SBI PO Prelims Mock Test - 4 - Bank Exams MCQ

The correct answer is option 4 i.e. A-B and C-D.
Key Points

We can look into the sentence in the following way:

The climate crisis has (A) ________ the traditional narrative of such “normality” like (B) _________ fires in current eco-fiction, (C) _________ such events as (D) ________ and beyond the limits of the (E) ________ of ecosystems.

• E has the correct word in both grammatical and contextual sense.
• A needs a verb that would signify how the traditional narrative has been affected. Thus, ‘changed’ is the correct word for it. So, A-B. Putting ‘forest’ before fires also makes contextual sense as it defines the type of fires under discussion.
• Again, C needs a verb while D needs an adjective. Thus, C and D should interchange. ‘Exacerbating’ is a verb meaning make (a problem, bad situation, or negative feeling) worse. ’Disastrous’ is an adjective meaning causing great damage.
• Thus, the correct answer is option 4 – A-B and C-D.

Correct Sentence - The climate crisis has (B) changed the traditional narrative of such “normality” like (A) forest fires in current eco-fiction, (D) exacerbating such events as (C) disastrous and beyond the limits of the (E) resilience of ecosystems.

The correct answer is DEBAC.

Key Points

• D is the part that establishes the subject of the matter i.e. 'Money'. Hence, it'll be the first part after rearrangement.
• Part E talks about authority which is owned by the people with money as mentioned in D. Hence, E follows D.
• Part B talks about 'earning' which is done by people. Hence, B follows E.
• Part A talks about .powers which are usually misused as mentioned in B. So, A follows B.
• Part C talks about black money which is the money earned by misusing one's power. Hence, C follows A.

Correct rearrangement of segments is: Money that people having authority earn misusing their powers is black money.

Hint

• While solving jumbles, one must first look for any independent sentences/segments or the option which establishes the subject matter.
• Then, one must look for connections between the sentences/segments.
• Some sentences/segments might have some concluding notion. So those options will be always at the end.

The correct answer is 2.

Key Points

• Since the second sentence is fixed therefore in order to derive the third sentence of the correct arrangement, it is imperative to know the subject dealt in the first two sentences.
• The second sentence talks about how education is essential in our lives. From this, we get to know that the passage is about the importance of education.
• So the first sentence must talk about the importance of education. This part of the passage is provided by the sentence F which therefore forms the first sentence after rearrangement of the sentences.
• The passage now talks about what are the different purposes of education and education enhances our lives.
• This part of the passage is provided by the sentence A which therefore forms the third sentence after rearrangement of the sentences.

The correct answer is 5.

Key Points

• Since the second sentence is fixed therefore in order to derive the fifth sentence of the correct arrangement, it is imperative to know the subject dealt in the first four sentences. The second sentence talks about how education is essential in our lives. From this, we get to know that the passage is about the importance of education.
• So the first sentence must talk about the importance of education. This part of the passage is provided by the sentence F which therefore forms the first sentence after rearrangement of the sentences.
• The passage now talks about what are the different purposes of education and education enhances our lives. This part of the passage is provided by the sentence A which therefore forms the third sentence after rearrangement of the sentences.
• Now the passage gives further details by saying that how easy it is now to get education. This part of the passage is provided by the sentence E which therefore forms the fourth sentence after rearrangement of the sentences.
• The passage now moves on to the point where it says that how today's education removes the differences between the social divisions. This part of the passage is provided by the sentence D which therefore forms the fifth sentence after rearrangement of the sentences.

The correct answer is 4.

Key Points

• Since the second sentence is fixed therefore in order to derive the fifth sentence of the correct arrangement, it is imperative to know the subject dealt in the first four sentences. The second sentence talks about how education is essential in our lives. From this, we get to know that the passage is about the importance of education.
• So the first sentence must talk about the importance of education. This part of the passage is provided by the sentence F which therefore forms the first sentence after rearrangement of the sentences.
• The passage now talks about what are the different purposes of education and education enhances our lives. This part of the passage is provided by the sentence A which therefore forms the third sentence after rearrangement of the sentences.
• Now the passage gives further details by saying that how easy it is now to get education. This part of the passage is provided by the sentence E which therefore forms the fourth sentence after rearrangement of the sentences.
• The passage now moves on to the point where it says that how today's education removes the differences between the social divisions. This part of the passage is provided by the sentence D which therefore forms the fifth sentence after rearrangement of the sentences.
• This is the concluding part of the passage which says that the abilities of education in understanding the human rights and liberties. his part of the passage is provided by the sentence C which therefore forms the fifth sentence after rearrangement of the sentences.
• Thus the correct rearrangement of the sentences is: FBAEDC

The correct answer is '​Foundation.'

