SSC CGL (Tier II) Practice Test - 7 - SSC CGL MCQ

Old wage bill = 9x × 14y = 126xy

New wage bill = 8x × 15y = 120xy

Required ratio = 126xy : 120xy = 21 : 20

Hence, answer option 2 is correct.

Thus, the value of W is equal to Q and the value of T is equal to S.

Hence, this is the correct answer.

Son's share = 2x/3

Daughter's share = 5x/4

According to the question:

= 11,50,000

x = Rs. 6,00,000

Son's share = = Rs. 4,00,000 = Rs. 4 lakh

So, (k - 1)/(2 - k) = 1/(-3)

Or, -3k + 3 = 2 - k

Or, -2k = -1

Or, k = 1/2

2 × 10 + 5 = 25

2 × 25 + 6 = 56

2 × 56 + 7 = 119

2 × 119 + 8 = 246

2 × 246 + 9 = 501

Hence, option (3) is the correct answer.

Monthly income of A = Rs. 2x

Savings of A = 5,000 × 4/(4 + 1) = Rs. 4,000

Savings of B = Rs. 1,000

6x - 12,000 = 5x - 5,000

x = Rs. 7,000

Average speed =

= 22.5 km/hr

8 = 2^n/5

2³ = 2^n/5

n/5 = 3

n = 15 years

∴ Expression =

= 0.125

Annual savings = Rs. 5320

Annual income = Rs. (32,900 + 5320) = Rs. 38,220

Average monthly income = Rs.38,220 ÷ 12 = Rs. 3185

Work done by A in one day = 1/6

Work done by B in one day = 1/12

Work done by A and B together in one day =

Number of days required to finish pending work =

T₂ = (1 + 1²) × 1 = 2

T₃ = (2 + 3²) × 3 = 33

T₄ = (33 + 5²) × 5 = 290

T₅ = (290 + 7²) × 7 = 2373

T₆ = (2373 + 9²) × 9 = 22086

In triangle BDC,

Base = 40 m

Now, in triangle ABC,

40√3 - 40 = x

x = 40(√3 - 1) m

Then, S.P. = 0.6 × M.P. = 0.6 × n × C.P. ...(i)

Also, S.P. = 0.7 × C.P. ...(ii)

From (i) and (ii),

0.6 × n × C.P. = 0.7 × C.P.

So, n = 7/6

Therefore, M.P. = 7/6 × C.P. = New S.P.

Hence, profit % =

= 100/6% =

According to the question,

729 = x(1 – 10/100)³

Or, 729 = x (9/10)³

Or, x = Rs. 1000

Arun's salary increased in 2014 by (12500 - 10000) = Rs 2500

So the percentage increased in 2014 by (2500 / 10000) × 100 = 25%

Arun's salary increased in 2015 by (14670 - 12500) = Rs 2170

So the percentage increased in 2015 by (2170 / 12500) × 100 = 17.36%

Arun's salary increased in 2016 by (17890 - 14670) = Rs 3220

So, the percentage increased in 2016 by (32200 / 14670) × 100 = 21.9%

In 2014 Arun's salary increased the highest percentage in respect of the previous year.

Let the number of total coins of 50p, 25p, and 10p denominations be 2a, 3a, and 5a.

According to the question-

Total monetary value of coins is ₹ 90

⇒ 0.5 × 2a + 0.25 × 3a + 0.1 × 5a = ₹ 90

⇒ 1a + 0.75a + 0.5a = ₹ 90

⇒ 2.25a = ₹ 90

Coins of 25p denomination = 3 × 40 = 120

The coins of 25p denomination were 120.

The numbers are between 120 and 519

they are exactly divisible by both 3 and 7

Concept used:

The number divisible by both 3 and 7 is divisible by 21

(LCM of 3 and 7)

Calculation:

The total numbers divisible by 21 in between 1 and 120 is

⇒ 120 / 21 = 5

The total numbers divisible by 21 in between 1 and 519 is

⇒ 519 / 21 = 24

So total number that is divisible by 21 between 120 and 519 is

(24 - 5) = 19

So, the total number is 19

If N is divided b/w A, B & C in the ratio a : b : c then

Share of A = [a/(a+b+c)] × N

Share of B = [b/(a+b+c)] × N

Share of C = [c/(a+b+c)] × N

Calculation:

Given ratio is ½ : ¼ : 5/16

LCM of (2, 4, 16) = 16

Multiply the given ratio with 16

⇒ 8 : 4 : 5 :: A : B : C

Greatest part = 8/(8 + 4 + 5) = 8/17

Smallest part = 4/(8 + 4 + 5) = 4/17

Therefore, the required difference

⇒ (4/17) × 68000 = 16000

∴ The difference between the greatest part and the smallest part is Rs. 16000.

Three coins are tossed simultaneously.

Outcome should be all heads.

Concept used:

The probability of the occurrence of an event A is given by: P(A) = n(A)/N, where n(A) is the number of ways of occurring of event A and N is the total number of ways in which the event can occur.

