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Test: Structure of Atom - 1 - NEET MCQ


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15 Questions MCQ Test Chemistry Class 11 - Test: Structure of Atom - 1

Test: Structure of Atom - 1 for NEET 2024 is part of Chemistry Class 11 preparation. The Test: Structure of Atom - 1 questions and answers have been prepared according to the NEET exam syllabus.The Test: Structure of Atom - 1 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Structure of Atom - 1 below.
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Test: Structure of Atom - 1 - Question 1

If the kinetic energy of an electron is increased four times, the wavelength of the de-Broglie wave associated with it would become

Detailed Solution for Test: Structure of Atom - 1 - Question 1

The wavelength λ is inversely proportional to the square root of kinetic energy. So if KE is increased 4 times, the wavelength becomes half.

λ∝1/√KE

Hence Option A is the answer.

Test: Structure of Atom - 1 - Question 2

Calculate the wavelength (in nanometer) associated with a proton moving at 1.0×103ms-1 (Mass of proton = 1.67×10-27kg and h = 6.63×10-34Js)

Detailed Solution for Test: Structure of Atom - 1 - Question 2

Given mp = 1.67×10-27kg
h = 6.63×10-34Js
v = 1.0×103ms-1

We know wavelength λ = h/mv
∴λ = 6.63×10-34/(1.67×10-27 × 1.0×103)
= 0.40×10-10
≈ 0.40nm

Hence, Option (B) is the Correct Answer.

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Test: Structure of Atom - 1 - Question 3

The frequency of light emitted for the transition n = 4 to n = 2 of He+ is equal to the transition in H atom corresponding to which of the following

Detailed Solution for Test: Structure of Atom - 1 - Question 3

Correct Answer is A.

Test: Structure of Atom - 1 - Question 4

The maximum number of atomic orbitals associated with a principal quantum number 5 is

Detailed Solution for Test: Structure of Atom - 1 - Question 4

Number of orbitals in a shell = n2 = (5)= 25

Test: Structure of Atom - 1 - Question 5

The radius of the second Bohr orbit for the hydrogen atom is :
(Planck’s constant, h = 6.262×10-34Js: Mass of electron = 9.1091×10-31kg; Charge of electron e = 1.60210×10-19C; permittivity of vacuum ε0 = 8.854185×10-12kg-1m-3A2)

Detailed Solution for Test: Structure of Atom - 1 - Question 5

Test: Structure of Atom - 1 - Question 6

Which model describes that there is no change in the energy of electrons as long as they keep revolving in the same energy level and atoms remains stable?

Detailed Solution for Test: Structure of Atom - 1 - Question 6

Bohr Model of atom:

  • An atom is made up of three particles: Electrons, neutrons and protons.
  • The protons and neutrons are located in a small nucleus at the centre of the atom.
  • The electrons revolve rapidly around the nucleus at the centre of the atom.
  • There is a limit to the number of electrons that each energy level can hold.
  • Each energy level is associated with a fixed amount of energy.
  • There is no change in the energy of electrons as long as they keep revolving in the same energy level.

Bohr explained the stability through the concept of revolution of electrons in different energy levels.


The change in the energy of an electron occurs when it jumps from lower to higher energy levels. When it gains energy, it excites from lower to higher and vice versa.
Thus energy is not lost and the atom remains stable.

Test: Structure of Atom - 1 - Question 7

The number of radial nodes for 3p orbital is:

Detailed Solution for Test: Structure of Atom - 1 - Question 7
  • Number of radial nodes = n - l – 1

where n = principal quantum number, l = azimuthal quantum number

  • For 3p orbital, n = 3 – 1 – 1 = 1
  • Number of radial nodes = 3 – 1 – 1 = 1. 
Test: Structure of Atom - 1 - Question 8

A sub-shell with n = 6 , l = 2 can accommodate a maximum of

Detailed Solution for Test: Structure of Atom - 1 - Question 8

n = 6, l = 2 means 6d → will have 5 orbitals. 

∴ max 10 electrons can be accommodate as each orbital can have maximum of 2 electrons. 

Test: Structure of Atom - 1 - Question 9

Thomson’s plum pudding model explained:

Detailed Solution for Test: Structure of Atom - 1 - Question 9
  • An atom consists of a positively charged sphere with electrons filled into it. The negative and positive charges present inside an atom are equal and as a whole, an atom is electrically neutral.
  • Thomson’s model of the atom as compared to plum pudding and watermelon.
  • He compared the red edible part of the watermelon to a positively charged sphere whereas the seeds of watermelon to negatively charged particles.

electrical world

Test: Structure of Atom - 1 - Question 10

Which of the following conclusions could not be derived from Rutherford’s α -particle scattering experiment?

Detailed Solution for Test: Structure of Atom - 1 - Question 10
  • Concept of electrons moving in a circular path of fixed energy called orbits was put forward by Bohr and not derived from Rutherford's scattering experiment.
  • Out of a large number of circular orbits theoretically possible around the nucleus.
  • The electron revolves only in those orbits which have a tired value of energy Hence, these orbits are called energy level or stationary states.
Test: Structure of Atom - 1 - Question 11

The charge on electron was determined by:

Detailed Solution for Test: Structure of Atom - 1 - Question 11

The charge on electrons was determined by Milliken by using an oil drop experiment.

Test: Structure of Atom - 1 - Question 12

The nature of positive rays depends on?

Detailed Solution for Test: Structure of Atom - 1 - Question 12
  • The nature of positive rays produced in a vacuum discharge tube depends upon the nature of the gas-filled.
  • The positive rays consist of positive ions obtained by removing one or more electrons from gas molecules.
Test: Structure of Atom - 1 - Question 13

The nucleus of a tritium atom, 3H, contains

Detailed Solution for Test: Structure of Atom - 1 - Question 13
  • Tritium (3H) is the only radioactive isotope of hydrogen.
  • The nucleus of a tritium atom consists of a proton and two neutrons.
Test: Structure of Atom - 1 - Question 14

The wavelengths of two photons are 2000 Å and 4000 Å respectively. What is the ratio of their energies?

Detailed Solution for Test: Structure of Atom - 1 - Question 14



= 4000/2000
= 2

Test: Structure of Atom - 1 - Question 15

The ion that is isoelectronic with CO is-

Detailed Solution for Test: Structure of Atom - 1 - Question 15

Isoelectronic species are the having same number of electrons.
Number of electrons in CO = 6 + 8 = 14
O2- = 16 + 1 = 17
N2+ = 14 - 1 = 13
O2+ = 1 6 - 1 = 15
CN- = 6 + 7 + 1 = 14
Hence, CO isoelectronic with CN ion.

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