MAT Mock Test - 9 - MAT MCQ

A gentleman at large means a man without a job.

Eg- He sold his business and is now a gentleman at large.

Refer to the 2^nd paragraph 2^nd line- Men are named, sometimes anonymously, and the naming itself requires punitive action to be taken against them. There isn’t really any room for discussion on context or degree of culpability.

The statement is not true according to the passage is- just naming and shaming the perpetrators does not account for culpability,

The most appropriate word to fill in the given blank is 'nevertheless'.

• The word 'nevertheless' means 'in spite of that 
  • Example: It was a cold, rainy day. Nevertheless, more people came than we had expected.
• We use 'nevertheless' when saying something that contrasts with what has just been said.

The proper order is: QRPS

Reason:

• The first sentence tells us that we should plan our leisure carefully, which also means we should choose our leisure activity wisely. Q follows 1.
• Now the question arise, which type of activity should we choose? Since in the previous sentence we have already mentioned about the activity. In this sentence, activity should be referred to as 'it'. Therefore, the next sentence in the sequence should be R.
• The author goes on to explain exactly which type of activity we must choose. He says we must choose the ones that make us happy. So the next sentence is P, followed by the last remaining sentence S.

The correct sentence is:

We should choose some interesting and useful activity. It should increase our confidence. The activity we choose should make us happy. We should then work at it during our leisure.

The word 'insipid' refers to something that lacks flavor and is tasteless.
The word 'delicious' refers to something that is very tasty and very pleasant to the taste.
Thus, it is clear the 'insipid' and 'delicious' are opposite words.

The given figure shows the mirror image of the clock:

The mirror image of the circle remains a circle, the arrow facing south will also remain the same, but the arrow facing north-west will face north-east.

Therefore "6 : 05" is the real-time.

As per the English alphabetical series and its place value.
The logic is as:

Similarly,

Therefore, VDABECN is the correct answer.

1 minute = 60 seconds

1 second = 1 ÷ 60 minutes

So, 3240° is covered by minute hand in (3240 ÷ 60) minutes i.e, 54 minutes.

According to the given information:

Number of soldiers between Sam and Deepak = Total Soldiers - 28 - 1 (Sam) - 8 - 1 (Deepak)

Given that:

Total number of soldiers = 49

Therefore,

Number of soldiers between Sam and Deepak = 49 - 28 - 1 - 8 - 1 = 11

Total number of cameras = Position of the camera from right + Position of the camera from left
60 = Position of Dino's camera from right + 9
Position of Dino's camera from right = 60 - 9 = 51
Therefore, there will be 51 cameras on the right-hand side of his selected camera.

When date and month are same and the year is different, we find the odd days via subtracting the year from higher to lower year and add the leap year between the years.

Odd days = 2017-2002=

Leap year between 2002 to 2017 are 2004,2008,2012,2016 total 4 leap year.

Odd days =

=

= 2 week + 5 odd days

Friday, Saturday, Sunday, Monday, Tuesday, Wednesday (5th odd day). So, the answer is Wednesday.

1) F has a rank DIG and using the Samsung mobile. One person between F and who use Redmi.

2) The one who is DG use Apple.

3) The total number of ranks is senior than F is the same as the number of ranks between F and D.

4)  Person C is two rank seniors from the one who use Samsung phone.

5) Only two persons between person C and Nokia.

6) The one who use One plus one rank senior to G, who is not DSP. (So, mobile phone (a) is eliminate because no place for it.)

7) Only three persons between the G and A.

8) The one who use realme is one rank senior to Jio and one person between realme and H.

9) B is junior than H and senior than A.

In the final arrangement, E has the posted as DG and IG using the Google phone.

So, E is the three rank above the one who use Samsung phone.

1) F has a rank DIG and using the Samsung mobile. One person between F and who use Redmi.

2) The one who is DG use Apple.

3) The total number of ranks is senior than F is the same as the number of ranks between F and D.

4)  Person C is two rank seniors from the one who use Samsung phone.

5) Only two persons between person C and Nokia.

6) The one who use One plus one rank senior to G, who is not DSP. (So, mobile phone (a) is eliminate because no place for it.)

7) Only three persons between the G and A.

8) The one who use realme is one rank senior to Jio and one person between realme and H.

9) B is junior than H and senior than A.

In the final arrangement, E has the posted as DG and IG using the Google phone.

So, SP is using Nokia mobile phone.

Quantity I: 6 kmph

Quantity II:

Speed of boat = 5.5 km/h

Let the speed of the stream be x km/h

⇒ Downstream speed = (5.5 + x)

⇒ Upstream speed = (5.5 – x)

According to the question,

(5.5 + x) = 3 × (5.5 – x)

⇒ 5.5 + x = 16.5 – 3x

⇒ 5.5 – 16.5 = -3x – x

⇒ 11 = 4x

⇒ x = 2.75

Speed of stream = 2.75 kmph

∴ Quantity I ˃ Quantity II

Statement I:

6 men and 4 women together can complete the work in 12 days and 1 man and 8 women together can complete the work in 17 days.

