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Olympiad Test: Comparing Quantities - Class 7 MCQ


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20 Questions MCQ Test Mathematics (Maths) Class 7 - Olympiad Test: Comparing Quantities

Olympiad Test: Comparing Quantities for Class 7 2025 is part of Mathematics (Maths) Class 7 preparation. The Olympiad Test: Comparing Quantities questions and answers have been prepared according to the Class 7 exam syllabus.The Olympiad Test: Comparing Quantities MCQs are made for Class 7 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Comparing Quantities below.
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Olympiad Test: Comparing Quantities - Question 1

In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 1

3 computers are used by 6 students.

To determine the number of computers needed:

  • Each computer serves 2 students (6 students / 3 computers).
  • For 24 students, the calculation is:
  • 24 students / 2 students per computer = 12 computers.
Olympiad Test: Comparing Quantities - Question 2

Out of 32 students, 8 are absent. What percent of the students are present?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 2

Solution:

To find the percentage of students who are present, follow these steps:

  • Calculate the number of students present:
    • Total students: 32
    • Absent students: 8
    • Present students = 32 - 8 = 24
  • Calculate the percentage of present students:
    • Percentage = (Present students / Total students) × 100
    • Percentage = (24 / 32) × 100 = 75%

Thus, 75% of the students are present.

Olympiad Test: Comparing Quantities - Question 3

There are 25 radios, 16 of them are out of order. What percent of radios are out of order?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 3

Solution:

The number of radios that are out of order is 16.

To find the percentage of radios that are out of order, use the following formula:

  • Percentage = (Number of radios out of order / Total number of radios) × 100

Substituting the values:

  • Percentage = (16 / 25) × 100 = 64%

Thus, 64% of the radios are out of order.

Olympiad Test: Comparing Quantities - Question 4

A shop has 500 parts, out of which 5 are defective. What percent are not defective?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 4

Solution:

To find the percentage of items that are not defective:

  • First, calculate the percentage of defective items:
  • Defective items: 5 out of 500
  • Percentage of defective items = (5 / 500) × 100 = 1%

Next, determine the percentage of items that are not defective:

  • Percentage of not defective items = 100% - 1% = 99%
Olympiad Test: Comparing Quantities - Question 5

There are 120 voters, 90 of them voted yes. What percent voted yes?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 5

To find the percentage of voters who voted yes:

  • Start with the number of voters who voted yes: 90.
  • Divide this number by the total number of voters: 120.
  • Calculate the fraction: 90/120.
  • To convert this fraction to a percentage, multiply by 100: (90/120) x 100%.
  • Simplifying the fraction gives 3/4.
  • Now, calculate: 3/4 x 100% = 75%.

Thus, 75% of the voters voted yes.

Olympiad Test: Comparing Quantities - Question 6

A survey of 40 children showed that 25% liked playing football. How many children not liked playing football?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 6

Total number of children: 40

Percentage of children who like football: 25%

To find the number of children who do not like playing football:

  • Calculate the percentage of children who do not like football: 100% - 25% = 75%
  • Now, find 75% of the total number of children:
  • Number of children who do not like football = 75% of 40
  • Calculation: (75/100) * 40 = 30

Therefore, 30 children do not like playing football.

Olympiad Test: Comparing Quantities - Question 7

8% children of a class of 25 like getting wet in the rain. How many children do not like getting wet in the rain.

Detailed Solution for Olympiad Test: Comparing Quantities - Question 7

Number of children that like getting wet in rain = 8% of 25
= 8/100 × 25
= 8/4
= 2 children.
Number of children that don't like getting wet in rain
= 25 - 2
= 23 children
Therefore, there are 23 such students that don't like getting wet in rain.
 

Olympiad Test: Comparing Quantities - Question 8

Rahul bought a sweater and saved Rs 20 when a discount of 25% was given. What was the price of the sweater before the discount?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 8

Solution:

Rahul saved Rs 20 due to a 25% discount on the sweater. To find the original price:

  • Let the original price be x.
  • The discount can be expressed as:
    • 25% of x = Rs 20
  • This translates mathematically to:
    • 25/100 * x = 20
  • By rearranging, we get:
    • 25x = 2000
    • x = 2000 / 25
    • x = Rs 80

Thus, the original price of the sweater was Rs 80.

Olympiad Test: Comparing Quantities - Question 9

Out of 15,000 voters in a constituency, 60% voted. Find the number of voters who did not vote.

Detailed Solution for Olympiad Test: Comparing Quantities - Question 9

To find the number of voters who did not vote:

  • Total voters in the constituency: 15,000
  • Percentage of voters who voted: 60%
  • Number of voters who voted: 15,000 × 60% = 9,000
  • Number of voters who did not vote: 15,000 - 9,000 = 6,000

Therefore, the number of voters who did not vote is 6,000.

Olympiad Test: Comparing Quantities - Question 10

Meeta saves Rs 400 from her salary. If this is 10% of her salary. What is her salary?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 10

Meeta saves Rs 400 from her salary. If this is 10% of her salary, what is her salary?

To find Meeta's salary, we can use the following steps:

  • Identify the percentage: Rs 400 is 10% of her salary.
  • Set up the equation: 10% of salary (x) = 400.
  • Convert percentage to decimal: 10% = 10/100 = 0.1.
  • Write the equation: 0.1 * x = 400.
  • Solve for x: x = 400 / 0.1.
  • Calculate: x = 4000.

Therefore, Meeta's salary is Rs 4000.

