Test: Simplification- 6 - CUET Commerce MCQ

(√3 + 1)² = ? + √12
3 + 2√3 + 1 = ? + 2√3 = 4

621 ÷ 27 * 2 – 37 = √?
23 * 2 – 37 = √? = 9
x = 81

√? + 43 = √19881
√? = 141 – 43
x = 9604

325 – (12)² + 75 = (?)² – 68
325 – 144 + 75 + 68 = (?)²
(?)² = 324
x = 18

(62.5 * 14 * 5) ÷ 25 + 41 = (?)³
4375 ÷ 25 + 41 = (?)³
(?)³ = 216
x = 6

48356 + 5412 – 736 = x * 40
53032 = x * 40
x = 1325.8

538.24 – 193.42 + 343.91 = 882.15 – 193.42 = 688.73

3/8 of 4/5 of 5/6 of 7450 = 3/8 * 4/5 * 5/6 * 7450
= 7450/4 = 1862.5

44616 ÷ √? = 143 * 6
√?  = 2704

45% of 300 + √x = 56% of 750 – 10% of 350
135 + √x = 420 – 35 ⇒ √x  = 250
x = 62500

[(?)^11/7/50] = [20/(?)^10/7] x³ = 1000
x = 10

√x = 79296 / 112*12
√x = 59
x = 3481

1637 + 1832 = (45)² + (?)²
(?)² = 3469 – 2025 = 1444 => x = 38

13498 + 8932 – 1159 = ? * 89
x * 89 = 21271 => x = 239

(37685 + 29452 – 41897) ÷ 250
= 25240 ÷ 250 = 100.96

x² = 75 * 147 => x = 105

32.4 * 8 * 5 + 4 = 1300
1300 ÷ 26 + 14 = 64 => x = 8

√(12 * 145 ÷ 6 + 34)
= √(290 + 34)
= 18

5670 ÷ (28*13.5)
= 5670 ÷ 378 = 15

We have:

6156 ÷ √(?) × 53 = 4028

Step 1: Rearrange to isolate √(?).

6156 × 53
----------- = √(?)
4028

Step 2: Compute the numerator.

6156 × 53 = 6156 × (50 + 3) = 6156 × 50 + 6156 × 3
= 307800 + 18468 = 326268

So:

√(?) = 326268 / 4028

Step 3: Divide 326268 by 4028.

Note that 4028 × 80 = 322240, and the difference 326268 - 322240 = 4028.
Hence 4028 × 81 = 326268.

Therefore:

326268 / 4028 = 81

So:

√(?) = 81

Hence:

? = 81² = 6561

Answer: 6561