Key Points

• The given sentence is talking about something that is the reason behind the two-decade-long relationship.
• Therefore, the most appropriate word to be filled in the blank is 'Foundation'.
• Also, the use of the word ''laid'' in the sentence indicates the use of the word 'foundation' in the blank.
• The word 'Foundation' means The idea, principle, or fact on which something is based.
  • Example: The foundation of true joy is in the conscience.

Hence, the correct answer is option 4.

Complete Sentence: It laid the foundation of the relationship for two decades.

Additional Information

• Let us explore the other options:
  • Intention means A plan or purpose.
  • Diversion means The act of changing the direction or purpose of something.
  • Absorption means The state of being engrossed in something.

The correct answer is Option 3) i.e. Only A is correct.

Key Points

• Sentence A) The oldest canard in the book is the one about how getting the first big win is the hardest bit, and after that, they just fall into your lap like autumn leaves.
  • Here canard is correctly used. 'Canard' means a false or unfounded report or story
• Sentence B) The preacher warned that those who were interested only in canard pursuits would not see the kingdom of heaven
  • Here the use of canard makes no sense. 'Carnal' should be there in place of 'Canard'. Carnal means relating to or given to crude bodily pleasures and appetites
• Sentence C) The soup is notably holistic as if refusing to take sides, neither frankly canard nor purely herbaceous but somewhere more intriguingly in between.
  • Here the use of canard makes no sense. 'Carnal' should be there in place of 'Canard'. Carnal means relating to or given to crude bodily pleasures and appetites

Therefore, the correct answer is 'Only A is correct'.

The correct answer is option 3), i.e. 'Depends on'.

Key Points
Reading the above sentence we find that:

• The preposition 'with' is used and it is incorrect.
• 'On' should be used after the verb 'depend'.
  • Example: You cannot depend on her.
• 'Depend on someone/something' is a phrasal verb which means 'to need the help of someone or something'.
• Therefore, 'on' should replace 'with'.

Hence the correct answer is option 3.

Important Points

• A preposition shows the relationship of a noun or pronoun to another word.
  • Example: He is sitting on the chair. I was standing before the judge.
• A phrasal verb is an idiomatic phrase consisting of a verb and another element, typically either an adverb, as in break down or a preposition.
  • Example: see to, or a combination of both, such as look down on.

The correct sentence would be: "The country depends on its seas for food and tourism."

The correct answer is ‘A-B and C-D’.

Key Points

• The combination of A-B i.e. studious and first makes sense because ‘first’ should be placed before ‘rank holder’ since 'first' is used as a Definite Numeral Adjective giving us information about the position of Sam in the class.
• The combination of C-D i.e. musician and dream make sense because despite being so much into studies Sam adores the dream of becoming a musician and sings for A.R. Rahman.
• Hence, Option 3 is the correct answer.

So, the correct sentence is: “Sam is the first rank holder of the class. He is very studious and dedicates twelve hours a day to prepare his lessons. But he also cherishes the dream of becoming a musician and sing for A.R. Rahman.” 

Additional Infromation

• Adjectives that tells us ‘how much’ or ‘how many’ of something that is indicated are called Adjectives of Number.
• There are three types of Adjectives of Number:
• Definite Numeral Adjectives - Adjectives that indicate an exact number. There are two types of Definite Numeral Adjectives:
  • Cardinals- When the numbers indicated are used in amounts.
    • For example- Two black horses are sleeping in the stable.
  • Ordinals- When the numbers indicated are used as an order in a queue.
    • For example- The second horse was the black horse.
• Indefinite Numeral Adjectives – Adjectives that do not tell us an exact number.
  • For example- There are some rotten potatoes in the basket.
• Distributive Numeral Adjectives – Refers to individual things in a group.
  • For example- Each horse that ran up the field had a black mane.

The correct answer is 'lambaste.'