Olympiad Test: Comparing Quantities - Question 11

A local cricket team played 20 matches in one season. It won 25% of them. How many matches did they lose?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 11

Percentage of matches won: 25%

Percentage of matches lost: 100% - 25% = 75%

Number of matches lost:

  • Calculate 75% of 20 matches:
  • 75% of 20 = (75/100) x 20
  • Result: 15 matches lost.
Olympiad Test: Comparing Quantities - Question 12

A school team won 6 games this year against 4 games won last year. What is the percent increase?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 12

To calculate the percentage increase in the number of games won by the school team:

  • The team won 6 games this year.
  • Last year, they won 4 games.
  • To find the increase in wins: 6 - 4 = 2.
  • Next, calculate the percentage increase using the formula:
    • Percentage Increase = (Amount of Change / Original Amount) × 100
  • Substituting the values:
    • Percentage Increase = (2 / 4) × 100 = 50%

The percentage increase in the number of games won is 50%.

Olympiad Test: Comparing Quantities - Question 13

The number of illiterate persons in a country decreased from 150 lakhs to 100 lakhs in 10 years. What is the percentage of decrease?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 13

Percentage of decrease can be calculated using the formula:

  • Change in illiterate people = Initial number - Final number
  • In this case: 150 lakhs - 100 lakhs = 50 lakhs

Now, apply the formula for percentage of decrease:

  • Percentage of decrease = (Change in illiterate people / Original amount) × 100
  • Substituting the values: (50 lakhs / 150 lakhs) × 100
  • This simplifies to: (50 / 150) × 100 = 33.33%

Thus, the percentage of decrease in the number of illiterate persons is 100/3%.

Olympiad Test: Comparing Quantities - Question 14

Cost of an item is Rs 50. It was sold with a profit of 12%. Find the selling price.

Detailed Solution for Olympiad Test: Comparing Quantities - Question 14

Cost of an item is Rs 50. It was sold with a profit of 12%. Find the selling price.

To find the selling price (SP) when the cost price (CP) is Rs 50 and the profit is 12%, follow these steps:

  • Calculate the profit amount: Profit = CP × (Profit Percentage / 100)
  • Substituting the values: Profit = 50 × (12 / 100) = 6
  • Now, add the profit to the cost price to find the selling price: SP = CP + Profit
  • Thus, SP = 50 + 6 = Rs 56

The selling price of the item is Rs 56.

Olympiad Test: Comparing Quantities - Question 15

How much will an item cost if 10% discount is given on the marked price Rs 100?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 15

Solution:

To calculate the cost of an item after a 10% discount on the marked price of Rs 100, follow these steps:

  • Determine the discount amount: 10% of Rs 100.
  • Calculate the discount:
    • Discount = 10/100 × 100 = Rs 10
  • Subtract the discount from the marked price:
    • Cost after discount = Rs 100 - Rs 10 = Rs 90

Thus, the final cost of the item is Rs 90.

Olympiad Test: Comparing Quantities - Question 16

A football team won 10 matches out of the total number of matches they played. If their win percentage was 40, then how many matches did they play in all?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 16

Olympiad Test: Comparing Quantities - Question 17

If Chameli had Rs 600 left after spending 75% of her money, how much did she have in the beginning?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 17

Solution:

Chameli has Rs 600 left after spending 75% of her money. This means:

  • She retains 25% of her total amount.
  • Thus, 600 equals 25% of her initial amount.

To find the original amount (let's call it x), we can set up the equation:

  • 25% of x = 600
  • Which can be expressed as: (25/100) * x = 600

Now, solving for x:

  • Multiply both sides by 4 (since 100/25 = 4):
  • x = 600 * 4 = Rs 2400

Therefore, Chameli initially had Rs 2400.

Olympiad Test: Comparing Quantities - Question 18

The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 18

Price of the scooter last year: Rs 34,000

Increase: 20%

The amount of increase can be calculated as follows:

  • 20% of Rs 34,000 = Rs 6,800

To find the new price:

  • New Price = Last Year Price + Amount of Increase
  • New Price = Rs 34,000 + Rs 6,800
  • New Price = Rs 40,800

Therefore, the current price of the scooter is Rs 40,800.

Olympiad Test: Comparing Quantities - Question 19

The price of a scooter was Rs 34,000 last year. It has decreased by 5% this year. What is the price now?

Detailed Solution for Olympiad Test: Comparing Quantities - Question 19

Solution:

The price of the scooter last year was Rs 34,000. This year, it has decreased by 5%. To find the current price, follow these steps:

  • Calculate the amount of decrease: 5% of Rs 34,000.
  • Use the formula: Decrease = (5/100) × 34,000 = Rs 1,700.
  • Subtract the decrease from the original price: Rs 34,000 - Rs 1,700 = Rs 32,300.

Therefore, the current price of the scooter is Rs 32,300.

Olympiad Test: Comparing Quantities - Question 20

Mohit bought a CD for Rs. 750 and sold it Rs. 875. Find his gain or loss percent.

Detailed Solution for Olympiad Test: Comparing Quantities - Question 20

Solution:

To find the gain percentage, we can use the following steps:

  • Calculate the gain by subtracting the cost price (CP) from the selling price (SP):
  • Gain = SP - CP
  • In this case:
  • Gain = 875 - 750 = 125

Next, we calculate the gain percentage using the formula:

  • Gain Percentage = (Gain / CP) × 100
  • Substituting the values:
  • Gain Percentage = (125 / 750) × 100
  • This simplifies to:
  • Gain Percentage = (1/6) × 100 ≈ 16.67%

Thus, the gain percentage is approximately 16.67%.

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