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Test: Quadrilaterals- 1 - Class 9 MCQ


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Test: Quadrilaterals- 1 - Question 1

The length of each side of a rhombus is 10cm and one of its diagonal is of length 16cm. The Length of the other Diagonal is:

Detailed Solution for Test: Quadrilaterals- 1 - Question 1
Firstly we know that diagonal of rhombus bisects each other. thus half of diagonal =8cm.
by pythagoras theorem we find another half of diagonal.that is 6 cm
as we diagonals bisect other thus another diagonal
=2×6=12cm
Test: Quadrilaterals- 1 - Question 2

In a Quadrilateral ABCD, AB = BC and CD = DA, then the quadrilateral is a

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Test: Quadrilaterals- 1 - Question 3

ABCD is a Parallelogram in which AB = 9.5cm and its perimeter is 30cm. Find the length of each side of the Parallelogram?

Detailed Solution for Test: Quadrilaterals- 1 - Question 3

We know that the perimeter of parallelogram ABCD can be written as

Perimeter = AB + BC + CD + DA

We know that opposite sides of parallelogram are equal

AB = CD and BC = DA

By substituting the values

Perimeter = 9.5 + BC + 9.5 + BC

It is given that perimeter = 30 cm

So we get

30 = 19 + 2BC

It can be written as

2BC = 30 – 19

By subtraction

2BC = 11

By division we get

BC = 5.5 cm

Therefore, AB = 9.5 cm, BC = 5.5 cm, CD = 9.5 cm and DA = 5.5 cm.

Test: Quadrilaterals- 1 - Question 4

The angle between two altitudes of a Parallelogram through the vertex of an obtuse angle of the Parallelogram of 60. Find the angles of the Parallelogram

Detailed Solution for Test: Quadrilaterals- 1 - Question 4

Test: Quadrilaterals- 1 - Question 5

If an angle of a parallelogram is two-third of its adjacent angle, then find the smallest angle of the parallelogram.

Detailed Solution for Test: Quadrilaterals- 1 - Question 5


Test: Quadrilaterals- 1 - Question 6

If ABCD is a Parallelogram with 2 Adjacent angles ∠A =∠B, then the parallelogram is a

Test: Quadrilaterals- 1 - Question 7

Given a triangular prism, then what can we conclude about the lateral faces?

Detailed Solution for Test: Quadrilaterals- 1 - Question 7

In a triangular prism, the bases are triangles and the lateral faces are parallelograms.

Thus it can be both rectangles and parallelograms.

So, option (D) is correct.

If the faces are rectangles, then we call it as right triangular prism

Observe the following figure.

It is clear that the faces of the above figure are rectangles and hence it is right triangular prism.

Test: Quadrilaterals- 1 - Question 8

If angles A, B, C and D of the quadrilateral ABCD, taken in order, are in the ratio 3:7:6:4, then ABCD is 

Detailed Solution for Test: Quadrilaterals- 1 - Question 8

 Given, ratio of angles of quadrilateral ABCD is 3 : 7 : 6 : 4.
Let angles of quadrilateral ABCD be 3x, 7x, 6x and 4x, respectively. We know that, sum of all angles of a quadrilateral is 360°.
3x + 7x + 6x + 4x = 360°
=> 20x = 360°
=> x=360°/20° = 18°

Test: Quadrilaterals- 1 - Question 9

ABCD is a Trapezium in which AB∥DC and ∠A = ∠B = 45. Find angles C and D of the Trapezium

Test: Quadrilaterals- 1 - Question 10

Angles of a quadrilateral are in the ratio 3 : 6 : 8: 13. The largest angle is :

Detailed Solution for Test: Quadrilaterals- 1 - Question 10

3p + 6p + 8p + 13p = 30p = 360° ⇒ p

= 12° Largest angle is 13p = 13 × 12°

= 156°

Test: Quadrilaterals- 1 - Question 11

If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is:

Test: Quadrilaterals- 1 - Question 12

Consecutive angles of a Parallelogram are

Test: Quadrilaterals- 1 - Question 13

The angles of a quadrilateral are in the ratio 4: 5: 10: 11. The angles are

Detailed Solution for Test: Quadrilaterals- 1 - Question 13

 Let x be the common angle among all the four angles of a quadrilateral.

As per angle sum property, we know:

4x+5x+10x+11x = 360°

30x = 360°

x = 12°

Hence, angles are

4x = 4 (12) = 48°

5x = 5 (12) = 60°

10x = 10 (12) = 120°

11x = 11 (12) = 132°

Test: Quadrilaterals- 1 - Question 14

One Angle of a quadrilateral is of 108 and the remaining three angles are equal. Find each of the three equal angles.

Detailed Solution for Test: Quadrilaterals- 1 - Question 14

Test: Quadrilaterals- 1 - Question 15

ABCD is a Rectangle. Find the values of x and y?

AB =30 DA= 14 DC= x+y CB=x-y

Detailed Solution for Test: Quadrilaterals- 1 - Question 15

ABCD is a rectangle.
∴ AB = CD
⇒ 30 = x + y
or x + y = 30 ..... (i)
Similarly, AD = BC
⇒ 14 = x - y
or x - y = 14 .......(ii)
On adding eq. (i) and (ii), we get
2x = 44
⇒ x = 22
Putting the value of x in eq. (i), we get
22 + y = 30
⇒ y = 30 -22
⇒ y = 8
So, x = 22, y = 8.

Test: Quadrilaterals- 1 - Question 16

If area of a Parallelogram with sides ‘a’ and ‘b’ is A and that of a rectangle with sides ‘a’ and ‘b’ is B, then

Test: Quadrilaterals- 1 - Question 17

A diagonal of a Rectangle is inclines to one side of the rectangle at an angle of 25. The Acute Angle between the diagonals is :

Test: Quadrilaterals- 1 - Question 18

Diagonals of a Parallelogram ABCD intersect at O. If ∠BOC = 90, ∠BDC = 50 then ∠OAB is

Test: Quadrilaterals- 1 - Question 19

Angles of a quadrilateral are in the ratio 3 : 4 : 4 : 7. Find all the angles of the quadrilateral.

Test: Quadrilaterals- 1 - Question 20

In Triangle ABC which is right angled at B. Given that AB = 9cm, AC = 15cm and D, E are the mid-points of the sides AB and AC res. Find the length of BC?

Test: Quadrilaterals- 1 - Question 21

The Parallel sides of a trapezium are ‘a’ and ‘b’ res. The line joining the mid-points of its non-parallel sides will be

Test: Quadrilaterals- 1 - Question 22

If a diagonal AC and BD of a quadrilateral ABCD bisect each other, then ABCD is a

Test: Quadrilaterals- 1 - Question 23

Which of the following is not true for the Parallelogram?

Test: Quadrilaterals- 1 - Question 24

The angles of the quadrilateral are in the ratios 3 : 5 : 9 : 13. Find all the angles of the Quadrilateral

Test: Quadrilaterals- 1 - Question 25

The length of each side of a rhombus is 10cm and one of its diagonal is of length 16cm. The Length of the other Diagonal is:

Detailed Solution for Test: Quadrilaterals- 1 - Question 25

Use pythagoras theorem in right triangle,

102 -[16/2]2 = 100 -64 = 36 = [6]2 ; hence the other diagonal = 6x2 = 12cm

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