Key Points

• Let us know the meaning of the correct given option:
  • Lambaste - to criticize someone or something harshly. (किसी की या किसी चीज की कठोर आलोचना करना)
• Filling this word in the blanks, the sentences will read as follows:
  • A: The rude shopper continued to lambaste the salesgirl for the slow work pace.
    • The above sentence is talking about the rude behavior of the shopper towards the salesgirl, hence, 'lambaste' is the right choice.
  • B: My parents always find some small error to lambaste me over.
    • The above sentence is talking about always finding errors in someone, hence, 'lambaste' is the right choice.
  • C: Harsh party leaders continued to lambaste the plan for healthcare reform.
    • The above sentence is talking about criticizing the healthcare plan by the party leaders, hence, 'lambaste' is the right choice.

Hence, the correct answer is option 2.

Additional Information

• Let us know the meaning of the other given words:
  • Sanction - official permission to do or change something. (आधिकारिक अनुमति, मंज़ूरी)
  • Acclaim - to express a very high opinion of something or somebody. (किसी व्‍यक्ति या वस्‍तु के प्रति आदर या प्रशंसा प्रकट करना; अभिनंदन करना)
  • Endorse - to declare one's public approval or support. (किसी की सार्वजनिक स्वीकृति या समर्थन की घोषणा करना)
  • Extol - to praise enthusiastically. (उत्साहपूर्वक प्रशंसा करना)

Given:

A container contains 6 white, 8 blue and 4 red marbles. Three marbles are drawn at random from the container

Concept used:

The classical definition of probability

Formula used:

Probability = Favorable Outcome / Total Outcome

P(E) = n(E)/n(S)

ⁿC_r = n! / r!(n - r)!

ⁿC_r = ⁿC_{(n - r)}

Calculation:

Total number of marbles is 6 + 8 + 4 = 18

Let S be the sample space

n(S) = Total number of ways of drawing 3 marbles out of 18 = ¹⁸C₃

Let E = Event of drawing 3 marbles, all of them are blue

n(E) = Number of ways of drawing 3 marbles, all of them are blue

Number of ways of drawing 3 marbles from the total 8 = ⁸C₃

P(E) = n(E) / n(S)

⇒ ⁸C₃/¹⁸C₃

⇒ {(8 × 7 × 6)/(1 × 2 × 3)}/{(18 × 17 × 16)/(1 × 2 × 3)}

⇒ 56/816

⇒ 7/102

∴ The probability that all of them are blue is 7/102.

Let the total number of 'Full face' helmets sold by the company in all given five months together = 100%
ATQ, 30% + 375 + 10% + 25% + 20% = 100%
⇒ 15% = 375
⇒ 1% = 25
The total number of 'Full face' helmets sold by the company in all given five months together = 2500
Putting all the given information in a table form we get

Total number of 'Full face' helmets sold in May and July together = 750 + 250 = 1000
Required% = (1000/500) × 100 = 200%
Hence, the correct answer is 200%.

Correct answer is Option 2.

For college P,
Total percentage of students studying BCA and DCA in college P = 16.67% + 33.33% = 50%
⇒ Total percentage of students studying MCA in college P = 100% - 50% = 50%
It is given that 243 students have been studying MCA from college P.
⇒ 50% = 243
⇒ 100% = 486
⇒ 16.67% = 486 × (1/6) = 81
⇒ 33.33% = 486 × (1/3) = 162
Total number of students studying BCA in college P = 16.67% = 81
Total number of students studying DCA in college P = 33.33% = 162

Now for college Q,
Total percentage of students studying BCA and DCA in college Q = 30% + 45% = 75%
⇒ Total percentage of students studying MCA in college Q = 100% - 75% = 25%
It is given that 960 students have been studying MCA from college Q.
⇒ 25% = 960
⇒ 100% = 960 × 4 = 3840
⇒ 30% = 3840 × (30/100) = 1152
⇒ 45% = 3840 × (45/100) = 1728
Total number of students studying BCA in college Q = 30% = 1152
Total number of students studying DCA in college Q = 45% = 1728

Now for college R,
Total percentage of students studying BCA and DCA in college R = 25% + 25% = 50%
⇒ Total percentage of students studying MCA in college R = 100% - 50% = 50%
It is given that 294 students have been studying MCA from college R.
⇒ 50% = 294
⇒ 100% = 294 × 2 = 588
⇒ 25% = 588 × (25/100) = 147
Total number of students studying BCA in college R = 25% = 147
Total number of students studying DCA in college R = 25% = 147

