Test: Uniform Circular Motion (NCERT) - NEET MCQ

# Test: Uniform Circular Motion (NCERT) - NEET MCQ

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## 10 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Uniform Circular Motion (NCERT)

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Test: Uniform Circular Motion (NCERT) - Question 1

### The term centripetal acceleration was proposed by

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 1

The term centripetal acceleration was proposed by Newton.

Test: Uniform Circular Motion (NCERT) - Question 2

### Centripetal acceleration is

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 2

Centripetal acceleration, ac = v2/R
where v is the speed of an object and R is the radius of the circle. It is always directed towards the center of the circle. Since v and R are constants for a given uniform circular motion, therefore the magnitude of centripetal acceleration is also constant. However, the direction of centripetal acceleration changes continuously. Therefore, centripetal acceleration is not a constant vector.

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Test: Uniform Circular Motion (NCERT) - Question 3

### What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g = 10 m s-2) of an air-craft flying at a speed of 400 m s-1 through a circular arc of radius 0.6 km?

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 3

Here, v  = 400ms−1,

r = 0.6 km = 0.6 × 103m,

g = 10ms−2
Centripetal acceleration,

= 26.7 × 10ms−2
In the units of (g = 10ms−2), the centripetal acceleration is 26.7.

Test: Uniform Circular Motion (NCERT) - Question 4

Velocity vector and acceleration vector in a uniform circular motion are related as

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 4

In a uniform circular motion, the acceleration is directed towards the centre while velocity is acting tangentially. Therefore, velocity vector is perpendicular to acceleration vector.

Test: Uniform Circular Motion (NCERT) - Question 5

A body executing uniform circular motion has its position vector and acceleration vector

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 5

In Circular motion, the Position vector is always outward and passes through the center. whereas the and centripetal acceleration is always toward the center.
∴ Both is the opposite direction.

Test: Uniform Circular Motion (NCERT) - Question 6

For a particle performing uniform circular motion, choose the incorrect statement form the following.

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 6

For a particle performing uniform circular motion, magnitude of the acceleration remains constant.

Test: Uniform Circular Motion (NCERT) - Question 7

Which of the following statements is incorrect?

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 7

The kinematic equations for uniform acceleration do not apply in case of uniform circular motion because in this case the magnitude of acceleration is constant but its direction is changing.

Test: Uniform Circular Motion (NCERT) - Question 8

A particle is moving on a circular path of radius r with uniform speed v. What is the displacement of the particle after it has described an angle of 60°?

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 8

Let the particle is moving from point A to B
Displacement of the particle = AB
According to cosine formula

Displacement AB = x = r

Test: Uniform Circular Motion (NCERT) - Question 9

A cyclist starts from the centre O of a circular park of radius 1 km, reaches the edge P of the park, then cycles along the circumference and returns to the centre along QO as shown in the figure.

If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 9

Since the initial position coincides with the final position. So, the net displacement of the cyclist = zero

Test: Uniform Circular Motion (NCERT) - Question 10

A cyclist is riding with a speed of 27 km h-1. As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 m s-1 every second. The net acceleration of the cyclist on the circular turn is

Detailed Solution for Test: Uniform Circular Motion (NCERT) - Question 10

Given here,
Speed of the cyclist, = 27 km/h = 7.5m/s
Radius of the circular tun on the road, r = 80 m
Therefore the centripetal acceleration of the cyclist at the moment when velocity is 7.5 m/s is,

When brakes are applied, the speed is decreased at the rate of 0.5m/s every second.

Therefore the tangential acceleration is,
ar = - 0.5 m/s2
Therefore the total acceleration of the cyclist is,

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