The number of ways in which r objects can be selected out of n objects = nCr = n!/{r!(n − r)!}.

n! = 1 × 2 × … × n.

0! = 1.

Calculation:

Total number of possible outcomes in tossing 3 coins = N = 2 × 2 × 2 = 8.

Total number of ways of getting 3 heads = ³C₃ = 3!/{3!(3 − 3)!} = 1.

Required probability = 1/8.

∴ The probability of getting all heads is 1/8.

Let the two-digit number be (10x + y)

According to the question,

⇒ (10x + y)² - (10y + x)²

⇒ 100x² + y² + 20xy - 100y² - x² - 20xy

⇒ 99x² - 99y² = 99(x² - y.)

As 99 is divisible by both 9 and 11

So, the result is also divisible by 9 and 11

∴ The correct answer is both 9 and 11

Calculation:

Using Venn Diagram we get,

Considering the universal set to be 100%.

Percentage of those who're only Rice eater = 65 - 25 = 40%

Percentage of those who're only Wheat eater = 40 - 25 = 15%

Now, the percentage of those who're neither rice eaters nor wheat eaters

⇒ 100 - 40 - 15 - 25 = 20%

∴ The percentage of people neither rice eaters nor wheat eaters is 20%.

Concept used:Volume of a cuboid = Length × Breadth × Height

Final discount percentage after two successive discounts of A% and B%

Calculation:Initial volume of the cuboid = 20 × 5 × 25 = 2500 m3

Revised length = 20 + 20 × 25% = 25 m

Revised breadth = 5 + 5 × 15% = 5.75 m

Revised height = 25 - 25 × 10% = 22.5 m

Final volume = 25 × 5.75 × 22.5 = 3234.375 m³

Now, % increase

⇒ 29.375% ≈ 29.38%

∴ The corresponding increase in the volume of the cuboid is 29.38%.

Expenses of α = 7y & β = 3y

Savings of each = 4500/-

We know that-

Savings = (income – expenses) → (expenses + Savings) = income

Then

= α = 7y + 4500 = 9x ……………(i)

= β = 3y + 4500 = 4x …………(ii)

= 4 (7y + 4500) = 9 (3y + 4500)

= 28y + 18000 = 27y + 40500

= 28y -27y = 40500 – 18000

= y = 22500

so the expenditure of β = 3y

= 3 × 22500 = 67,500/-

Distance between Kanpur and Allahabad = 250 km

Cruise Speed in still water(v) = 40 km/hr

Time taken when goes downstream = 5 hours

Formula used:-

Time = Distance/Speed

Calculation:-

Let the stream velocity be u,

When goes downstream,

Relative speed = v + u = 40 + u

⇒ 5 = 250/(40 + u)

⇒ 200 + 5u = 250

⇒ u = 50/5 = 10 km/hr = Speed of stream

When goes upstream,

Relative speed = v - u = 40 - 10 = 30 km/hr

∴ Time = 250/30

Time = 8.34 hours

Time is taken = 8.34 × 60 = 500 mins

The total number of visitors = 400

Calculation:

According to the question,

Number of visitors on Tuesday = 30% of 400 = 120

Number of male visitors on Tuesday

Number of visitors on Wednesday = 45% of 400 = 180

Number of female visitors on Wednesday

The required ratio = 50 : 100 = 1 : 2

Therefore, '1 : 2' is the required answer.

here, l = slant height of cylinder

r = radius of cylinder

h = height of cylinder

⇒ Total remaining surface area = 2πrh + πr² + πrl

⇒ 2π × 8 × 15 + π × 64 + π × 136

⇒ 440π cm²

(a² - b²)sinθ + 2abcosθ = a² + b²

Formula used:-

sin(A + B) = sinA.cosB + cosA.sinB

Calculation:-

From Triangle ABC,

⇒ cosα.sinθ + sinα.cosθ = 1

⇒ sin(θ + α) = sin90^o

⇒ θ + α = 90

⇒ θ = 90 - α

Taking tan both sides-

⇒ tanθ = tan(90 - α) = cotα

A seller sells a bat at 40% profit.

If he bought it at 20% more and sold it for 120 more there will be 100% profit earned.

Concept used:

SP = CP + Profit

Profit percentage = (Net profit / CP) × 100

Calculation:

Let the CP is Rs 100. So,

SP = 100 + (40/100) × 100

⇒ 100 + 40 = 140

So the new CP is

100 + (20/100) × 100

⇒100 + 20 = Rs 120

New SP = 120 + 120

⇒ Rs 240

So, as per the question

(SP - CP) = 100%

Rs (240 – 120) = 100%

⇒ 100 % = Rs 120

So the cost price of the bat is Rs 120.

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

⇒ 24/5 + 31/15 - 27/5 = 11/5 ÷ 3 × k

⇒ (24 × 3 + 31 - 27 × 3)/15 = 11/15 × k

⇒ (72 + 31 - 81)/15 = 11/15 × k

⇒ 22/15 = 11/15 × k

⇒ k = 22/11 = 2.