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RRB JE ECE (CBT II) Mock Test- 7 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test - RRB JE ECE (CBT II) Mock Test- 7

RRB JE ECE (CBT II) Mock Test- 7 for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The RRB JE ECE (CBT II) Mock Test- 7 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The RRB JE ECE (CBT II) Mock Test- 7 MCQs are made for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ECE (CBT II) Mock Test- 7 below.
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RRB JE ECE (CBT II) Mock Test- 7 - Question 1

A 220 Ω resistor is connected in series with the gate of an SCR as shown in fig. The gate current required to fire the SCR is 7 mA. What is the input voltage (Vin) required to fire the SCR?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 1

The input voltage must overcome the junction voltage between the gate and cathode (0.7V) and cause 7 mA to flow through the 220 Ω resistor. According to Kirchhoff’s voltage law, Vin us given by:
Vin = VGK + IGR
= 0.7V + (7 mA) (220 Ω) = 2.24 V

RRB JE ECE (CBT II) Mock Test- 7 - Question 2

Which of the following living beings is most likely to produce greenhouse gases?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 2

Green plants are most likely to produce greenhouse gases.

  • Greenhouse gases consists gases such as carbon dioxide, methane, water vapour, nitrous oxide and ozone.
  • These gases absorbs heat which produced from the Sun.
  • A greenhouse is called so because it is a house which contains green things such as plants and beneficial gasses.

RRB JE ECE (CBT II) Mock Test- 7 - Question 3

Solid grounding is adopted for voltages below

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 3

Solid grounding is adopted for voltages below 600 V because of the higher point-of-fault energy levels. A power system is said to be effectively grounded or solidly grounded when the neutral of a generator, power transformer or grounding transformer are directly connected to the ground through a conductor of negligible resistance and reactance.

RRB JE ECE (CBT II) Mock Test- 7 - Question 4

A bipolar transistor has a maximum junction temperature rating of 200°C. If its junction-to-case thermal resistance of 1°C per watt, the transistor can dissipate at the most a power of 100 watts if the case temperature is not to exceed

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 4

Let the case and junction temperature be T₁ and T₂. The thermal resistance θR = 1°C/W. Then power
dissipated PD is given by,
PD = T2 - T1R
⇒ T1 = T2 - PD . θR
⇒ T1 = 200 - 100 × 1 = 100°C
Thus, the case temperature should be, T1 = 100°C

RRB JE ECE (CBT II) Mock Test- 7 - Question 5

Which among the following glasses can cut off the UV rays?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 5
  • Crooked Glass can cut off the UV rays.
  • It is a special type of glass which contains Cerium Oxide [CeO2].
  • It is used in making sunglasses.
RRB JE ECE (CBT II) Mock Test- 7 - Question 6

The process of decomposing organic waste in the presence of air is termed as

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 6

Incineration is a waste treatment process that involves the combustion of organic substances contained in waste materials. Incineration and other high-temperature waste treatment systems are described as "thermal treatment". Incineration of waste materials converts the waste into ash, flue gas and heat means in the presence of air

RRB JE ECE (CBT II) Mock Test- 7 - Question 7

The current passing through a terminal is i = (3t2 - t) A
Determine the total charge entering the terminal between t = 1 s and t = 2 s

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 7


Q = 7 - 15
Q = 5.5 C

RRB JE ECE (CBT II) Mock Test- 7 - Question 8

Which of the following companies has launched the educational app ‘JEE Ready’?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 8

Global e-commerce giant ‘Amazon’ has entered, into the ed tech space with the launch of its first ed tech app in India called ‘JEE Ready’ for IIT JEE.
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 7 - Question 9

As per Indian Protocol, who among the following ranks highest in the order of precedence?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 9

Self explanatory as per the list of precedence given by the constitution
Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 7 - Question 10

How many times Testbook will be printed?
                for(i=0;i<6;i++)
                {
                                if(i==3)
                      continue;
                                printf("Testbook\n");
                }

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 10
  • Continue is also a loop control statement just like the break statement
  • continue statement is opposite to that of break statement, instead of terminating the loop, it forces to execute the next iteration of the loop
  • When the continue statement is executed in the loop, the code inside the loop following the continue statement will be skipped and next iteration of the loop will begin

Syntax: continue;

  • When i=3 condition in if expression becomes true then Testbook won’t be printed else it will be printed
  • loop will run 6 times but Testbook will be printed for 5 times

Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 7 - Question 11

Electron beam in oscilloscope is deflected in __________

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 11
  • The electron beam in an oscilloscope can be deflected in two directions.
  • One is horizontal (x-direction) and the second vertical (y-direction).
  • When two inputs are applied at horizontal and vertical plates, two dimensional displays are produced as a result.

