Test: Domain and Range - Class 10 MCQ

g({0}) for the function g(x) is {x | 0 ≤ x ≤ 1}. Put g(x) = y and find the value of x in terms of y such that [x] = y.

To find the inverse of the function equate f(x) then find the value of x in terms of y such that f ^-1 (y) = x.

The composition of f and g is given by f(g(x)) which is equal to 2(3x + 4) + 1.

The function is not onto as f(a) ≠ b.

For every integer “y” there is an integer “x ” such that f(x) = y.

The function f(x) = x³ is one to one as no two values in domain are assigned the same value of the function and it is onto as all R of the co domain is images of elements in the domain.

Two bytes are required to encode 2000 (actually with 2 bytes you can encode up to and including 65,535.

The domain of the integers is Z⁺ X Z⁺.

The value of [5/2] is 2 so, the value of [1/2.2] is 1.

A function is one-to-one if and only if f(a) ≠ f(b) whenever a ≠ b.