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IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Bank Exams MCQ


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30 Questions MCQ Test Mock Tests for Banking Exams 2024 - IBPS RRB PO (Scale 1) Mains Mock Test - 3

IBPS RRB PO (Scale 1) Mains Mock Test - 3 for Bank Exams 2024 is part of Mock Tests for Banking Exams 2024 preparation. The IBPS RRB PO (Scale 1) Mains Mock Test - 3 questions and answers have been prepared according to the Bank Exams exam syllabus.The IBPS RRB PO (Scale 1) Mains Mock Test - 3 MCQs are made for Bank Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for IBPS RRB PO (Scale 1) Mains Mock Test - 3 below.
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IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 1

In the given group of letters ABSUDSX if every letter which is at even position is replaced by the previous letter and every letter which is at odd position is replaced by the next letter according to the English alphabet dictionary then how many three-letter meaningful English words can be formed by 2nd, 6th and 7th letter after rearrangement. No letter will be repeated. If one word is formed than what will be 1st letter of that word. If two words can be formed answer will be Y and more than three words are formed, the answer will be Z.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 1
Even letters of ABSUDSX are B, U, and S. They are replaced by the previous letters of the English alphabet which are A, T, R, respectively.

The odd letters of ABSUDSX are A, S, D, and X. they are replaced by the next letters of the English alphabet which are B, T, E, and Y respectively.

According to the question, the new word will be BATTERY.

The 2nd, 6th, and 7th letters are A, R, and Y. Possible words are 'RAY'.

Hence, the correct option is (E).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 2

If it is possible to make only one meaningful five letters English word with the first, second and the third letters of the word TREE, together with the first, second and fourth letters of the word WEEP, then which of the following will be the fourth letter of the newly formed word? If no such word can be made give ‘X’ as the answer and if more than one such word can be made give ‘Y’ as the answer.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 2
Given Words: T R E E, W E E P

First word: 1st letter = T; 2nd letter = R; 3rd letter = E

Second word: 1st letter = W; 2nd letter = E; 4th letter = P

Letters given: T R E W E P

Possible words: TWERP (a silly or annoying person), REWET (to wet again), PETER (decrease or fade gradually before coming to an end).

Therefore, more than one such word can be made,

So, the correct answer is Y.

Hence, the correct option is (E).

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IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 3

Study the following information carefully and answer the questions given below.

A number arrangement machine when given an input line of numbers, it performs some mathematical operations in each step

Input: 348914 463581 986457 654386 146748 872351

Step I: 984431 865431 987654 866543 876441 875321

Step II: 05 21 23 02 26 60

Step III: 25 09 25 04 64 36

Step IV: 16 16 21 60 28

Step V: 37 37 05 36 68

Step V is the final step of the above input

As per the rules followed in the given steps, find appropriate steps for the given input

Input: 143765 265986 864763 344578 848754 354789

Q. What is the sum of the numbers which are second from the left end in step II and fourth from the right end in Step IV?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 3
Input: 143765 265986 864763 344578 848754 354789

Step I: 765431 986652 876643 875443 887544 987543

Step II: 20 24 04 01 02 40

Step III: 04 36 16 01 04 16

Step IV: 32 20 15 03 12

Step V: 13 04 26 09 05

Step I: In this step, all the digits are arranged in descending order within the number from left to right.

Step II: In this step, even digits are subtracted first (left to right in the given number) and then odd digits are subtracted (left to right in the given number) within the numbers.

Step III: In this step, Square of the sum of the digits of each number is taken

Step IV: In this step, The difference between the first and second number, second and third number and so on till the fifth and sixth number from left to right

Step V: In this step, sum of the square of the all digits of the number is calculated.

Required result = 20 + 24 = 44

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 4

Study the following information carefully and answer the questions given below.

A number arrangement machine when given an input line of numbers, it performs some mathematical operations in each step

Input: 348914 463581 986457 654386 146748 872351

Step I: 984431 865431 987654 866543 876441 875321

Step II: 05 21 23 02 26 60

Step III: 25 09 25 04 64 36

Step IV: 16 16 21 60 28

Step V: 37 37 05 36 68

Step V is the final step of the above input

As per the rules followed in the given steps, find appropriate steps for the given input

Input: 143765 265986 864763 344578 848754 354789

Q. Which of the following number is third to the left of the fourth number from the left end in Step I?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 4
Input: 143765 265986 864763 344578 848754 354789

Step I: 765431 986652 876643 875443 887544 987543

Step II: 20 24 04 01 02 40

Step III: 04 36 16 01 04 16

Step IV: 32 20 15 03 12

Step V: 13 04 26 09 05

Step I: In this step, all the digits are arranged in descending order within the number from left to right.