Hence, the correct option is (D)

RRB JE ECE (CBT II) Mock Test- 7 - Question 12

The heights (in cm) of 5 students are 150, 165, 161, 144 and 155. What are the values of mean and median (in cm) respectively?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 12

The "Mean" is the "average" = 150 + 165 + 161 + 144 ++ 155/5 = 775/5 = 155
The "Median" is the "middle" value in the list of numbers, given number is 144,150,155,161 and 165, middle value of given 
numbers is 155 i.e. median of given number is 155
Mean = 155 and median = 155 
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 7 - Question 13
To an observer on the earth the stars appear to twinkle, this is because:
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 13

The twinkling of a star is due to atmospheric refraction of starlight. The starlight, on entering the earth’s atmosphere, undergoes refraction continuously before it reaches the earth.

The atmospheric refraction occurs in a medium of gradually changing refractive index.

Since the atmosphere bends starlight towards the normal, the apparent position of the star is slightly different from its actual position.

RRB JE ECE (CBT II) Mock Test- 7 - Question 14
Microcontroller 8051 has ____ I/O ports.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 14

8051 is a 8-bit microcontroller with 40 pin chip. It has 4 8-bit input ports (P0, P1, P2, P3) port P1 is a general purpose I/O port while P0, P2, P3 have additional function associated with them based on context of their usage.

RRB JE ECE (CBT II) Mock Test- 7 - Question 15
A conducting SCR can be opened by reducing __________to zero.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 15

  • To turn OFF the conducting SCR, the anode or forward current of SCR must be reduced to zero or below the level of holding current and then an enough reverse voltage must be applied across the SCR to regain its forward blocking state
  • The reverse voltage which causes to commutate the SCR is called commutation voltage.
  • A conducting SCR can be opened by reducing the anode current to zero

RRB JE ECE (CBT II) Mock Test- 7 - Question 16

What is the status of Carry flag after the execution of following instruction?

MVI A, FF H

INR A 

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 16

FF + 01 = 1 00 H

The accumulator contains 00 H

And 1 carry is obtained

The important point to note here that though carry is obtained but carry flag will not be used because INR instruction does not affect carry flag.

The status of carry flag will remain unaltered I.e. if it was set earlier it will remain set if it was reset earlier, it will remain reset

RRB JE ECE (CBT II) Mock Test- 7 - Question 17
What was the theme of the World Brain Day 2019?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 17

  • World Brain Day is observed on July 22 every year.
  • The day aims at promoting interest of neurology. Previously, World Brain Day has covered topics like dementia, epilepsy and stroke, in cooperation with other societies.
  • World Brain Day 2019 theme is Migraine: The Painful Truth.
  • This year, the focus is on migraine, which is known to be one of world's most common brain diseases.

RRB JE ECE (CBT II) Mock Test- 7 - Question 18

The series element of a band stop filter is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 18

Band stop filter using Parallel L and C is shown

  • At low frequencies, L is a short circuit and passes low frequencies
  • At High frequencies, Capacitor C acts as a short circuit and passes high frequencies
  • But at mid-frequency say Resonant frequency parallel L-C circuit behaves as an open circuit and the output voltage Vout is zero
RRB JE ECE (CBT II) Mock Test- 7 - Question 19

An electric field Intensity of 15 V/cm is applied across semiconductor of length 5 cm and drift velocity was observed to be 90 m/s. The electron mobility in the semiconductor is:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 19

Concept:
The drift velocity is related to electric field and mobility by
v  = μn E
Calculations:
900m / s = μn 15 V / cm

μn = 600 cm2/V-sec

RRB JE ECE (CBT II) Mock Test- 7 - Question 20

 The Dead Sea is located between which two countries?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 20

  • The Dead Sea is a salt lake which is bordered by Jordan to the east and Israel to the west.
  • The Dead Sea lies in the Jordan Rift Valley, with the Jordan River as its main tributary.
  • Its surface and shores are 430.5 meters (1412 feet) below sea level.

