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Olympiad Test: Simple Equations - Class 7 MCQ


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20 Questions MCQ Test Mathematics (Maths) Class 7 - Olympiad Test: Simple Equations

Olympiad Test: Simple Equations for Class 7 2025 is part of Mathematics (Maths) Class 7 preparation. The Olympiad Test: Simple Equations questions and answers have been prepared according to the Class 7 exam syllabus.The Olympiad Test: Simple Equations MCQs are made for Class 7 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Simple Equations below.
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Olympiad Test: Simple Equations - Question 1

Write the statement “p multiplied by 16” in the form of expression.

Detailed Solution for Olympiad Test: Simple Equations - Question 1

Solution:

  • To express "p multiplied by 16", we write it as 16p.
  • This indicates that p is being multiplied by 16.

The correct expression is therefore 16p.

Olympiad Test: Simple Equations - Question 2

Write the statements “2 subtracted from a number is 8”in the form of equations:

Detailed Solution for Olympiad Test: Simple Equations - Question 2

Number is x. When two is subtracted from it, we write this as x - 2. This expression equals 8. Therefore, the equation is:

x - 2 = 8.

Olympiad Test: Simple Equations - Question 3

Write the statements “Seven times a number plus 7 gets you 77”in the form of equations:

Detailed Solution for Olympiad Test: Simple Equations - Question 3

Seven times a number plus 7 gets you 77 can be expressed as an equation:

  • The equation is 7x + 7 = 77.

To break this down:

  • 7x represents seven times a number.
  • Adding 7 to that gives us the total.
  • Setting this equal to 77 completes the equation.
Olympiad Test: Simple Equations - Question 4

Write the statements “If you take away 6 from 6 time a number, you get 60”in the form of equations:

Olympiad Test: Simple Equations - Question 5

Write the statements “If you add 3 to one-third of a number, you get 30”in the form of equations:

Detailed Solution for Olympiad Test: Simple Equations - Question 5

One third of a number is represented as (1/3)x.

When you add 3 to this, it becomes:

  • (1/3)x + 3

This sum equals 30, leading to the equation:

  • (1/3)x + 3 = 30

To isolate x, subtract 3 from both sides:

  • (1/3)x = 30 - 3
  • (1/3)x = 27

Next, multiply both sides by 3 to solve for x:

  • x = 27 × 3
  • x = 81

Thus, the equation (1/3)x + 3 = 30 is correctly formed.

Olympiad Test: Simple Equations - Question 6

The solution of the equation p + 4 = 15 is p =

Detailed Solution for Olympiad Test: Simple Equations - Question 6

Solution:

To solve the equation p + 4 = 15, follow these steps:

  • Start with the equation: p + 4 = 15
  • Subtract 4 from both sides:
  • p = 15 - 4
  • Calculate the right side:
  • p = 11

The solution is p = 11.

Olympiad Test: Simple Equations - Question 7

The solution of the equation m – 7 = 3 is m =

Detailed Solution for Olympiad Test: Simple Equations - Question 7

X-7 = 3
X = 3+7
ans. Is x = 10

Olympiad Test: Simple Equations - Question 8

The solution of the equation 2m = 7 is

m =

Detailed Solution for Olympiad Test: Simple Equations - Question 8

Solution:

To solve the equation, we can break it down step by step:

  • Let m be the variable we are solving for.
  • The equation states that two times m equals seven.
  • To isolate m, we divide both sides of the equation by 2.

This gives us:

  • m = 7 / 2

Thus, the solution to the equation is:

  • m = 3.5
Olympiad Test: Simple Equations - Question 9

The solution of the equation x/5=3 is x =

Olympiad Test: Simple Equations - Question 10

The solution of the equation 3m/5=6 is m =

Detailed Solution for Olympiad Test: Simple Equations - Question 10

Solution:

To solve the equation 3m/5 = 6, follow these steps:

  • First, multiply both sides by 5 to eliminate the fraction:
  • 3m = 6 * 5
  • This simplifies to 3m = 30.

Next, divide both sides by 3:

  • m = 30 / 3
  • This gives m = 10.

Thus, the solution to the equation is m = 10.

Olympiad Test: Simple Equations - Question 11

The solution of the equation (a/2)+2=8 is a =

Detailed Solution for Olympiad Test: Simple Equations - Question 11

Solution:

To solve the equation (a/2) + 2 = 8, follow these steps:

  • Start with the equation: (a/2) + 2 = 8
  • Subtract 2 from both sides to isolate the term with a:
    • a/2 = 6
  • Multiply both sides by 2 to solve for a:
    • a = 12

The solution to the equation is a = 12.