Step II: In this step, even digits are subtracted first (left to right in the given number) and then odd digits are subtracted (left to right in the given number) within the numbers.

Step III: In this step, Square of the sum of the digits of each number is taken

Step IV: In this step, The difference between the first and second number, second and third number and so on till the fifth and sixth number from left to right

Step V: In this step, sum of the square of the all digits of the number is calculated.

Step I: 765431 986652 876643 875443 887544 987543

765431 is third to the left of the fourth number from the left end in Step I.

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 5

Study the following information carefully and answer the questions given below.

A number arrangement machine when given an input line of numbers, it performs some mathematical operations in each step

Input: 348914 463581 986457 654386 146748 872351

Step I: 984431 865431 987654 866543 876441 875321

Step II: 05 21 23 02 26 60

Step III: 25 09 25 04 64 36

Step IV: 16 16 21 60 28

Step V: 37 37 05 36 68

Step V is the final step of the above input

As per the rules followed in the given steps, find appropriate steps for the given input

Input: 143765 265986 864763 344578 848754 354789

Q. What is the position of “36” in the third step?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 5
Input: 143765 265986 864763 344578 848754 354789

Step I: 765431 986652 876643 875443 887544 987543

Step II: 20 24 04 01 02 40

Step III: 04 36 16 01 04 16

Step IV: 32 20 15 03 12

Step V: 13 04 26 09 05

Step I: In this step, all the digits are arranged in descending order within the number from left to right.

Step II: In this step, even digits are subtracted first (left to right in the given number) and then odd digits are subtracted (left to right in the given number) within the numbers.

Step III: In this step, Square of the sum of the digits of each number is taken

Step IV: In this step, The difference between the first and second number, second and third number and so on till the fifth and sixth number from left to right

Step V: In this step, sum of the square of the all digits of the number is calculated.

Step III: 04 36 16 01 04 16

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 6

Study the following information carefully and answer the questions given below.

A number arrangement machine when given an input line of numbers, it performs some mathematical operations in each step

Input: 348914 463581 986457 654386 146748 872351

Step I: 984431 865431 987654 866543 876441 875321

Step II: 05 21 23 02 26 60

Step III: 25 09 25 04 64 36

Step IV: 16 16 21 60 28

Step V: 37 37 05 36 68

Step V is the final step of the above input

As per the rules followed in the given steps, find appropriate steps for the given input

Input: 143765 265986 864763 344578 848754 354789

Q. Which of the following number is third from the left end in penultimate step?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 6
Input: 143765 265986 864763 344578 848754 354789

Step I: 765431 986652 876643 875443 887544 987543

Step II: 20 24 04 01 02 40

Step III: 04 36 16 01 04 16

Step IV: 32 20 15 03 12

Step V: 13 04 26 09 05

Step I: In this step, all the digits are arranged in descending order within the number from left to right.

Step II: In this step, even digits are subtracted first (left to right in the given number) and then odd digits are subtracted (left to right in the given number) within the numbers.

Step III: In this step, Square of the sum of the digits of each number is taken

Step IV: In this step, The difference between the first and second number, second and third number and so on till the fifth and sixth number from left to right

Step V: In this step, sum of the square of the all digits of the number is calculated.

Step IV: 32 20 15 03 12

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 7

The consonants in the word 'HOUSEWARMING' are changed to the respective previous alphabets in the English alphabetical series and the vowels are changed to the respective alphabets succeeding them in the series. Any alphabet which is repeated in the word thus formed is eliminated. How many pairs of letters in the word formed after arranging the remaining letters in alphabetical order have as many letters between them in the word (both forward and backward direction) as they have between them in the English alphabetical series?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 7
1) After replacing the consonants and the vowels in the word 'HOUSEWARMING' as required: GPVRFVBQLJMF

2) After eliminating the alphabets as required: GPRBQLJM

3) After arranging in alphabetical order: BGJLMPQR

Forward direction: 4 pairs (LM, PQ, PR, QR)

Backward direction: no pair

So, there are only four such pairs that have as many letters between them in the word as they have between them in the English alphabetical series.

Hence, the correct option is (D).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 8

Directions: Study the following information carefully and answer the questions given below.

