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If log 2 = 0.3010 and log 3 = 0.4771, the value of log_{5} 512 is:
If log 2 = 0.3010 and log 3 = 0.4771, What is the value of log_{5}1024?
if log 2 = 0.30103 and log 3 = 0.4771, find the number of digits in (648)^{5}.
log(2^{128}) = 128log(2) = 128 × 0.30103 ≈ 38.4
ie, its characteristic = 38
Hence, number of digits in 2^{128} = 38+1 = 39
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