RRB JE ECE (CBT II) Mock Test- 7 - Question 21
Burden of a protective relay is the power
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 21

Burden of a protective relay is the power absorbed by the relay circuit. It is expressed in volt amperes (VA).

RRB JE ECE (CBT II) Mock Test- 7 - Question 22

A solution contains 40 g of common salt in 320 g of water. The concentration in terms of mass by mass percentage of the solution.

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 22

Mass of solute (salt) = 40 g

Mass of solvent (water) = 320 g

We know,

Mass of solution = Mass of solute + Mass of solvent

= 40 g + 320 g

= 360 g

mass percentage of solution = mass of solute / mass of solution x 100

mass percentage of solution = 40/360 x 100 = 11.11 %

RRB JE ECE (CBT II) Mock Test- 7 - Question 23

Which of the following networking device is called as protocol converter?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 23

Gateway is used to connect system from one layer of TCP/IP to another layer of TCP/IP.

A gateway device provides communication to a remote network or an autonomous system that is out of bounds for the host network nodes.

Gateways serve as the entry and exit point of a network; all data routed inward or outward must first pass through and communicate with the gateway in order to use routing paths

Other Networking Devices and their functions are:

RRB JE ECE (CBT II) Mock Test- 7 - Question 24

Which of the following multiplexing techniques is used for digital data transmission?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 24

RRB JE ECE (CBT II) Mock Test- 7 - Question 25

Correct Boolean expression representing modulus-2 addition is:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 25

The truth table for modulus-2 addition is

S = A'B + AB'

C = AB

RRB JE ECE (CBT II) Mock Test- 7 - Question 26
Which of the following statements is TRUE about the operating system?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 26

Mac OS is developed by Apple. Mac OS is a series of graphical operating systems which is developed and marked by Apple. Windows 7 is developed by Microsoft. IOS is developed by Apple Inc. Bada OS was developed by Samsung Electronics.

RRB JE ECE (CBT II) Mock Test- 7 - Question 27

Number of NAND gates required to implement
X = A B C + A’ B + A B C’

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 27

X = ABC + ABC’ + A’B

X = AB (C + C’) + A’B

X = AB + A’B

X= B(A + A’)

X= B

Since output is equal to input B hence no NAND gate is required to implement the expression.

RRB JE ECE (CBT II) Mock Test- 7 - Question 28
A device which reads barcodes and converts them into electric pulses to be processed by a computer is
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 28

A barcode reader is an electronic device that can read barcodes and converts them into electric pulses to be processed by a computer. A barcode reader scans the barcode, and the CPU handle the barcode, turn them into information that we can read and it sends the data to the scanner's output port.

RRB JE ECE (CBT II) Mock Test- 7 - Question 29

The input resistance Rin and output resistance Rout of an ideal Transresistance amplifier, in ohms are

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 29

A transresistance amplifier has current as input and voltage as output.

For effective coupling of current to transistor, the input impedance should be small.

The output is voltage:

Hence for effective coupling of output to load, the output resistance is large.

Generally the Transresistance amplifier has low input impedance and low output impedance.

Hence in ideal case it should have Rin = 0 and Rout = 0

Similarly the Transconductance amplifier has high input impedance and high output impedance.

Hence in ideal case it should have Rin = ∞ and Rout = ∞

RRB JE ECE (CBT II) Mock Test- 7 - Question 30
The Schottky-barrier diode has
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 7 - Question 30

  • A Schottky diode is formed between metal and semiconductor (n-type), thus there is no p-n junction in Schottky diode
  • Schottky diodes have less recovery time compare to normal diodes and hence provide fast switching speeds
  • Schottky diodes are used at high-frequency applications

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