Six buses P, Q, R, S, T and U are made to stand in a row facing north and the distance between two adjacent buses increases from left to right, in consecutive integral multiple of 5. Only two buses stand between P and U, one of them stands at the right end of the row. The distance between R and T is 105 meters. The distance between T and U is 95 meters. T stands somewhere to the left of U. S stands immediate to the left of P. Only one bus stands between S and T. Bus U starts towards North, after moving 30 meters, it turns to its right and moved 10 meters. Again it turns left and moves 5 meters it reaches at a point A. Bus P, moves in the South direction for a distance of 10 meters and then turns to its left and moves 50 meters. After taking one more turn to its left it stops at point B after moving 5 meters. Bus R, moves west and travels 10 meters before turning to its right. After moving 20 meters it takes the right turn and moves 5 meters. After taking one more turn to its left it stops at point C after moving 15 meters.

Q. What is the position of Car P with respect of point C?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 8
Six buses P, Q, R, S, T and U are made to stand in a row facing north and the distance between two adjacent buses increases from left to right, in consecutive integral multiple of 5.

1) Only two buses stand between P and U, one of them stands at the right end of the row

2) S stands immediate left of P.

3) Only one bus stands between S and T. (This eliminates case 2)

4) Distance between T and U is 95 meters.

5) T stands somewhere to the left of U.

6) Distance between R and T is 105 meters.

7) Bus U starts towards North, after moving 30 meters, it turns to its right and moved 10 meters. Again it turns left and moves 5 meters it comes at a point A.

8) Bus P, moves in the South direction for a distance of 10 meters and then turns to its left and moves 50 meters. After taking one more turn to its left stops at point B after moving 5 meters.

10) Bus R, walks west and travels 10 meters before turning to its right. After moving 20 meters it takes the right turn and moves 5 meters. After taking one more turn to its left it stops at point C after moving 15 meters.

So, Car P stands Southeast of point C.

Hence, the correct option is (E).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 9

Directions: Study the following information carefully and answer the questions given below.

Six buses P, Q, R, S, T and U are made to stand in a row facing north and the distance between two adjacent buses increases from left to right, in consecutive integral multiple of 5. Only two buses stand between P and U, one of them stands at the right end of the row. The distance between R and T is 105 meters. The distance between T and U is 95 meters. T stands somewhere to the left of U. S stands immediate to the left of P. Only one bus stands between S and T. Bus U starts towards North, after moving 30 meters, it turns to its right and moved 10 meters. Again it turns left and moves 5 meters it reaches at a point A. Bus P, moves in the South direction for a distance of 10 meters and then turns to its left and moves 50 meters. After taking one more turn to its left it stops at point B after moving 5 meters. Bus R, moves west and travels 10 meters before turning to its right. After moving 20 meters it takes the right turn and moves 5 meters. After taking one more turn to its left it stops at point C after moving 15 meters.

Q. What is the distance between bus S and bus Q?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 9
Six buses P, Q, R, S, T and U are made to stand in a row facing north and the distance between two adjacent buses increases from left to right, in consecutive integral multiple of 5.

1) Only two buses stand between P and U, one of them stands at the right end of the row

2) S stands immediate left of P.

3) Only one bus stands between S and T. (This eliminates case 2)

4) Distance between T and U is 95 meters.

5) T stands somewhere to the left of U.

6) Distance between R and T is 105 meters.

7) Bus U starts towards North, after moving 30 meters, it turns to its right and moved 10 meters. Again it turns left and moves 5 meters it comes at a point A.

8) Bus P, moves in the South direction for a distance of 10 meters and then turns to its left and moves 50 meters. After taking one more turn to its left stops at point B after moving 5 meters.

10) Bus R, walks west and travels 10 meters before turning to its right. After moving 20 meters it takes the right turn and moves 5 meters. After taking one more turn to its left it stops at point C after moving 15 meters.

Distance between S and Q = 35 + 40 + 45 = 120 m

So, the distance between Bus S and Bus Q is 120 meters.

Hence, the correct option is (D).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 10

If all the letters of the words are changed to the second successive letter as per the alphabetical series and arrange the letters in reverse alphabetical order within the word, then which of the following words have vowels each of which is immediately preceded by a consonant?

I. MEMORIAL

II. CHANGE

III. GEOGRAPHY

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 10
I. MEMORIAL → OGOQTKCN → TQOONKGC

II. CHANGE → EJCPIG → PJIGEC

III. GEOGRAPHY → IGQITCRJA → TRQJIIGCA

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 11

If all the digits are added within the number, then in which of the following the resultant obtained will be an odd number after subtracting the highest number and lowest number thus formed in each option?