Now for college S,
Total percentage of students studying BCA and DCA in college S = 35% + 55% = 90%
⇒ Total percentage of students studying MCA in college S = 100% - 90% = 10%
It is given that 500 students have been studying MCA from college S.
⇒ 10% = 500
⇒ 1% = 50
⇒ 35% = 35 × 50 = 1750
⇒ 55% = 55 × 50 = 2750
Total number of students studying BCA in college S = 35% = 1750
Total number of students studying DCA in college S = 55% = 2750

Now for college T,
Total percentage of students studying BCA and DCA in college T = 40% + 30% = 70%
⇒ Total percentage of students studying MCA in college T = 100% - 70% = 30%
It is given that 300 students have been studying MCA from college T.
⇒ 30% = 300
⇒ 1% = 10
⇒ 40% = 10 × 40 = 400
⇒ 30% = 300
Total number of students studying BCA in college T = 40% = 400
Total number of students studying DCA in college T = 30% = 300

Total number of students studying DCA in college Q = 1728
Total number of girls studying DCA in college Q = 988
⇒ Total number of boys studying DCA in college Q = 1728 - 988 = 740
Total number of students studying DCA in college P = 162
Girls : Boys = 3 : 6
⇒ Total number of boys studying DCA in college P = 162 × (6/9) = 108
So, total number of boys studying DCA from college P and Q = 108 + 740 = 848

Given:
Total profit = Rs. 18500
X = 1.5 × Y
Z = 2.5 × Y

Formula used:
Profit earned in Rs = Profit earned in % × investment

Calculation:
Calculating ratio of profit share
⇒ (1.5Y × 10) : (Y × 12) : (2.5Y × 4)
⇒ 15Y : 12Y : 10Y
⇒ X : Y : Z = 15 : 12 : 10
⇒ Y’s share in profit = 12 × 18500/ 37
⇒ Y’s share in profit = 6000
⇒ Z’s share in profit = 10 × 18500/ 37
⇒ Z’s share in profit = 5000
⇒ required difference = 1000
∴ required difference is 1000

Considering the given series,
243, 512, 729, 1000, 1331, 1728
The logic of above series can be explained as,
243 ≠ 7³
512 = 8³
729 = 9³
1000 = 10³
1331 = 11³
1728 = 12³
∴ Wrong Number is 243.

Considering the given series
6, 12, 42, 231, 1848, 20326, 294756
The logic of the given series can be explained as
6 × 2 = 12
12 × 3.5 = 42
42 × 5.5 = 231
231 × 8 =1848
1848 × 11 = 20328
20328 × 14.5 = 294756
∴ corrected number is 20328 which take place for correction.

Given:
50 paise coins = 10
Probability of chossing one one rupee coin = 6 / 11
Two rupee coins = 8

Formula used:
Probability = Favorable events / Total events

Calculation:
6 / 11 = X / (10 + X)
⇒ 60 + 6X = 11X
⇒ 5X = 60
⇒ X = 12
⇒ Total events = 12 + 10 + 8
⇒ Total events = 30
⇒ Favorable events = 8
⇒ New probability = 8 / 30
∴ Probability of choosing one two rupee coin from the bag is 4 / 15

Hint
Find the unknown X and then solve the remaining probem

Given:
In a race of 2.7 km, 'A' beats 'B' by 200 meters.
In a race of 3.3 km, 'C' beats 'D' by 300 meters.
The speed of 'B' and 'D' is same.

Calculation:
Let the speeds of 'A', 'B', 'C', and 'D' be a, b, c, and d respectively.
In a race of 2.7 km = 2700 meters.
⇒ 2700/a = (2700 - 200)/b
⇒ a/b = 27/25
In a race of 3.3 km = 3300 meters.
⇒ 3300/c = (3300 - 300)/d
⇒ c/d = 11/10
Let a = 27x, b = 25x, c = 11y and d = 10y
ATQ, 25x = 10y
⇒ x/y = 2/5
Let x = 2p and y = 5p
Therefore, a = 54p, b = 50p, c = 55p, d = 50p
Speed of 'C' > Speed of 'A'
In a race of 4.4 km = 4400 meters.
Time taken by 'C' to finish 4400 meters race = 4400/55p = 80/p
Distance covered by 'A' in the same time = (80/p) × 54p = 4320 meters
'C' beats 'A' by = 4400 - 4320 = 80 meters
Hence, the correct answer is 'C' beats 'A' by 80 meters.

