Test: Knowing Our Number- 1 - Class 6 MCQ

• We know that the greatest 3-digit number is 999.
• When one is added to the  greatest 3-digit number we get the smallest 4-digit number i.e.,
  ► 999 + 1 = 1000
• So option D is the correct answer. 

We know that the greatest 2 digit number is 99.

When 1 is added to greatest 2 digit number i.e,

► 99 + 1 = 100 

we get smallest 3 digit number.

So option A is the correct answer. 

• The greatest 4 digit number is 9999 and the smallest 4 digit number is 1000.
• So option C is the correct answer. 

• The smallest 5 digit number is 10,000. On subtracting 1 from the smallest 5-digit number,
  ► 10,000 - 1 = 9999
• 9999 is the greatest 4 digit number. So Option C is the correct answer. 

The smallest 4-digit number is 1000

On subtracting 1 from smallest 4-digit number , we get

► 1000 - 1 = 999

which is greatest 3 digit number. 

So Option A is the correct answer. 

We know, smallest 3 digit number is 100

On subtracting 1 from smallest 3 digit number 

We get,

► 100 -1 = 99

which is greatest 2 digit number.
So option C is the correct answer. 

500428 in expanded form will be:
► 500428 = 500000 + 400 + 20 + 8 
That is five lakh four hundred twenty eight.

345600 in expanded form will be : 

► 345600 = 300000 + 40000 + 5000 + 600 

i.e. Three lakh forty five thousand six hundred.

► 204560 = 2,00,000 + 4,000 + 500 + 60 

i.e,  Two lakh four thousand five hundred sixty. 

Therefore, Option A is the correct answer

987500 in expanded form will be :

► 987500 = 900000 + 80000 + 7000 + 500

i.e, nine lakh eighty-seven thousand five hundred

Greatest 6-digit number is 999,999 

On adding 1 to  greatest 6-digit number we get,

► 999,999 + 1 = 1000000

i.e, smallest 7-digit number.

So, option C is the correct answer. 

Greatest 5-digit number is 99999

On adding 1 to greatest 5-digit number we get

► 99999 + 1 = 10,0000

which is smallest 6 digit number . 

So option D is the correct answer. 

The greatest 4-digit number is 9999 on adding 1 to greatest 4-digit number we get 

► 9999 + 1 = 10,000

which is smallest 5 digit number.

So option A is the correct answer. 

As the greatest 3-digit number is 999

So on adding 1 to  greatest 3-digit number 

We get ,

► 999 + 1 = 1000

which is smallest 4 digit number . 

So option A is the correct answer. 

The greatest 2-digit number is 99

on adding 1 to the greatest 2-digit number we get, 

►  99 + 1 = 100

which is smallest 3 digit number. 

• The largest 7-digit number is 99,99,999.
• The successor of 99,99,999
  = 99,99,999 + 1 = 1,00,00,000.
• So, 1,00,00,000 is the smallest 8-digit number which is called one crore.

100 lakhs (or 1 crores) is therefore equal to 10 million. 

The numeral for the number Nine crore five lakh forty-one is: 
► 9,00,00,000 + 5,00,000 + 40 + 1 = 90500041

1 million = 1,000,000 which is equal to 10 lakhs.

We have to find the least number that is divisible by all numbers from 1 to 10.

∴ LCM (1 to 10) = 2³ × 3² × 5 × 7
= 2520

Thus, 2520 is the least number that is divisible by every element and is equal to the least common multiple.