I. 4793, 3782, 5437

II. 4662, 8355, 1347

III. 7742, 6753, 2022

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 11
I. 4793, 3782, 5437 → 23, 20, 19 → 23-19 = 4

II. 4662, 8355, 1347 → 18, 21, 15 21-15 = 6

III. 7742, 6753, 2022 20, 21, 06 21-6 = 15

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 12

DIRECTION: The question consists of two statements, an assertion and a reason. The student must first determine whether each statement is true. Choose the appropriate option, after reading the two statements carefully.

ASSERTION (A): India is one of the world's fastest-growing economies

REASON (R): The agricultural sector is the largest sector of employment, in India

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 12
The assertion, which states that India is one of the world's fastest growing economies, is true, In 2018, it overtook China, as the world's fastest growing economy. The reason is also true, however it is not an explanation for the assertion, and is merely an independent fact.

Hence, the correct option is (B).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 13

Direction: question below consists of a question and three statements numbered I, II and III given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Six persons A, B, C, D, E, and F have the meeting with the teacher on 5th and 12th in the month of September, October, and November. No two persons have the meeting on the same day. Who among them has the meeting on October 5th?

Statement I: C and D have the meeting in the same month. No person has the meeting before C.

Statement II: B has the meeting on the 5th of a month, which has 30 days. Only two persons have meetings between B and D.

Statement III: B and E have the meeting in the same month. A and E do not have the meeting on the same date.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 13
Statement I: C and D have the meeting in the same month. No person has the meeting before C.

That means C has the meeting on 5th Sep and D has a meeting after C.

Therefore, the statement I alone is not sufficient.

Statement II: B has the meeting on the 5th of a month, which has 30 days. Only two persons have meetings between B and D.

Case 1:

Case 2:

Therefore, statement II alone is not sufficient.

Statement III: B and E have the meeting in the same month. A and E do not have the meeting on the same date.

Therefore, B and E can have the meeting in either September or October, or November.

So, statement III alone is not sufficient.

On combining Statement I and II:

C and D have the meeting in the same month. No person has the meeting before C.

B has the meeting on the 5th of a month, which has 30 days. Only two persons have meetings between B and D.

That means B has meeting on 5th Nov (November has 30 days).

Therefore, statements I and II together are not sufficient.

On combining statement I, II, and III:

C and D have the meeting in the same month. No person has the meeting before C.

B has the meeting on the 5th of a month, which has 30 days. Only two persons have meetings between B and D.

B and E have the meeting in the same month. A and E do not have the meeting on the same date.

That means E has the meeting on 12th Nov and thus A has the appointment on 5th Oct.

So, A has the appointment on 5th Oct.

So, all the statements together are required to answer the question.

Hence, the correct option is (C).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 14

Study the following information carefully and answer the questions given below.

In a certain code language

“Water level stain molecules sphere” is coded as “O6 H10 I6 V5 M6”

“Core Machine Learn Element Magic” is coded as “V8 G8 V3 M6 X6”

“Each Coating variety Bounce floor” is coded as “T8 S3 V5 I6 B8”

Q. What is the code for the word “Stereotype” in the given code language?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 14
For Number: If the number of the letters in the word is even, then the number is decreased by 1. If the number of letters in the word is odd, then the number is increased by 1.

For letter: The last letter of the word is coded as its complementary pair as per alphabetical series.

Ex: Water ->The number of letters in the word is odd (5), then the code for number is increased by 1 i.e. 6

Complementary pair for R is I and then the code for Water is I6

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 15

Study the following information carefully and answer the questions given below.

In a certain code language

“Water level stain molecules sphere” is coded as “O6 H10 I6 V5 M6”

“Core Machine Learn Element Magic” is coded as “V8 G8 V3 M6 X6”

“Each Coating variety Bounce floor” is coded as “T8 S3 V5 I6 B8”

Q. How “Variety Element” is coded in the given code language?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 15
For Number: If the number of the letters in the word is even, then the number is decreased by 1. If the number of letters in the word is odd, then the number is increased by 1.

For letter: The last letter of the word is coded as its complementary pair as per alphabetical series.

Ex: Water ->The number of letters in the word is odd (5), then the code for number is increased by 1 i.e. 6

Complementary pair for R is I and then the code for Water is I6

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 16

Study the following information carefully and answer the questions given below.