Suppose the efficiencies of man and woman are ‘m’ and ‘w’ respectively.

So,

(6 × m + 4 × w) × 12 = (1 × m + 8 × w) × 17

⇒ 72m + 48w = 17m + 136w

⇒ 55m = 88w

⇒ m : w = 8 : 5

So, ratio of efficiencies of a man and a woman = 8 : 5

Combining statement II:

Ratio of efficiencies of a woman and a kid = 5 : 2

Ratio of efficiencies of a man, a woman and a kid = 8 : 5 : 2

Suppose the work done by men, women and kid be 8x, 5x and 2x respectively

Now,

Suppose the time taken by 8 men, 4 women and 6 kids together is T days

(6 × 8x + 4 × 5x) × 12 = (8 × 8x + 4 × 5x + 6 × 2x) × T

⇒ (48x + 20x) × 12 = (64x + 20x + 12x) × T

⇒ 68x × 12 = 96x × T

⇒ T = 8.5

Time taken by 8 men, 4 women and 6 kids together = 8.5 days

∴ Statements I and II together are required to answer the question.

The number of units of electricity consumed by house R in June = 320

The ratio of the number of units of electricity consumed by food appliances to an electronic appliance in the month of June = 2 : 3

The  number of units of electricity consumed by food appliances in the month of June 

The number of units of electricity consumed by house R in July = 550

The ratio of the units of electricity consumed by food appliances to electronic appliances in the month of July = 3 : 2

The  number of units of electricity consumed by food appliances in the month of July 

The total number of units of electricity consumed by food appliances in house R = 128 + 330 = 458

∴ The total number of units of electricity consumed by food appliances in house R is 458 units.

The number of units of electricity consumed by house S in June = 250 

The number of units of electricity consumed by house S in July = 420 

The number of units of electricity used in the month of August is the average of the number of units of electricity used in the month of June and July.

The number of units electricity consumed by house S in August  units

The initial 150 units of electricity used in August is charged at the rate of Rs. 3 per unit.

The remaining units are charged at the rate of Rs. x per unit.

The total bill paid in August = Rs. 1745
∴ 150 × 3 + ( 335 − 150 ) × x = 1745
⇒ 450 + 185 x = 1745
⇒ 185 x = 1295
⇒ x = 7
∴ The value of x is Rs. 7.

Given:

Excavation cost of coal per kg:

October 2020 = Rs 5 per kg

December 2020 = Rs 6 per kg

Cost of coal Rs per kg:

October 2020 = Rs 14 per kg

December 2020 = Rs 16 per kg

Selling price of coal Rs per kg:

October 2020 = Rs 47 per kg

December 2020 = Rs 52 per kg

Coal manufactured:

October 2020 = 2500 kg

December 2020 = 4500 kg

Coal purchased:

October 2020 = 3000 kg

December 2020 = 3600 kg

Total cost in October 2020 = 2500 × (5 + 14)

⇒ Total cost in October 2020 = Rs 47,500

Total selling price in October 2020 = 47 × 2500

⇒ Total S.P. in October 2020 = 117500

Profit = 117500 - 47500

⇒ Profit = Rs 70,000

Total cost in December 2020 = 4500 × (16 + 6)

⇒ Total cost in December 2020 = 99,000

Total selling price in December 2020 = 3600 × 52

⇒ Total selling price in December 2020 = 187,200

Profit = 187,200 – 99,000

⇒ Profit = Rs 88,200

Total profit is 70,000 + 88,200

∴ Total profit is Rs 158,200.

From the above, we don't know the total amount 

From I ratio of Anirudh and Aravind = 15 : 19

From II ratio of Aravind and Aditya  = 8 : 15 

From the above two statements 

The ratio of Anirudh, Aravind, and Aditya = 120 : 152 : 285

From III the difference between Aditya and Anirudh = 6,600

⇒ 285x - 120x = 6,600

⇒ 165x = 6,600

⇒  x = 40

Then aditya total amount = 40 × 285 = 11,400

∴ We require all statements.

Statement II∶

The lion, dog and fox cover distances of 4 m, 12 m, and 3 m respectively in 1 jump.

Statement III∶

Given that the distance covered by the dog in 5 jumps, distance covered by the lion in 15 jumps and distance covered by fox in 20 jumps are equal;

Suppose the distance covered by all three is 60 m (LCM of 5, 15 and 20)

∴ Distance covered by lion in one jump = 60/15 = 4 m

Distance covered by dog in 1 jump = 60/5 = 12 m

Distance covered by fox in 1 jump = 60/20 = 3 m

Here, we can see that statement II and III give the same information.

∴ Combining either statement II or III with the statement I, we can get the answer.

∴ Either statement II or statement III and statement I together are sufficient to answer the question.

From I:

Let the age of A, B and C be a, b, and c respectively.

a + b + c = 15

c > b > a and a > 3

If a = 4, b = 5 and c = 6, the sum of the age of A, B and C is 15. No other case is possible,

So, the ratio of age of A and B will be 4 : 5.

So statement I alone is sufficient.

From II:

Let the age of A, B and C be a, b, and c respectively.

b – c = 2 and a + c = 12

b – c + a + c = 2 + 12

⇒ b + a = 14

But we cannot determine the ratio of age of A and B.

So, Statement II alone is not sufficient.

From III:

Let the age of A, B and D be a, b, and d respectively.

a – d = d - c

⇒ a + c = 2d

⇒ a + c = 2 × 30

⇒ a + c = 30

But we cannot determine the ratio of age of A and B.

Thus, statement III alone is not sufficient.

∴ Only statement I alone is sufficient.

Given,

Tank filled in 20 hours

Tank filled in 40 hours due to leakage.

Let the tank empty in x hours due to leakage.

Tank filled in 1 hour without leakage = (1/20)
Tank empty in 1 hour = (1/x)
Tank filled in 1 hour with leakage = 1/40
According to question
Tank filled in 1 hour with leakage = Tank filled in 1 hour - Tank empty in 1 hour due to leakage

∴ The tank will empty in 40 hours.

Total distance covered by train = Length of bridge + length of train = 655 + 145 

 = 800 m 

= 0.8 km

Time taken = 36 seconds 

= 36/3600 hours 

= 1/100 hours

∴  Speed of train

= 80 km/h

Formula used:
a³ + b³ = (a + b)³ - 3ab(a + b)
a² + b² = (a + b)² - 2ab
Our given equation is 16 (sin⁶θ + cos⁶θ) - 24 (sin⁴θ + cos⁴θ)
= 16 {(sin²θ + cos²θ)³ - 3 sin²θ cos²θ (sin²θ + cos²θ)} - 24 { (sin²θ + cos²θ)² - 2 sin²θ cos²θ}
= 16 (1 - 3 sin²θ cos²θ) - 24 (1 - 2 sin²θ cos²θ)
= 16 - 24 - 48 sin²θ cos²θ + 48 sin²θ cos²θ
= 16 - 24
= -8 
∴ The required value of the given expression is -8.

According to the question:

By selling cloth at Rs. 9 per meter, a shopkeeper loses 10% 

Therefore, Selling Price = 90% of Cost Price

⇒ Cost Price

⇒ Cost Price = 10 Rs. per meter 

To earn a profit of 15% , 

Selling Price = 115% of 10 
⇒ Selling Price = 11.50 Rs. per meter

Given,

Two tap X and Y can fill a Bucket in 36 minutes and 45 minutes respectively.

Another tap Z can empty the bucket in 30 minutes.

After seven minutes of opening X and Y, Z is also opened

If a tap can fill a tank in x hours, then the tank filled by the tap in 1-hour = 1/x of the total tank.

Part of the bucket filled by tap X and Y in 1 minute = 1/36 + 1/45 

= 9/180

= 1/20

Part of the Bucket filled by these pipes in 7 minutes = 7/20 

Remaining unfilled part = 1 - 7/20

= 13/20

When all three taps are opened

Time taken in filling 13/20 part = 13/20 × 60 = 39 minutes

Required time = 39 + 7 = 46 minutes

∴ The bucket will be filled up in 46 minutes.

Interest = Rs. (31,000 - 25,000) 

= Rs. 6,000

Rate

= 12%

Given,
Ratio of Populations of villages X and Y = X ∶ Y = 34 ∶ 43
Ratio of Populations of villages X and Y if the population of village Y increase by 125000 = X ∶ (Y + 125000) = 17 ∶ 24
X ∶ Y = 34 ∶ 43
⇒X/Y = 34/43
⇒ Y = 43X/34
Now,
X ∶ (Y + 125000) = 17 ∶ 24

⇒ 24X = 43X/2 + 2125000
⇒ X = 850000
The population of village Y = 43 X 850000/34 = 1075000
∴ The population of village Y = 1075000

Firoz Shah Tughlaq established the Diwan-i-Bundagan.

Firoz Shah Tughlaq:

• He was the third ruler of the Tughlaq dynasty that ruled over Delhi from 1351 to 1388 AD.
• He established the Diwan-i-Khairat --to take care of orphans and widows. 
• He established the Diwan-i-Bundagan -- department of a slave.
• He is known to establish four new towns, Firozabad, Fatehabad, Jaunpur and Hissar.
• He appointed Khan-i-Jahan Maqbal, a Telugu Brahmin convert as wazir (prime minister).
• The wazir helped the Sultan in his administration and maintained the prestige of the Sultanate during this period.
• Free hospitals and marriage bureaus for poor Muslims were also established. Firoz patronized scholars like Barani and Afif.
• He also developed royal factories called karkhanas in which thousands of slaves were employed. 

An ivory scale in Harappan context was found at Lothal. Lothal is a place associated with Indus Valley Civilization currently in Gujarat.