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All numbers are cubed,
(7)^{3} = 343
(1)^{3} = 1
(3)^{3} = 27
Similarly, (5)^{3} = 125.
(4 + 9 + 2) = (3 + 5 + 7) = (8 + 1 + 6)
Total in each case = 15.
(15 + 12)/9 = 3
and (44 + 28)/9 = 8
Therefore, (64 + 53)/9 = 13.
(30  24) x 8 = 48
and (23  12) x 8 = 88
Therefore, (92  86) x 8 = 48.
9 + (2)^{2} = 13
13 + (3)^{2} = 22
22 + (4)^{2} = 38.
93  (27 + 3) = 63
79  (38 + 4) = 37
Therefore, 67  (16 + X) = 42
X = 9
Putting the position of the letters in reverse order
P = 11, S = 8, V = 5 and Y = 2.
5 x 8 x 10 = 400
and 6 x 9 x 7 = 378
Therefore 5 x 7 x ? = 315
? = 9.
(16)^{2} = 256
Therefore, (2)^{2} = 4.
From I row, 1 + (1/2) = 3/2
From II row, 2 + (2/3) = 8/3
From III row, 3 + ? = 19/5
? = (19/5)  3
? = (4/5).
(4 x 8) + 1 = 33
(5 x 9) + 1 = 46
Similarly, (7 x 11) + 1 = 78.
(2)^{2} + (4)^{2} = 20
(3)^{2} + (9)^{2} = 90
Therefore, (1)^{2} + (5)^{2} = 26.
3 x 5 x 4 = 60
and 5 x 7 x 4 = 140
Therefore, 4 x 4 x ? = 96
? = (96/16) = 6.
(915  364) = 551
(789  543) = 246
(863  241) = 622.
(4 x 7) % 4 = 7
and (6 x 2) % 3 = 4
Therefore, (6 x 2) % 2 = 6.
(5 x 6 x 4)/10 = 12
and (6 x 7 x 5)/10 = 21
Therefore (4 x 8 x 10)/10 = 32.
13 + 15 = 28
36 + 54 = 90
Therefore, 45 + 63 = 108.
(3 x 4  8) = 4
(2 x 5  4) = 6
(4 x 5  9) = 11.
(3 x 3) + (5 x 6) = 39
and (4 x 4) + (5 x 7) = 51
Therefore, (3 x 4) + (5 x 5) = 37.
(2)^{2} = 4
(8)^{2} = 64
(5)^{2} = 25
(1)^{2} = 1.
(10 + 9 + 14 + 7)/2 = 20
and (11 + 16 + 10 + 13)/2 = 25
Therefore, (15 + ? + 12 + 10)/2 = 22
Hence 37 + ? = 44
? = 44  37
? = 7.
(5 x 6) + 2 = 32
(7 x 6) + 2 = 44
(7 x 5) + 2 = 37.
(5 + 3)/2 = 4
and (6 + 8)/2 = 7
Therefore (8 + 4)/2 = 6.
(1)^{2} + (5)^{2} + (4)^{2} + (3)^{2} = 51 x 10 = 510
and (3)^{2} + (4)^{2} + (6)^{2} + (2)^{2} = 65 x 10 = 650
Similarly (0)^{2} + (1)^{2} + (2)^{2} + (8)^{2} = 69 x 10 = 690.
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