In a certain code language

“Water level stain molecules sphere” is coded as “O6 H10 I6 V5 M6”

“Core Machine Learn Element Magic” is coded as “V8 G8 V3 M6 X6”

“Each Coating variety Bounce floor” is coded as “T8 S3 V5 I6 B8”

Q. Which of the following word is coded as “I6” in the given code language?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 16
For Number: If the number of the letters in the word is even, then the number is decreased by 1. If the number of letters in the word is odd, then the number is increased by 1.

For letter: The last letter of the word is coded as its complementary pair as per alphabetical series.

Ex: Water ->The number of letters in the word is odd (5), then the code for number is increased by 1 i.e. 6

Complementary pair for R is I and then the code for Water is I6

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 17

Study the following information carefully and answer the questions given below.

In a certain code language

“Water level stain molecules sphere” is coded as “O6 H10 I6 V5 M6”

“Core Machine Learn Element Magic” is coded as “V8 G8 V3 M6 X6”

“Each Coating variety Bounce floor” is coded as “T8 S3 V5 I6 B8”

Q. How “World Crisis” is coded in the given code language?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 17
For Number: If the number of the letters in the word is even, then the number is decreased by 1. If the number of letters in the word is odd, then the number is increased by 1.

For letter: The last letter of the word is coded as its complementary pair as per alphabetical series.

Ex: Water → The number of letters in the word is odd (5), then the code for number is increased by 1 i.e. 6

Complementary pair for R is I and then the code for Water is I6

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 18

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions:

a) If the data in Statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.

b) If the data in Statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question.

c) If the data either in Statement I alone or in Statement II alone is sufficient to answer the question.

d) If the data in both Statements I and II together are not sufficient to answer the question.

e) If the data in both Statements I and II together are sufficient to answer the question.

Q. Eight persons are living in a eight storey building. The lowermost floor is numbered as 1 and the floor immediately above it is numbered as 2 and so on. R lives on which floor?

Statement I: Q lives either on 2nd or 5th floor. M lives immediately above Q. O lives two floors above M. P lives adjacent floor of O. Only one person lives between R and P.

Statement II: L lives on an odd numbered floor but below fifth floor. Only one person lives between L and M, who lives two floors below O. Only one person lives between O and N. S lives immediately above N.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 18
From Statement I

Clearly, we can’t find on which floor does R live.

Hence, statement I is not sufficient

From statement II:

Clearly, we can’t find on which floor does R lives.

Hence, statement II is not sufficient

After combining I and II we have:

Clearly, we can’t find on which floor does R live.

Hence, Statement I and II together is not sufficient.

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 19

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions:

a) If the data in Statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.

b) If the data in Statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question.

c) If the data either in Statement I alone or in Statement II alone is sufficient to answer the question.

d) If the data in both Statements I and II together are not sufficient to answer the question.

e) If the data in both Statements I and II together are sufficient to answer the question.

Q. Six persons A, B, C, D, E and F are sitting around a circular table facing Centre. Who sits second to the right of B?

Statement I: E sits second to the right of F. Only two persons sit between E and A. Both D and B are adjacent to each other.

Statement II: Both A and C are immediate neighbors of F. B sits two places away from C. D sits between A and B.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 19
From Statement I

Clearly, we can’t find the person who sits second to the right of B.

Hence, Statement I is not sufficient

From Statement II:

Clearly, we can’t find the person who sits second to the right of B.

Hence, Statement II is not sufficient

After combining I and II we have:

Clearly, we can find that A sits second to the right of B

Hence, Statement I and II together is sufficient.

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 20

Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions:

a) If the data in Statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.

b) If the data in Statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question.

c) If the data either in Statement I alone or in Statement II alone is sufficient to answer the question.

d) If the data in both Statements I and II together are not sufficient to answer the question.

e) If the data in both Statements I and II together are sufficient to answer the question.

Q. What is the direction of Point M with respect to point Z?

Statement I: Point K is north of point T, which is west of point M. Point Z is west of point A. Point Z is neither south nor southeast of point T. Point A is southeast of point K and South of point M.

Statement II: Point K is north of point M, which is west of point L. Point Z is south of point L. Point N is north of point F, which is southeast of point K and west of point Z. Point N is neither west of L nor northeast of point M.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 20
From Statement I

From Statement I, we can find the direction

From Statement II:

From Statement II, we can find the direction

So either from I or II we can find the direction of Point M with respect to point Z

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 21

If it is possible to make only one meaningful English word with the first, second and fourth letters of the word RAMP, together with the first, second, third and seventh letters of the word DISLIKE, which of the following will be the sixth letter of the newly formed word? If no such word can be made give ‘X’ as the answer and if more than one such word can be made give ‘Y’ as the answer.

