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NEET Exam  >  NEET Tests  >  Chemistry Class 11  >  Test: p-Block Elements - 2 - NEET MCQ

Test: p-Block Elements - 2 - NEET MCQ


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25 Questions MCQ Test Chemistry Class 11 - Test: p-Block Elements - 2

Test: p-Block Elements - 2 for NEET 2024 is part of Chemistry Class 11 preparation. The Test: p-Block Elements - 2 questions and answers have been prepared according to the NEET exam syllabus.The Test: p-Block Elements - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: p-Block Elements - 2 below.
Solutions of Test: p-Block Elements - 2 questions in English are available as part of our Chemistry Class 11 for NEET & Test: p-Block Elements - 2 solutions in Hindi for Chemistry Class 11 course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: p-Block Elements - 2 | 25 questions in 35 minutes | Mock test for NEET preparation | Free important questions MCQ to study Chemistry Class 11 for NEET Exam | Download free PDF with solutions
Test: p-Block Elements - 2 - Question 1
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Inert pair effect of p-block elements is due to the

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Due to the presence of inner lying d and f electrons oxidation state which is 2 unit less than the group oxidation state become popular.

Test: p-Block Elements - 2 - Question 2
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The elements of group 14 are slightly more electronegative than group 13 elements because of

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As we move along the period electronegativity increases due to increase in nuclear charge.

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Test: p-Block Elements - 2 - Question 3
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In which of the following compounds, nitrogen exhibits highest oxidation state?

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so clearly N3H has the highest oxidation state

Test: p-Block Elements - 2 - Question 4
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The function of Fe (OH)3 in the contact process is
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Fe (OH)3 is used to remove arsenic impurities.

Test: p-Block Elements - 2 - Question 5
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In general, nonmetals as compared to metals have
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Non metals have high value of ionization energy while metals have comparatively low value of ionization energy.

Test: p-Block Elements - 2 - Question 6
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Among the following which is the strongest oxidizing agent?
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F2 is very strong oxidizing agent.

Test: p-Block Elements - 2 - Question 7
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The compounds formed by highly reactive non-metals with highly reactive metals are generally
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Compunds formed by highly reactive non metals and metals is ionic bond.

Test: p-Block Elements - 2 - Question 8
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A compound X, of boron reacts with NH3 on heating to give another compound. Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.
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BF3 reacts with LiAlH4 to form B2H6 which reacts with NH3NH3 in 1:2 ratio forming B3N3H6( Borazine , inorganic benzene

Test: p-Block Elements - 2 - Question 9
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Three reactions involving  are given below  

B.

C.   

 

In which of the above does  act as an acid?
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in B only  is losing its proton therefore act as acid.

Test: p-Block Elements - 2 - Question 10
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When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from
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The correct answer is option D
The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is
3Cl2​ + 6NaOH⟶NaClO3​+ 5NaCl+3H2​O
Oxidation number of Cl is 0 in Cl2​, −1 in NaCl and +5 in NaClO3​
So the oxidation number of chlorine changes from Zero to -1 and Zero to +5.
 

Test: p-Block Elements - 2 - Question 11
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As we move from B to Al in the p-block elements the sum of the first three ionisation enthalpies
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On moving from B to Al size increases so sum of ionization energies also decreases.

Test: p-Block Elements - 2 - Question 12
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The non-metal oxides are:
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nonmetallic oxides are either neutral or acidic. Example CO is neutral while CO2 is acidic.

Test: p-Block Elements - 2 - Question 13
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Dry ice is
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Dry ice is solid CO2

Test: p-Block Elements - 2 - Question 14
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The tendency of BF3, BCl3 and BBr3 to behave as Lewis acid decreases in the sequence:
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because in BF3 there is backbonding which decreases its acidity. And as we for from BF3 to BBr3 tendency of back bonding decreases so acidity increases,.

Test: p-Block Elements - 2 - Question 15
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Of the following compounds the most acidic is
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More is the oxidation number greater is the acidity of oxide

Test: p-Block Elements - 2 - Question 16
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Boron forms only covalent compounds and not +3 ions because
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Due to smaller size and high nuclear charge B has very high ionization energy value so doesnot show +3 oxidation state

Test: p-Block Elements - 2 - Question 17
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The element having the noble gas plus 14 f- electrons plus 10 d-electron cores
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Tl have bole gas + 14 f +10 d electrons.

Test: p-Block Elements - 2 - Question 18
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In trivalent state, for example, the trichlorides, being covalent are hydrolysed in water form
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trihalides hydrolysis to form tetrahedral structure

Test: p-Block Elements - 2 - Question 19
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Which of the following statements regarding ozone is not correct?
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Bond order of O-O bond in ozone is less than that in oxygen.
Due to resonance the bond order in ozone is 1.5, hence O---O bond length in O3​ is greater than O---O bond length in O2​.

Test: p-Block Elements - 2 - Question 20
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XeF2 is isostructural with
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The correct answer is option D

XeF2 is isostructural with ICl2−.
Both contain the same number of lone pairs and bond pairs on the central atom.
There are 3 lone pairs and 2 bond pairs.
This results in linear geometry.

Test: p-Block Elements - 2 - Question 21
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Aqueous solution of Na2S2O3 on reaction with Cl2 gives
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Aqueous Na2S2O3 on reaction with Cl2Cl2 produces NaHSO4

Test: p-Block Elements - 2 - Question 22
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Which noble gas is most abundant in atmosphere? 
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Argon

Argon is most abundant in composition of air percent by volume. It is in 0.934% in composition of air and is one of the major gas in the Earth's atmosphere.

Test: p-Block Elements - 2 - Question 23
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Aqueous solution of Na2S2O3 on reaction with Cl2 gives
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Sodium thiosulphate, Na2S2O3 gets oxidised by chlorine water

Na2S2O3 + 4Cl + 5H2O → 2NaHSO4 + 8HCl

Na2S2O3 get oxidised by FeCl3 into Na2S4O6

2Na2S2O3 + 2FeCl3 → Na2S4O6 + 2FeCl2 + 2NaCl

Further Na2S2O3 decomposes on treatment with dilute acids

Na2S2O3 + 2HCl → 2NaCl + SO2 + S + H2O.

Test: p-Block Elements - 2 - Question 24
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One of the following p-block elements has unusually low melting point
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Ga has very low melting point.

Test: p-Block Elements - 2 - Question 25
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In the manufacture of sulphuric acid by contact process Tyndall box is used to
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In the manufacture of sulphuric acid by contact process, Tyndall box is used to. remove impurities. Solution : Tyndall box is for testing the presence of dust particles.

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