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Which pair of elements has maximum electronegativity difference?
When magnesium burns, in the air, compounds of magnesium formed are magnesium oxide and ______.
When magnesium burns in the air it forms magnesium nitride with nitrogen and with oxygen it forms magnesium oxide.
The set representing the correct order of ionic radius is:
The ionic radius of the following elements are:
Na+: 1.02 Ao
Be2+: 0.39 Ao
Mg2+: 0.72 Ao
Li+: 0.76 Ao
So, the correct option is B.
Which of the following pairs has the highest difference in their first ionization energy?
True increasing order of acidity of the oxides of Mn is:
The correct order of ionic size of N3–, Na+, F–, Mg2+ and O2– is:
The given ions are:
Hence the increasing order of ionic radius is:
12Mg2+< 11Na+< 9F-< 8O2-< 7N3-
For isoelectronic species, lower the nuclear charge higher the radius.
The size of isoelectronic species, F–, Ne and Na+ is affected by:
The first ionization potential in electron volts of nitrogen and oxygen atoms are respectively given by:
Nitrogen has higher ionization energy than Oxygen because it has a stable half-filled electronic configuration as shown below:
N - (1s)2(2s)2(2px)1(2py)1(2pz)1
O - (1s)2(2s)2(2px)2(2py)1(2pz)1
Which of the following ions is most unlikely to exist?
Be- ion is most unlikely to exist as Be has a higher tendency to lose an electron and Be has a full filled configuration.
Li- = 1s2, 2s2 (In it all sub shells are saturated so, it is stable)
Be- = 1s2, 2s2 2p1
B- = 1s2, 2s2 2p2
C- = 1s2, 2s2 2p3
Which of these does not reflect the periodicity of the elements?
The neutron/proton ratio does not reflect the periodicity of the elements.
What is the atomic number of the element with the maximum number of unpaired 4p electron?
The electronic configuration is given as follows:
Observation of the above given 4 E.C. tells us that the element having atomic number 33 will have the maximum number of unpaired electrons i.e. 3.
The electronic configuration of four elements are:
Consider the following statements:
(i) I shows variable oxidation state.
(ii) II is a d-block element.
(iii) The compound formed between I and III is covalent.
(iv) IV shows single oxidation state.
Which statement is True(T) or False (F)?
Explanation: (I) [Kr]5s1, shows only single oxidation state +1.
(II) [Rn]5f14 6d1 7s2, it is f-block element (Z=103).
(III) The compound formed between I and Ill is ionic.
(IV) [Ar]3d6 4s2, (Z=26) Fe shows variable oxidation state.
Therefore, all the above statements in the question are false.
If period number and group number of any representative element(s) are same then which of the following statement is incorrect regarding such type element(s) in their ground state: (Period number and group number are according to modern form of periodic table)
When the period and group is the same, it can only be for Hydrogen(1s1) and Beryllium(1s2 2s2). Then:
Principal quantum number (n) = 2,
Azimuthal quantum number (l) = 0,
Magnetic quantum number (m) = 0,
Spin quantum number (s) = +1 / 2 or -1 / 2.
How does the energy gap between successive energy levels in an atom vary from low to high values?
Which of the following properties of the alkaline earth metals increase from Be to Ba:
(I) Atomic radius
(II) Ionisation energy
(III) Nuclear charge
In which of the following pair, both the species are isoelectronic but the first one is large in size than the second?
The order of increasing ionic radius of the following is:
If the ionic radii of K+ and F– are nearly the same (i.,e. 1.34 Å), then the atomic radii of K and F respectively are:
Among the following species, Identify the isoelectronic and isostructural pair.
The correct option is B [BF3, NO-3]
Isoelectronic species have same number of electrons and Isostructural species have same hybridisation at the central atom.
Steric Number (x) = 1/2(M + V − C+A).
where, M = number of monovalent surrounding atoms
V = number of valence electrons on the central atom
C = charge (with sign)
A=charge on anion
number of electron=7+9×3=34
Steric Number (x)=1/2(3+5−0+0).
Steric Number (x)=4.
number of electron=7+8×3+1=32
Steric Number (x)=1/2(0+5−0+1).
Steric Number (x)=3.
number of electron=5+9×3=32
Steric Number (x)=1/2(3+3−0+0).
Steric Number (x)=3.
[BF3, NO-3] are isoelectronic and isostructural pairs.
The correct set of decreasing order of electronegativity is:
The correct option is C)