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 21
Given Words: RAMP, DISLIKE

First word: 1st letter = R; 2nd letter = A; 4th letter = P

Second word: 1st letter = D; 2nd letter = I; 3rd letter = S; 7th letter = E;

Letters given: R A P D I S E

Possible words: ASPIRED (ambitions towards achieving), DESPAIR (absence of hope),

DIAPERS (a baby's nappy), PRAISED (express one’s respect and gratitude).

Therefore, more than one such word can be made.

So, the correct answer is Y.

Hence, the correct option is (E).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 22

Direction: Study the following information carefully and answer the given questions.

When a number/letter/symbol arrangement machine is given an input of line of letter/number/symbol, it arranges them by following a certain rule. Following is an illustration of input and rearrangement.

Read the following information and answer the questions that follow.

INPUT: paper 61 below 77 and round 98 temple eliminate 83 64

Step 1: 61 paper below 77 and round 98 temple eliminate 83 64

Step 2: 61 83 paper below 77 and round 98 temple eliminate 64

Step 3: 61 83 and paper below 77 round 98 temple eliminate 64

Step 4: 61 83 and eliminate paper below 77 round 98 temple 64

Step 5: 61 83 and eliminate 77 paper below round 98 temple 64

Step 6: 61 83 and eliminate 77 below paper round 98 temple 64

Step 7: 61 83 and eliminate 77 below paper round temple 98 64

Step 8: 61 83 and eliminate 77 below paper round temple 64 98

Find the output for the following input:

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Q. Which of the following element is fourth to the left of second from the right end in step 5?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 22
Conditions are as follows,

(I) Arrange prime number in increasing order.

(II) Then arrange the word that start with vowels in ascending order.

(III) Then arrange odd numbers in increasing order.

(IV) After odd numbers, remaining all consonant in alphabetic order.

(V) At last, even number is placed in ascending order.

Apply the same rule on the given input we get,

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Step 1: 19 energy random 23 could slowly 35 movie 75 phone 98

Step 2: 19 23 energy random could slowly 35 movie 75 phone 98

Step 3: 19 23 energy 35 random could slowly movie 75 phone 98

Step 4: 19 23 energy 35 75 random could slowly movie phone 98

Step 5: 19 23 energy 35 75 could random slowly movie phone 98

Step 6: 19 23 energy 35 75 could movie random slowly phone 98

Step 7: 19 23 energy 35 75 could movie phone random slowly 98

Thus, ‘could’ is fourth to the left of the second from the right end in step 5.

Hence, the correct option is (A).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 23

Direction: Study the following information carefully and answer the given questions.

When a number/letter/symbol arrangement machine is given an input of line of letter/number/symbol, it arranges them by following a certain rule. Following is an illustration of input and rearrangement.

Read the following information and answer the questions that follow.

INPUT: paper 61 below 77 and round 98 temple eliminate 83 64

Step 1: 61 paper below 77 and round 98 temple eliminate 83 64

Step 2: 61 83 paper below 77 and round 98 temple eliminate 64

Step 3: 61 83 and paper below 77 round 98 temple eliminate 64

Step 4: 61 83 and eliminate paper below 77 round 98 temple 64

Step 5: 61 83 and eliminate 77 paper below round 98 temple 64

Step 6: 61 83 and eliminate 77 below paper round 98 temple 64

Step 7: 61 83 and eliminate 77 below paper round temple 98 64

Step 8: 61 83 and eliminate 77 below paper round temple 64 98

Find the output for the following input:

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Q. Which of the following step represent the following output?

19 23 energy 35 random could slowly movie 75 phone 98

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 23
Conditions are as follows,

(I) Arrange prime number in increasing order.

(II) Then arrange the word that start with vowels in ascending order.

(III) Then arrange odd numbers in increasing order.

(IV) After odd numbers, remaining all consonant in alphabetic order.

(V) At last, even number is placed in ascending order.

Apply the same rule on the given input we get,

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Step 1: 19 energy random 23 could slowly 35 movie 75 phone 98

Step 2: 19 23 energy random could slowly 35 movie 75 phone 98

Step 3: 19 23 energy 35 random could slowly movie 75 phone 98

Step 4: 19 23 energy 35 75 random could slowly movie phone 98

Step 5: 19 23 energy 35 75 could random slowly movie phone 98

Step 6: 19 23 energy 35 75 could movie random slowly phone 98

Step 7: 19 23 energy 35 75 could movie phone random slowly 98

Thus, this output is in step 3.

