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Class 8 Exam  >  Class 8 Tests  >  Mathematics (Maths) Class 8  >  Test: Mensuration- 2 - Class 8 MCQ

Test: Mensuration- 2 - Class 8 MCQ


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10 Questions MCQ Test Mathematics (Maths) Class 8 - Test: Mensuration- 2

Test: Mensuration- 2 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation. The Test: Mensuration- 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Mensuration- 2 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mensuration- 2 below.
Solutions of Test: Mensuration- 2 questions in English are available as part of our Mathematics (Maths) Class 8 for Class 8 & Test: Mensuration- 2 solutions in Hindi for Mathematics (Maths) Class 8 course. Download more important topics, notes, lectures and mock test series for Class 8 Exam by signing up for free. Attempt Test: Mensuration- 2 | 10 questions in 10 minutes | Mock test for Class 8 preparation | Free important questions MCQ to study Mathematics (Maths) Class 8 for Class 8 Exam | Download free PDF with solutions
Test: Mensuration- 2 - Question 1
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Find the volume of a cuboid whose length is 8 cm, breadth 6 cm and height 3.5 cm. 

Detailed Solution for Test: Mensuration- 2 - Question 1
(8×6)×3.5=48×3.5= 168.00cm cube.
Test: Mensuration- 2 - Question 2
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Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm. 

Detailed Solution for Test: Mensuration- 2 - Question 2
Volume of cubiod =l×b×h
=8×3×5
=120cm3 .
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Test: Mensuration- 2 - Question 3
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Find the perimeter of the a square with side 4cm.

Detailed Solution for Test: Mensuration- 2 - Question 3
Because the perimeter of square is 4×side
so, 4×4=16
Test: Mensuration- 2 - Question 4
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The area of the circle is 2464 cm2 and the ratio of the breadth of the rectangle to radius of the circle is 6:7. If the circumference of the circle is equal to the perimeter of the rectangle, then what is the area of the rectangle.
Detailed Solution for Test: Mensuration- 2 - Question 4

Area of the circle=πr2

2464 = 22/7 * r2

Radius of the circle=28 cm

Circumference of the circle=2 * π* r =2 * 22/7 * 28 

= 176 cm

Breadth of the rectangle=6/7 * 28=24 cm

Perimeter of the rectangle=2 * (l + b)

176 = 2 * (l + 24)

Length of the rectangle = 64 cm

Area of the rectangle = l * b = 24 * 64 = 1536 cm2 

Test: Mensuration- 2 - Question 5
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A rectangular paper of width 7 cm is rolled along its width and a cylinder of radius 20 cm is formed. Find the volume of the cylinder. 
Detailed Solution for Test: Mensuration- 2 - Question 5
Given  : A rectangular paper of width 14 cm is rolled along its width to form a cylinder.

Height of cylinder =  h  =  7 cm = width of the rectangular paper

And
Radius of cylinder ( Given ) =  r  = 20 cm

And
we know Volume of cylinder  = π r^2 h , So

Volume of our given cylinder = 22/7 x 20 x 20 x 7  = 8800 cm^3    
Test: Mensuration- 2 - Question 6
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Top surface of a raised platform is in the shape of regular octagon as shown in the figure. Find the area of the octagonal surface.
Detailed Solution for Test: Mensuration- 2 - Question 6

Test: Mensuration- 2 - Question 7
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The diagonal of a quadrilateral shaped field is 24 m and perpendicular dropped on it from the remaining opposite vertices are 6 m and 12 m. Find the area of the field.
Detailed Solution for Test: Mensuration- 2 - Question 7

area=1/2×d×(h1+h2)
=1/2×24×(12+6)
=12(18)
=216 m2

Test: Mensuration- 2 - Question 8
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If the parallel sides of a parallelogram are 2 cm apart and their sum is 10 cm then its area is:
Detailed Solution for Test: Mensuration- 2 - Question 8

use formula:1/2(sum of of parallel sides)(distance between them)

Test: Mensuration- 2 - Question 9
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If the edge of a cube is 1 cm then which of the following is its total surface area?
Detailed Solution for Test: Mensuration- 2 - Question 9
Total surface area of cube is 6*length^2
=6×1^2
=6×1
=6 cm2
Test: Mensuration- 2 - Question 10
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Find the area of a triangle whose base is 4 cm and altitude is 6 cm.
Detailed Solution for Test: Mensuration- 2 - Question 10

We know that area of triangle is equals to 1/2 base × altitude.
Here, base = 4 cm and altitude = 6 cm.
So, area = 1/2 × 4 × 6= 24 /2= 12 cm2.

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