Olympiad Test: Simple Equations - Question 12

By solving the equation 2a - 2 = 20, the value of 'a' will be

Detailed Solution for Olympiad Test: Simple Equations - Question 12

Solution:

To solve the equation, follow these steps:

  • Start with the equation: 2a - 2 = 20.
  • Add 2 to both sides to isolate the term with a:
  • 2a = 20 + 2
  • This simplifies to 2a = 22.
  • Now, divide both sides by 2:
  • a = 22 / 2
  • This results in a = 11.

Thus, the value of a is 11.

Olympiad Test: Simple Equations - Question 13

The solution of the equation 4m – 2 = 18 is m =

Detailed Solution for Olympiad Test: Simple Equations - Question 13

Solution:

To solve the equation 4m - 2 = 18, follow these steps:

  • Start with the equation: 4m - 2 = 18.
  • Add 2 to both sides to isolate the term with m:
    • 4m = 18 + 2
    • 4m = 20
  • Next, divide both sides by 4 to solve for m:
    • m = 20 / 4
    • m = 5

The solution is m = 5.

Olympiad Test: Simple Equations - Question 14

The solution of the equation 3x + 7 = 25 is x =

Detailed Solution for Olympiad Test: Simple Equations - Question 14

The sum of three times a number and 11 is 32. Find the number.

Let the unknown number be x. The equation can be set up as follows:

  • Three times the number: 3x
  • The equation: 3x + 11 = 32

To solve for x, follow these steps:

  • Subtract 11 from both sides:
    • 3x = 32 - 11
    • 3x = 21
  • Now, divide both sides by 3:
    • x = 21 / 3
    • x = 7

The required number is 7. You can check this by calculating:

  • 3 times 7 + 11 = 21 + 11 = 32
Olympiad Test: Simple Equations - Question 15

The solution of the equation 2b – 1 = 23 is b =

Detailed Solution for Olympiad Test: Simple Equations - Question 15

Solution:

To solve the equation 2p - 1 = 23, follow these steps:

  • First, add 1 to both sides:
    • 2p - 1 + 1 = 23 + 1
    • This simplifies to 2p = 24.
  • Next, divide both sides by 2:
    • 2p / 2 = 24 / 2
    • This gives us p = 12.

To verify, substitute p = 12 back into the original equation:

  • Left-hand side: 2p - 1 = 2 × 12 - 1 = 24 - 1 = 23
  • Right-hand side: 23

Since both sides are equal, the solution is confirmed as p = 12.

Olympiad Test: Simple Equations - Question 16

The solution of the equation 20m/3 = 40 is m =

Detailed Solution for Olympiad Test: Simple Equations - Question 16

 

Olympiad Test: Simple Equations - Question 17

The solution of the equation 3a/10=6 is a =

Detailed Solution for Olympiad Test: Simple Equations - Question 17

To solve the equation:

  • Start with the equation: 3a/10 = 6.
  • Multiply both sides by 10 to eliminate the fraction:
    • 3a = 10 * 6
    • 3a = 60
  • Now, divide both sides by 3:
    • a = 60 / 3
    • a = 20

The solution is a = 20.

Olympiad Test: Simple Equations - Question 18

The solution of the equation 3z – 2 = 46 is z =

Detailed Solution for Olympiad Test: Simple Equations - Question 18

To solve the equation 3z – 2 = 46:

  • First, add 2 to both sides to isolate the term with z:
    • 3z – 2 + 2 = 46 + 2
    • This simplifies to 3z = 48.
  • Next, divide both sides by 3 to solve for z:
    • 3z / 3 = 48 / 3
    • This gives z = 16.

The solution to the equation is z = 16.

Olympiad Test: Simple Equations - Question 19

The solution of the equation 5x + 7 = 17 is x =

Detailed Solution for Olympiad Test: Simple Equations - Question 19

The solution of the equation 5x + 7 = 17 is x =

To solve the equation, follow these steps:

  • Start with the equation: 5x + 7 = 17.
  • Subtract 7 from both sides to isolate the term with x:
    • 5x + 7 - 7 = 17 - 7
    • This simplifies to: 5x = 10.
  • Next, divide both sides by 5 to solve for x:
    • 5x / 5 = 10 / 5
    • This gives: x = 2.

To verify the solution, substitute x back into the original equation:

  • 5(2) + 7 = 10 + 7 = 17, which matches the right-hand side.

Thus, the solution is confirmed as correct: x = 2.

Olympiad Test: Simple Equations - Question 20

The sum of three times a number and 11 is 32. Find the number.

Detailed Solution for Olympiad Test: Simple Equations - Question 20

Three times a number plus 11 equals 32.

To find the number, follow these steps:

  • Let the unknown number be x.
  • The equation can be written as: 3x + 11 = 32.
  • Subtract 11 from both sides to isolate 3x: 3x = 32 - 11.
  • This simplifies to: 3x = 21.
  • Now, divide both sides by 3: x = 21 / 3.
  • Thus, x = 7.

The required number is 7. You can verify this by calculating 3 times 7 plus 11, which equals 32.

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