Hence, the correct option is (E).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 24

Direction: Study the following information carefully and answer the given questions.

When a number/letter/symbol arrangement machine is given an input of line of letter/number/symbol, it arranges them by following a certain rule. Following is an illustration of input and rearrangement.

Read the following information and answer the questions that follow.

INPUT: paper 61 below 77 and round 98 temple eliminate 83 64

Step 1: 61 paper below 77 and round 98 temple eliminate 83 64

Step 2: 61 83 paper below 77 and round 98 temple eliminate 64

Step 3: 61 83 and paper below 77 round 98 temple eliminate 64

Step 4: 61 83 and eliminate paper below 77 round 98 temple 64

Step 5: 61 83 and eliminate 77 paper below round 98 temple 64

Step 6: 61 83 and eliminate 77 below paper round 98 temple 64

Step 7: 61 83 and eliminate 77 below paper round temple 98 64

Step 8: 61 83 and eliminate 77 below paper round temple 64 98

Find the output for the following input:

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Q. Which of the following steps is the step 4 given input?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 24
Conditions are as follows,

(I) Arrange prime number in increasing order.

(II) Then arrange the word that start with vowels in ascending order.

(III) Then arrange odd numbers in increasing order.

(IV) After odd numbers, remaining all consonant in alphabetic order.

(V) At last, even number is placed in ascending order.

Apply the same rule on the given input we get,

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Step 1: 19 energy random 23 could slowly 35 movie 75 phone 98

Step 2: 19 23 energy random could slowly 35 movie 75 phone 98

Step 3: 19 23 energy 35 random could slowly movie 75 phone 98

Step 4: 19 23 energy 35 75 random could slowly movie phone 98

Step 5: 19 23 energy 35 75 could random slowly movie phone 98

Step 6: 19 23 energy 35 75 could movie random slowly phone 98

Step 7: 19 23 energy 35 75 could movie phone random slowly 98

Hence, the correct option is (E).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 25

Direction: Study the following information carefully and answer the given questions.

When a number/letter/symbol arrangement machine is given an input of line of letter/number/symbol, it arranges them by following a certain rule. Following is an illustration of input and rearrangement.

Read the following information and answer the questions that follow.

INPUT: paper 61 below 77 and round 98 temple eliminate 83 64

Step 1: 61 paper below 77 and round 98 temple eliminate 83 64

Step 2: 61 83 paper below 77 and round 98 temple eliminate 64

Step 3: 61 83 and paper below 77 round 98 temple eliminate 64

Step 4: 61 83 and eliminate paper below 77 round 98 temple 64

Step 5: 61 83 and eliminate 77 paper below round 98 temple 64

Step 6: 61 83 and eliminate 77 below paper round 98 temple 64

Step 7: 61 83 and eliminate 77 below paper round temple 98 64

Step 8: 61 83 and eliminate 77 below paper round temple 64 98

Find the output for the following input:

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Q. In step 7, what is the sum of first element from right end and fourth element from the left end?

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 25
Conditions are as follows,

(I) Arrange prime number in increasing order.

(II) Then arrange the word that start with vowels in ascending order.

(III) Then arrange odd numbers in increasing order.

(IV) After odd numbers, remaining all consonant in alphabetic order.

(V) At last, even number is placed in ascending order.

Apply the same rule on the given input we get,

INPUT: energy random 23 could 19 slowly 35 movie 75 phone 98

Step 1: 19 energy random 23 could slowly 35 movie 75 phone 98

Step 2: 19 23 energy random could slowly 35 movie 75 phone 98

Step 3: 19 23 energy 35 random could slowly movie 75 phone 98

Step 4: 19 23 energy 35 75 random could slowly movie phone 98

Step 5: 19 23 energy 35 75 could random slowly movie phone 98

Step 6: 19 23 energy 35 75 could movie random slowly phone 98

Step 7: 19 23 energy 35 75 could movie phone random slowly 98

Thus, sum of first element from right and fourth element from the left = 98 + 35 = 133.

Hence, the correct option is (B).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 26

Read the given details carefully and choose the correct option as your answer.

Cause: Following years of stringent population control, restricting most couples to a single child, in 2016, China relaxed its one-child policy to allow two children and later in 2021 to three.

Which of the given options is definitely an effect of the above cause?

Effects:

(i) The Total Fertility Rate (TFR) in China is barely 1.16.

(ii) India will become the most populous country in 2023.

