m3/kg)
  • The specific volume for the ideal gas is also equal to the gas constant (R) multiplied by the temperature and then divided by the pressure multiplied by the molar mass of the ideal gas.
Test: Specific Weight & Specific Gravity - Question 10

Dimension of specific volume is:

Detailed Solution for Test: Specific Weight & Specific Gravity - Question 10

Dimensional Analysis:

  • The systematic procedure of identifying the variables in physical phenomena and correlating them to form a set of the dimensionless group is known as dimensional analysis.

Specific volume:

  • It is defined as the volume per unit mass.
  • Thus, L3M-1T0 is the dimensional formula of Specific volume.
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