Given:
Bhaumik + Mahima + Kandarp = Rs. 150,000
Mahima’s investment = 1.2 × bhaumik’s investment
Kandarp’ investment = 0.9 × 1.2 × bhaumik’s investment
Profit earned = 16.4%

Formula used:
Profit earned in Rs = Profit earned in % × investment

Calculation:
Let, investment by bhaumik be X
⇒ Mahima’s investment = 1.2X
⇒ Kandarp’s investment = 1.08X
⇒ Ratio of profit share = X : 1.2X : 1.08X
⇒ Bhaumik : Mahima : Kandarp = 1 : 1.2 : 1.08
⇒ Bhaumik : Mahima : Kandarp = 25 : 30 : 27
⇒ Total profit earned = 150,000 × 0.164
⇒ Total profit earned = 24600
⇒ Profit earned by mahima and kandarp = 24600 × (30/ 82) + (24600 × 27/ 82)
⇒ Profit earned by mahima and kandarp = Rs. 24600 (30 + 27)/ 82
∴ Profit earned by mahima and kandarp is Rs 17,100

Concept:
This type of question can be solved by the help of BODMAS
Follow BODMAS rule to solve this question, as per the order given below.
Step- 1: Parts of an equation enclosed in ‘Brackets’ must be solved first and, in the bracket,
Step- 1: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,
Step- 3: Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated
Step- 4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated

Calculation:
⇒ √ 576 × (24/12) + 144 – 360 + (1728/√ 576) = y
⇒ √ 576 × (2) + 144 – 360 + (1728/24) = y
⇒ √ 576 × 2 + 144 – 360 + 72 = y
⇒ 24 × 2 + 144 – 360 + 72 = y
⇒ 48 + 144 – 360 + 72 = y
⇒ 264 – 360 = y
⇒ -96 = y
∴ y = -96 will be answer.

Fruits: apple, orange, grapes, banana, pineapple, peach, kiwi, and guava.
Number of fruits: 5, 4, 3, 2, 20, 39, 36 and 25.
(1) There are three boxes above oranges but below apples which are placed in an even-numbered place.

(2) There are five boxes between the box containing 5 pieces and the one containing 3 pineapples which are not placed on the bottommost position.

(3) Number of apples is a perfect square and only grapes are more in number than apples, therefore case 1 (a) eliminates and grapes are 39 in number implies apples must be 36 in number.
(4) There are at least three boxes between the box containing banana and peach.
(5) Bananas are placed three boxes above the one containing guava.
(6) Peaches are placed just above the box containing 20 fruits.

As peaches are placed just above the box containing 20 fruits. Case 1(b) and case 2 (a) eliminates here. But we need space for 39 grapes therefore case 2 (b) (ii) eliminates here.

(7) Number of banana are more than guava but not more than peaches, as 2, 4 and 25 left only, therefore, peaches are 25, bananas are 4 and guava are 2 in number.
Therefore the final arrangement is:

Hence, three boxes are below Grapes.

Fruits: apple, orange, grapes, banana, pineapple, peach, kiwi, and guava.
Number of fruits: 5, 4, 3, 2, 20, 39, 36 and 25.
(1) There are three boxes above oranges but below apples which are placed in an even-numbered place.

(2) There are five boxes between the box containing 5 pieces and the one containing 3 pineapples which are not placed on the bottommost position.

(3) Number of apples is a perfect square and only grapes are more in number than apples, therefore case 1 (a) eliminates and grapes are 39 in number implies apples must be 36 in number.
(4) There are at least three boxes between the box containing banana and peach.
(5) Bananas are placed three boxes above the one containing guava.
(6) Peaches are placed just above the box containing 20 fruits.

As peaches are placed just above the box containing 20 fruits. Case 1(b) and case 2 (a) eliminates here. But we need space for 39 grapes therefore case 2 (b) (ii) eliminates here.

(7) Number of banana are more than guava but not more than peaches, as 2, 4 and 25 left only, therefore, peaches are 25, bananas are 4 and guava are 2 in number.
Therefore the final arrangement is:

Hence, grapes are two boxes below the box containing pineapples is false.

Fruits: apple, orange, grapes, banana, pineapple, peach, kiwi, and guava.
Number of fruits: 5, 4, 3, 2, 20, 39, 36 and 25.
(1) There are three boxes above oranges but below apples which are placed in an even-numbered place.