(iii) Chinese couples seem to have adjusted to life with a single child

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 26
The statement given provides information about the Chinese strict ‘One-child’ policy which later was relaxed. In the effects, we can clearly rule out the second sentence because it talks about India and there is no discussion about India in the given cause.

Chinese couples getting adjusted to a policy may not necessarily be the main effect. It can be counted as a probable effect though. So, the correct answer should not include this statement.

Only the first sentence justifies the cause as the policy will directly affect the fertility rate. If the couples weren’t allowed more than one child, obviously the rate would be low.

So, the correct answer is option (a).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 27

Read the given details carefully and choose the correct option as your answer.

Statement: The entire Barak Valley in general and its headquarters, Silchar, have always been vulnerable to recurring floods due to the Barak going in spate resulting from heavy rains upstream, around Manipur and Mizoram.

Course Of Action:

(i) The state must make serious plans to guard the river

(ii) Dykes must be constructed and its maintenance should be prioritised

(iii) The activities in the area should restart after the flood water recedes slowly

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 27
The issue being mentioned in the statement is the flood that is a recurring phenomenon due to the carelessness of the authorities (not clearly mentioned though but understood). This problem should either be solved or at least lessened due with any course of action that we choose. We never take extreme solutions as the correct answers.

The first sentence talks about guarding the river which in turn can help in the management of the river water and save it from rampaging the state with floods. So, yes! This can be one correct course of action.

If the dykes being mentioned in the second CoA are constructed, they will certainly stop the river water from flooding into the inhabited areas. This CoA will also help solve the flooding problem.

The third sentence doesn’t help but is more like a measure to be followed after the floods. What we need is a plan to control the floods and its damage.

So, the best would be to mark option (b) as the answer.

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 28

Read the given details carefully and choose the correct option as your answer.

Woman can’t be forced to cohabit with husband even by court decree: Gujarat HC

Which of the given Assumptions would have led the HC to deliver such an order?

(i) Women have only one home after their marriage that is their husband’s

(ii) A certain court has passed an order necessitating the woman to live with her husband

(iii) It is mandatory for people to follow court’s orders

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 28
If we assume III which says people must follow court’s orders come what may, we understand that such a ruling might’ve been made that compels the woman to cohabit with her husband against her will. It is generally assumed that court’s orders must be followed.

But the Gujrat HC has negated that as per the information given.

Hence, option (e) is the best option.

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 29

Direction: Read the following information carefully and answer the questions that follow:

In a certain coding system,

P & Q means P is not greater than Q,

P % Q means P neither smaller than nor greater than Q.

P @ Q means P is neither smaller nor equal to Q,

P $ Q means P is not smaller than Q

Based on the information provided above, answer the following questions.

Statements: G $ P $ D, Q % R $ G, S & P

Conclusions:

I. P % Q

II. D $ S

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 29
According to the information given,

Given statement: G $ P $ D, Q % R $ G, S & P

After converting: G ≥ P ≥ D, Q = R ≥ G, S ≤ P

After combining: Q = R ≥ G ≥ P ≥ D and Q = R ≥ G ≥ P ≥ S

Conclusions:

I. P % Q ⇒ P = S → false (as Q = R ≥ G ≥ P → Q ≥ P)

II. D $ S ⇒ D ≥ S → false (as P ≥ D and S ≤ P → S ≤ P ≥ D → clear relation between D and S cannot be determined)

So, neither conclusion I nor II follows.

Hence, the correct option is (D).

IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 30

Direction: Read the following information carefully and answer the questions that follow:

In a certain coding system,

P & Q means P is not greater than Q,

P % Q means P neither smaller than nor greater than Q.

P @ Q means P is neither smaller nor equal to Q,

P $ Q means P is not smaller than Q

Based on the information provided above, answer the following questions.

Statements: B $ V, B % G & D, M @ G

Conclusions:

I. M @ D

II. D % M

Detailed Solution for IBPS RRB PO (Scale 1) Mains Mock Test - 3 - Question 30
According to the information given,

Given statement: B $ V, B % G & D, M @ G

After converting: B ≥ V, B = G ≤ D, M > G

After combining: V ≤ B = G ≤ D and V ≤ B = G < />

Conclusions:

I. M @ D ⇒ M > D → false (as G ≤ D and G < m="" →="" m="" /> G ≤ D → relation between M and D cannot be established)

II. D % M ⇒ D = M → false (as G ≤ D and G < m="" →="" m="" /> G ≤ D → relation between M and D cannot be established)

So, neither conclusion I nor II follows.

Hence, the correct option is (D).

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