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Test: Newton Raphson Method - Civil Engineering (CE) MCQ


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10 Questions MCQ Test Engineering Mathematics - Test: Newton Raphson Method

Test: Newton Raphson Method for Civil Engineering (CE) 2024 is part of Engineering Mathematics preparation. The Test: Newton Raphson Method questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Newton Raphson Method MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Newton Raphson Method below.
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Test: Newton Raphson Method - Question 1

The value of y’/x’ in terms of the angle 0 is given by ______

Detailed Solution for Test: Newton Raphson Method - Question 1

The value of derivative of a function f(x) is given as f’(x) = y’/x’. In terms of theta tangent is the ration of opposite side to adjacent side hence y’/x’ = tanθ.

Test: Newton Raphson Method - Question 2

The Newton-Raphson method is to be used to determine the reciprocal of the number x = 4. If we start with the initial guess 0.20 then after the first iteration the reciprocal is

Detailed Solution for Test: Newton Raphson Method - Question 2

According to the Newton-Rapson method we have;

CALCULATION:
As we know;

Now,

Now putting all the values we have;
xn+1 = 2 × 0.20 − 0.20× 4
⇒ xn+1 = 0.24
Hence option (2) is the correct answer.

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Test: Newton Raphson Method - Question 3

Starting with x = 1, the solution of the equation x3 + x = 1, after two iterations of newton raphson’s method (up to two decimal places) is

Test: Newton Raphson Method - Question 4

The Newton Raphson method is also called as ______

Detailed Solution for Test: Newton Raphson Method - Question 4

Newton Raphson method is also known as Tangent Method. It is carried out by drawing a tangent to the curve at the point of initial guess.

Test: Newton Raphson Method - Question 5

The iterative formula to find the root of the equation f(x) = x3 - 5x + 7 = 0 by the Newton Raphson method is ______.

Detailed Solution for Test: Newton Raphson Method - Question 5

Newton Raphson method:
The iteration formula is 
Calculation:
Given

Test: Newton Raphson Method - Question 6

Newton raphson method is to be used to find root of equation 3x – ex + sinx = 0. If the initial trial value of the roots is taken as 0.333, the next approximation for the root would be

Test: Newton Raphson Method - Question 7

The equation f(x) is given as x2-4=0. Considering the initial approximation at x = 6 then the value of x1 is given as ____________

Detailed Solution for Test: Newton Raphson Method - Question 7

Iterative formula for Newton Raphson method is given by

Hence x0=6 (initial guess), f(x0) = 32 and f’(x0) = 12.
Substituting the values in the equation we get x1 = 10/3.

Test: Newton Raphson Method - Question 8

The iteration step in order to solve for the cube roots of a given number Nusing the Newton- Raphson’s method is

Detailed Solution for Test: Newton Raphson Method - Question 8

Concept: 
Let x0 be an approximation root of f(x) = 0 and x1 = x0th
be the correct root so that f(x1) = 0 expanding f(x0th) by Taylor's series we obtain

Neglecting the second and higher order derivatives we have f(x0) + hf'(x0) = 0

A better approximation than x0 is therefore given by x1, where x1 = x0 + h = 
successive approximations are given by x2, x3 ....xn+1 where

For pth root of a given number N, is not of equation f(x) = xp - N = 0
Iteration equation:

for cube root, put p = 3

Therefore, option (2) is correct one.

Test: Newton Raphson Method - Question 9

The root of the function f(x) = x3 + x – 1 obtained after first iteration on application of newton raphson scheme using an initial guess of xo = 1 is

Test: Newton Raphson Method - Question 10

For decreasing the number of iterations in Newton Raphson method:

Detailed Solution for Test: Newton Raphson Method - Question 10

Iterative formula is given by

Hence if f’(x) decreases the value of next iteration approaches the initial one. This decreases the number of iterations in finding out next iterative value.

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