(2) There are five boxes between the box containing 5 pieces and the one containing 3 pineapples which are not placed on the bottommost position.

(3) Number of apples is a perfect square and only grapes are more in number than apples, therefore case 1 (a) eliminates and grapes are 39 in number implies apples must be 36 in number.
(4) There are at least three boxes between the box containing banana and peach.
(5) Bananas are placed three boxes above the one containing guava.
(6) Peaches are placed just above the box containing 20 fruits.

As peaches are placed just above the box containing 20 fruits. Case 1(b) and case 2 (a) eliminates here. But we need space for 39 grapes therefore case 2 (b) (ii) eliminates here.

(7) Number of banana are more than guava but not more than peaches, as 2, 4 and 25 left only, therefore, peaches are 25, bananas are 4 and guava are 2 in number.
Therefore the final arrangement is:

Hence, three boxes are there between pineapple and peaches.

Given: 11 persons belonging to 3 different countries travel to Germany.
Based on the given conditions, we get the following possibilities-
1. X doesn’t belong to Portugal or Croatia. Both O and P belong to Portugal. N doesn’t belong to Spain or Portugal. From these, we get-

2. C belongs to the same country as N. I belongs to the same country as X. From these, we get-

3. T and S belong to the same country. T and O belong to the same country. M belongs to the same country as I. B doesn’t belong to Croatia or Portugal. R and C belong to the same country. From these, we get the final table as follows-

From the final table, we see that M belongs to Spain.
Hence, M belongs to Spain.

Given: 11 persons belonging to 3 different countries travel to Germany.
Based on the given conditions, we get the following possibilities-
1. X doesn’t belong to Portugal or Croatia. Both O and P belong to Portugal. N doesn’t belong to Spain or Portugal. From these, we get-

2. C belongs to the same country as N. I belongs to the same country as X. From these, we get-

3. T and S belong to the same country. T and O belong to the same country. M belongs to the same country as I. B doesn’t belong to Croatia or Portugal. R and C belong to the same country. From these, we get the final table as follows-

From the final table, we see that B belongs to Spain.
Hence, B doesn’t belong to Portugal.

Given: 11 persons belonging to 3 different countries travel to Germany.
Based on the given conditions, we get the following possibilities-
1. X doesn’t belong to Portugal or Croatia. Both O and P belong to Portugal. N doesn’t belong to Spain or Portugal. From these, we get-

2. C belongs to the same country as N. I belongs to the same country as X. From these, we get-

3. T and S belong to the same country. T and O belong to the same country. M belongs to the same country as I. B doesn’t belong to Croatia or Portugal. R and C belong to the same country. From these, we get the final table as follows-

From the final table, we see that 4 persons belong to Spain and 3 persons belong to Croatia.
Hence, 7 persons belong to Spain and Croatia in total.

Eight employees - I, J, K, L, M, N, O, and P
Designations - Executive Director, Director, Senior Manager, Manager, Team Leader, Senior Software Engineer, Software Engineer, and Associate Software Engineer
1) There are four designations between M and O, who is junior to at least four persons.

2) K is immediately senior to I.
3) There are three designations between P and N.
4) I is senior to at least four persons in the company.
As the above conditions are not satisfied in case 3, it will get canceled.

5) J is not the Software Engineer.
6) Neither P nor N is the Executive Director of the company.
As the above condition is not satisfied in case 2, it will get canceled.

Final Arrangement:

Hence, M is the Executive Director of the company.

We have drawn the figure according to the information given in the question,
A is 5 km north of B, B is 3 km west of C.
D is 2 km west of B.

E is 5 km north of C, F is 4 km south of D.

G is 2 km east of F, H is 3 km east of G.

From the figure it is clear that the distance between G and H = 3 km.

Given statements: W < X, Y = Z, V < U, X > Z, T ≥ Y, W > U, P = V
By combining: T ≥ Y = Z < X > W > U > V = P

Conclusions:
I. T > X → False (as T ≥ Y = Z < X → T ≥ Z < X. Thus, no clear relation between T and X can be obtained because of presence of opposite sign between T and X)
II. W > P → True (as W > U > V = P → W > P)
III. Y = P → False (as Y = Z < X > W > U > V = P → Y < X > W > U > P. Thus, no clear relation between Y and P can be obtained because of presence of opposite sign between Y and P.)
Hence, Only conclusion II is True.

The least possible Venn diagram for the given statements is as follows: