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Test: Elasticity - SSC CGL MCQ


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15 Questions MCQ Test General Awareness for SSC CGL - Test: Elasticity

Test: Elasticity for SSC CGL 2024 is part of General Awareness for SSC CGL preparation. The Test: Elasticity questions and answers have been prepared according to the SSC CGL exam syllabus.The Test: Elasticity MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Elasticity below.
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Test: Elasticity - Question 1

What is the SI unit of elasticity?

Detailed Solution for Test: Elasticity - Question 1
The SI unit of elasticity is the pascal (Pa), which measures pressure and stress.
Test: Elasticity - Question 2

If a material experiences a longitudinal stress of 1000 N/m² and has a cross-sectional area of 5 m², what is the applied force?

Detailed Solution for Test: Elasticity - Question 2
Using the formula σ = F/A, rearrange to find F = σ × A. Therefore, F = 1000 N/m² × 5 m² = 5000 N.
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Test: Elasticity - Question 3

What type of stress is responsible for the change in volume of a material due to pressure changes?

Detailed Solution for Test: Elasticity - Question 3
Volume stress, or bulk stress, arises from changes in the volume of a material due to pressure changes.
Test: Elasticity - Question 4
How is shear stress (τ) calculated?
Detailed Solution for Test: Elasticity - Question 4
Shear stress is calculated by τ = F/A, where F is the applied force and A is the area over which the force acts.
Test: Elasticity - Question 5
What is the formula for longitudinal strain (∈)?
Detailed Solution for Test: Elasticity - Question 5
Longitudinal strain is calculated using the formula ∈ = ΔL/L0, where ΔL is the change in length and L0 is the original length.
Test: Elasticity - Question 6
A material has a Young’s modulus (E) of 200 GPa and experiences a stress (σ) of 50 MPa. What is the strain (∈)?
Detailed Solution for Test: Elasticity - Question 6
Using the formula E = σ/∈, rearrange to find ∈ = σ/E. Convert units to match (200 GPa = 200,000 MPa), so ∈ = 50 MPa / 200,000 MPa = 0.00025.
Test: Elasticity - Question 7
Which type of strain measures the distortion of a material’s cross-sectional elements due to shear stress?
Detailed Solution for Test: Elasticity - Question 7
Tangential strain, or shear strain, measures the distortion of a material’s cross-sectional elements due to shear stress.
Test: Elasticity - Question 8
How does elastic hysteresis affect a material during cyclic loading and unloading?
Detailed Solution for Test: Elasticity - Question 8
Elastic hysteresis results in energy loss during cyclic loading and unloading, even if the material remains within its elastic deformation range.
Test: Elasticity - Question 9
If a fluid is subjected to a pressure of 1500 Pa, what is the volume stress (σbulk) in the fluid?
Detailed Solution for Test: Elasticity - Question 9
For fluids, the volume stress (σbulk) is equal to -P, so σbulk = -1500 Pa.
Test: Elasticity - Question 10
What does Poisson’s ratio (ν) describe?
Detailed Solution for Test: Elasticity - Question 10
Poisson’s ratio describes the ratio of lateral strain to axial strain when a material is subjected to axial stress.
Test: Elasticity - Question 11
A material has a shear modulus (G) of 80 GPa and a shear stress (τ) of 16 MPa. What is the shear strain (γ)?
Detailed Solution for Test: Elasticity - Question 11
Using the formula G = τ/γ, rearrange to find γ = τ/G. Convert units to match (80 GPa = 80,000 MPa), so γ = 16 MPa / 80,000 MPa = 0.0002.
Test: Elasticity - Question 12
In a material with a bulk modulus (K) of 100 GPa, if the volume strain (∈V) is 0.001, what is the pressure applied to the material?
Detailed Solution for Test: Elasticity - Question 12
Using the formula K = -P/∈V, rearrange to find P = -K × ∈V. Convert units to match (100 GPa = 100,000 MPa), so P = 100,000 MPa × 0.001 = 100 MPa.
Test: Elasticity - Question 13
A material undergoes a change in length of 0.02 m when subjected to an axial force. If the original length of the material is 2 m, what is the longitudinal strain?
Detailed Solution for Test: Elasticity - Question 13
Using the formula ∈ = ΔL/L0, where ΔL = 0.02 m and L0 = 2 m, the longitudinal strain ∈ = 0.02 / 2 = 0.01.
Test: Elasticity - Question 14
How does Young’s modulus (E) relate to a material’s stiffness?
Detailed Solution for Test: Elasticity - Question 14
Young’s modulus quantifies a material’s stiffness; a higher E indicates a higher resistance to elastic deformation, thus higher stiffness.
Test: Elasticity - Question 15
What does the stress concentration factor (Kt) account for in materials?
Detailed Solution for Test: Elasticity - Question 15
The stress concentration factor (Kt) accounts for the impact of geometric discontinuities, like notches or holes, on stress distribution in materials.
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