MAT Mock Test - 6 - MAT MCQ

We put seed, then sprout will grow or develop, then sapling will come out a small plant and then the plant.

So the correct sentence is- I sow a seed I saw the sprout I saw the sapling I saw the plant.

The correct order is: PRSQ

Reason:

• Sentence P will be the first sentence of the sequence because it establishes the fact that they were silent when something passed/went by.
• Pass/went by(phrasal verb) -  to go past.
• For Example - Three buses passed by, but none of them was the right one.
• Sentence R will come after P because it mentions what happened after that thing went by (i.e. it receded). Hence, 'R' follows 'P'.
• Receded(verb) - (of a quality, feeling, or possibility) gradually diminish.
• For Example - The prospects of an early end to the war receded.
• Sentence Q will come after R because it tells about what people did after that thing receded or diminished.
• The sentence 'Q' is the concluding part because it tells what people shouted.

The correct sentence is:

They were silent as it went by and then as it receded 'That's him. What does he want? came their cries.

The correct sentence- Suresh has neither encouraged nor condoned violence.

• Here, 'Suresh has neither' should be used instead of 'Suresh have never'.
• 'Neither' is used in the negative sense when we are presenting things that aren’t true or valid. Neither…nor gives a negative meaning to verbs. 
• And we also know that 'Neither' is always followed by 'nor'.
• Hence, ‘never’ should be replaced with ‘neither’ to form a grammatically correct sentence.
• We know that 'Suresh' is singular and it should be followed by a singular helping verb. Hence, 'has' should be used instead of 'have'.

According to the line of the passage, The amendment is a good step to ease the burden of the depositors.

Once the Bill becomes the law, it will provide immediate relief to thousands of depositors who had their money parked in stressed lenders such as PMC Bank and other small cooperative banks.

All the other options are irrelevant to the passage.

The passage mentions that the 'painter and inventor Jan van der Heyden experimented during the 1660s with oil lamps in glass-paned lanterns.'

 His sophisticated designs for street lamps made Amsterdam the first city to use street lighting.

 The passage states that in London and Westminster, private street-lightning companies contracted with the city to light specific streets.

 So, it was private lighting companies that introduced street lighting in the city of London.

Jeopardize means put (someone or something) into a situation in which there is a danger of loss, harm, or failure.

The meaning of the given words-

• Safeguard means protection from harm or damage with an appropriate measure.
• Spur means give an incentive or encouragement to (someone).
• Conclusive means having or likely to have the effect of proving a case; decisive.
• Adulterate means render (something) poorer in quality by adding another substance.

Clearly, 'safeguard' is the correct answer.

The prospects of the company seemed bright.

Future means prospects i.e., the outlook for the future and hope, possibility, expectation.

A hard nut to crack means a difficult situation or problem to deal with.
Example- A company whose product has sold well in the states may find the European market a tougher nut to crack.

The pattern followed here is:

So, the correct answer is "L".

According to the directions, the diagrams given below can be made-

S denotes starting point and F denotes finishing point.

From the diagrams we can see that, the person is finally facing towards West.

The information given can be represented as follows,

Clearly, the man has walked a total of 20 km (6 + 2 + 2 + 4 + 4 + 2) and he is facing west.

Persons: Pratyush, Zeenat, Rakesh, Esha, Lalit and Girish
i) Zeenat have done films less than only Rakesh.
Rakesh > Zeenat > __ > __ > __ > __
ii) Girish have done five films more than Pratyush.
Girish (x + 5) > Pratyush (x)
iii) Pratyush have done two films less than Esha.
Girish (x + 5) > Esha (x + 2)> Pratyush (x)
iv) Lalit have done films more than Girish.
Lalit > Girish (x + 5) > Esha (x + 2)> Pratyush (x)
v) The least films done by these actors is 50 films.
Rakesh > Zeenat > Lalit > Girish (55) > Esha (52)> Pratyush (50)
So, Lalit have done third highest number of films.

Persons: Pratyush, Zeenat, Rakesh, Esha, Lalit and Girish
i) Zeenat have done films less than only Rakesh.
Rakesh > Zeenat > __ > __ > __ > __
ii) Girish have done five films more than Pratyush.
Girish (x + 5) > Pratyush (x)
iii) Pratyush have done two films less than Esha.
Girish (x + 5) > Esha (x + 2) > Pratyush (x)
iv) Lalit have done films more than Girish.
Lalit > Girish (x + 5) > Esha (x + 2) > Pratyush (x)
v) The least films done by these actors is 50 films.
Rakesh > Zeenat > Lalit > Girish (55) > Esha (52) > Pratyush (50)
So, three persons have done films more than Girish.

(1) Q lives on top floor, in an odd numbered flat.

(Q stays in either flat 1 or flat 3)

(2) T lives in flat number 3, on 3rd floor.

Case 1:

 Case 2:

(3) Only two floors are there between A and D who lives in an even numbered flat.

(4) B and D stay in the same numbered flat and on an odd numbered floor.

Since B and D stays on odd floor, So A stays on top floor and D stays on floor 1.

Case 1:

 Case 2:

(5) U lives on a floor immediately above W.

(6) Neither U nor W lives on the same floor on which T lives.

(7) U does not live in an odd numbered flat.

Therefore, W lives on floor 1.

Case 1:

 Case 2:

(8) Only one floor is there between V and Q.

V lives on floor 2.

(9) C lives immediate below the flat of S who is living on even floor.

(10) C lives in the same numbered flat as A.

Case 1:

 Case 2:

(11) R and S live in the same numbered flat.

W lives on floor 1 (refer point 7)

Thus, case 1 eliminates.

Case 2:

Thus, C and D live on the same floor.

A company would not replace the product if there had been no problem. So, only assumption I is implicit.

Shraddha's mother's father's son (=Shraddha's maternal uncle). Shraddha's maternal uncle is husband of Deepika's sister. Deepika is 'aunt' of Shraddha.

Statement (I):

Total length of bridge = 250 + 330 = 580 m

∴ The statement I alone is not sufficient to answer the question.

Statement (II):

Total distance covered by train = 5 × 60 × 2 = 600 m

Length of train = 600 - 580 = 20 m

∴  Statement II alone is not sufficient. 

∴ Statement I and Statement II together are sufficient, but neither of the two alone is sufficient to answer the question.

Total quantity of mixture A = 500 × 0.2 = 100 L

∴ Quantity of Soda in the mixture A = 100 × 0.45 = 45 L

∴ Cost of soda = 20 × 45 = Rs. 900

In order to get 50% profit,

Amount that should be received = 900 x 150/100 = Rs. 1350

Since total quantity of mixture, A is 100 L;

∴ Selling price at which mixture A must be sold = 1350/100 = Rs. 13.5 per litre

Number of pools in Delhi in 2015 = (100 × 3) – 60 – 140 = 100
Let the number of pools in Goa in 2012 and 2013 be ‘9x’ and ‘10x’ respectively. Then,
9x + 10x + 136 + 140 = 504
⇒ 19x + 276 = 504
⇒ x = 12
So, the number of pools in Goa in 2012 and 2013 are 108 and 120, respectively.
So, number of pools in Delhi in 2012 = 108/2 = 54
Number of pools in Punjab in 2015= 2/3 x 60 = 40
Following the common explanation, we get
Reqd.
= 54/256 x 100 = 21.09%

Number of pools in Delhi in 2015 = (100 × 3) – 60 – 140 = 100
Let the number of pools in Goa in 2012 and 2013 be ‘9x’ and ‘10x’ respectively. Then,
9x + 10x + 136 + 140 = 504
⇒ 19x + 276 = 504
⇒ x = 12
So, the number of pools in Goa in 2012 and 2013 are 108 and 120, respectively.
So, number of pools in Delhi in 2012 = 108/2 = 54
Number of pools in Punjab in 2015 = 2/3 x 60 = 40
Following the common explanation, we get
Required average 
= 156/4 = 39

Quantity I:

Probability of picking 2 balls such that one is green and the other one is blue

Quantity II:

Probability of picking 3 balls such that at least one of them is red

⇒ 0.276

Quantity III:

Probability of picking 3 balls such that at least one of them is blue

⇒ 0.456

Quantity III > Quantity II > Quantity I

From Statement I:
The time taken by Misha = 12 - 7 = 5 hours
Time taken by Misha’s brother = 11:30 - 8:00 = 3.5 hours
Thus, the ratio of time
= 5 : 3.5
= 10 : 7
Speed = inversely proportional to time
∴ ratio of Speed = 7 : 10
Let the distance between the house and office = 70 km
Then Misha’s speed = 70/7 = 10 km/h
Misha’s brother’s speed = 70 = 7 km/h
∴ Statement I alone is sufficient.
From Statement II:
Speed of Misha’s brother = 14 km/h
This doesn’t help in finding the answer.
∴ Statement II alone is not sufficient.
Thus, The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.

Given:

Time taken by (A + B) = 6 days

Time taken by (B + C) = 10 days

Time taken by (A + C) = 12 days

Let total work be 60 units (L.C.M of 6, 10, 12)

(A + B)'s efficiency per day= 10 units

(B + C)'s efficiency per day = 6 units

(A + C)'s efficiency per day = 5 units

Adding all three we get

2(A + B + C) = 21 units

(A + B + C) = 10.5 units

(A + B + C) - (B + C) = 10.5 - 6 

⇒ A's efficiency = 4.5 units

Time taken by A to complete the work   days

Given:

We have to find 15% of Rs. 34

As X is 25% more than Y

∴ If Y = 100 then X = 125

Thus Y is less than X by 25 where X is 125.

⇒ Percentage by which Y is less than X = (25/125) × 100 = 20%

Given:

A sum amounts to Rs. 6,050 in 2 years and to Rs. 6,655 in 3 years at a certain rate percentage p.a. when the interest is compounded yearly.

As we know, that

Simple interest = PNR/100 

Compound interest

Where,

P = Principal

R = rate of interest and 

N = time period

Accordingly,

And,

Dividing,

Simple interest on a sum of Rs. 6,000 at the same rate for years

⇒ Rs.3450

∴ Required simple interest is Rs. 3450.

Given:

Number of persons = 4

Initial time to complete the work = 40 days

Final time to complete the work = 50 days

Total work done = Number of persons × Time taken

Total work = 10 × 40 = 400 units

Let 4 persons leave after x days

So, remaining persons will complete the work in (50 – x) days

Total work = (10 × x) + 6(50 – x)

= 10x + 300 – 6x

= 4x + 300

Now, according to question,

400 = 4x + 300

⇒ 4x = 100

⇒ x = 25

∴ The four persons will leave after 25 days

Given:

If 658 bags are divided into three parts, proportional to

Third part

Ratio

Sum of the ratio

Third part = 126

Given:

Pipe P's 1 hour's work = 1/15

Pipe Q's 1 hour's work = 1/20

Pipe R's 1 hour's work = 1/40

Pipe P's 4 hours work = 4 x 1/15 = 4/15

Pipe (P + Q)’s 1 hours work = 1/15 + 1/20 = 7/60

Pipe (P + Q)’s 2 hours work = 2 x 7/60 = 7/30

Total work done in 6 hours = 4/15 + 7/30 = 1/2

Remaining work = 1 - 1/2 = 1/2

Pipe (P + Q + R)’s 1 hour's work = 1/15 + 1/20 - 1/40 = 11/120

Time taken by three taps to fill the half of the tank = 1/2 x 120/11 = 60/11 hours

∴ Total time taken to empty the tank = 4 + 2 + 60/11

= 126/11 hours

Given:
A sum doubles in 10 years at simple interest

Formula used:
Simple Interest (SI)
Where P = Principal
R = Rate of interest
t = Time
Let the principal be P, rate be R%, time be T and amount be A.
According to question,

⇒ R = 100/10
Now,

⇒ T = 30
∴ The required time is 30 years.