NEET Exam  >  NEET Tests  >  Daily Test for NEET Preparation  >  Test: Mechanical Properties of Solids (October 8) - NEET MCQ

Test: Mechanical Properties of Solids (October 8) - NEET MCQ


Test Description

10 Questions MCQ Test Daily Test for NEET Preparation - Test: Mechanical Properties of Solids (October 8)

Test: Mechanical Properties of Solids (October 8) for NEET 2024 is part of Daily Test for NEET Preparation preparation. The Test: Mechanical Properties of Solids (October 8) questions and answers have been prepared according to the NEET exam syllabus.The Test: Mechanical Properties of Solids (October 8) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mechanical Properties of Solids (October 8) below.
Solutions of Test: Mechanical Properties of Solids (October 8) questions in English are available as part of our Daily Test for NEET Preparation for NEET & Test: Mechanical Properties of Solids (October 8) solutions in Hindi for Daily Test for NEET Preparation course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: Mechanical Properties of Solids (October 8) | 10 questions in 20 minutes | Mock test for NEET preparation | Free important questions MCQ to study Daily Test for NEET Preparation for NEET Exam | Download free PDF with solutions
Test: Mechanical Properties of Solids (October 8) - Question 1

A steel rod 2.0 m long has a cross-sectional area of 0.30 cm2 . It is hung by one end from a support, and a 550-kg milling machine is hung from its other end. Determine the resulting strain. Young's Modulus of Steel (Y) = 20×1010 Pa

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 1

Stress = F⟂/A = (Mass x Acceleration⟂)/Cross-sectional Area

= (550 kg x 9.8 m/s2)/ (0.30×10−4 m2)

= 1.8×108 Pa

Young's ModulusSteel (Y) = 20×1010 Pa = Stress/Strain

=> Strain = Stress/Y = 1.8×108 Pa / 20×1010 Pa

= 9.0×10−4 

Test: Mechanical Properties of Solids (October 8) - Question 2

What diameter should a 10-m-long steel wire have if we do not want it to stretch more than 0.5 cm under a tension of 940 N? Take Young's modulus of steel as 20 × 1010 Pa

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 2

Y=F x l/A x Δ l
Δ l=0.5cm=0.5x10-2m, l=10M, F=940N
Y=20x1010pa
20x1010=940x10/πr2x0.5x10-10
πr2=94x100/5x10-3x2x1011=94x102/10x108
r2=94/π x 10-7 =2.99 x 10-6
r2 ≅3x10-6
r=1.13x10-10 m
diameter=2r=3.6mm

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Mechanical Properties of Solids (October 8) - Question 3

Elastomers are materials

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 3

An elastomer is a polymer with viscoelasticity (i. e., both viscosity and elasticity) and very weak intermolecular forces, and generally low Young's modulus and high failure strain compared with other materials. Elastomer rubber compounds are made from five to ten ingredients, each ingredient playing a specific role. Polymer is the main component, and determines heat and chemical resistance, as well as low- temperature performance. Reinforcing filler is used, typically carbon black, for strength properties.

Test: Mechanical Properties of Solids (October 8) - Question 4

Shear modulus or modulus of rigidity is

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 4

Shear modulus or modulus of rigidity is the ratio of shearing stress to the corresponding shearing strain, by the definition of shear modulus.

Test: Mechanical Properties of Solids (October 8) - Question 5

Rectangular section is rarely used in beams because

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 5

I section is generally used as a beam because of its high section modulus as its most of the area is situated away from its neutral axis hence it has high moment of inertia i.e. high section modulus i.e. high moment carrying capacity which is the major requirement for a good beam section.

Test: Mechanical Properties of Solids (October 8) - Question 6

You hang a flood lamp from the end of a vertical steel wire. The flood lamp stretches the wire 0.18 mm and the stress is proportional to the strain. How much would it have stretched if the wire were twice as long?

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 6

F/A = e/L
F/A = 0.18/l ( let the length be l)
F/A = x/2l
0.18/L = x/2l
0.18×2l = xl
0.36l = xl
x = 0.36

Test: Mechanical Properties of Solids (October 8) - Question 7

The S.I unit of stress is

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 7

Stress has its own SI unit called the Pascal. 1 Pascal (Pa) is equal to 1 N/m2. In imperial units stress is measured in pound force per square inch which is often shortened to "psi". The dimension of stress is same as that of pressure.

Test: Mechanical Properties of Solids (October 8) - Question 8

A lead cube measures 6.00 cm on each side. The bottom face is held in place by very strong glue to a flat horizontal surface, while a horizontal force F is applied to the upper face parallel to one of the edges. How large must F be to cause the cube to deform by 0.250 mm? (Shear modulus of lead = 0.6 × 1010Pa)

Detailed Solution for Test: Mechanical Properties of Solids (October 8) - Question 8

Test: Mechanical Properties of Solids (October 8) - Question 9

You hang a flood lamp from the end of a vertical steel wire. The flood lamp stretches the wire 0.18 mm and the stress is proportional to the strain. How much would it have stretched if the wire had the same length but twice the diameter?

Test: Mechanical Properties of Solids (October 8) - Question 10

You hang a flood lamp from the end of a vertical steel wire. The flood lamp stretches the wire 0.18 mm and the stress is proportional to the strain. How much would it have stretched for a copper wire of the original length and diameter?

12 docs|366 tests
Information about Test: Mechanical Properties of Solids (October 8) Page
In this test you can find the Exam questions for Test: Mechanical Properties of Solids (October 8) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Mechanical Properties of Solids (October 8), EduRev gives you an ample number of Online tests for practice

Top Courses for NEET

Download as PDF

Top Courses for NEET