NEET Minor Test - 2 - NEET MCQ

# NEET Minor Test - 2 - NEET MCQ

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## 180 Questions MCQ Test NEET Mock Test Series 2025 - NEET Minor Test - 2

NEET Minor Test - 2 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Minor Test - 2 questions and answers have been prepared according to the NEET exam syllabus.The NEET Minor Test - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Minor Test - 2 below.
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NEET Minor Test - 2 - Question 1

### An electric lift with a maximum load of 2000kg (lift + passengers) is moving up with a constant speed of 1.5ms−1. The frictional force opposing the motion is 3000N. The minimum power delivered by the motor to the lift in watts is : (g=10ms−2)

Detailed Solution for NEET Minor Test - 2 - Question 1

Fup =2000g + 3000

= 23000N

Minimum power =

= 34500W

NEET Minor Test - 2 - Question 2

### The distance covered by a body of mass 5g having linear momentum 0.3kgm∕s in 5s is:

Detailed Solution for NEET Minor Test - 2 - Question 2
P = mv

0.3 = 5/1000 × v ⇒ v = 60m/s

Distance travelled in 5s = 60 × 5

= 300m

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NEET Minor Test - 2 - Question 3

### A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively

Detailed Solution for NEET Minor Test - 2 - Question 3
Let required height of body is y.

When body from rest falls through height (S – y)

Then under constant acceleration

v2 = 02 + 2g(S − y)

V = √2g(S − y) ......(1)

When body is at height y above ground. Potential energy of body of mass m

U = mgy

As per given condition kinetic energy, K = 3U

1/2m(v)2 = 3 × mg(y)

1/2 × m × 2g(S − y) = 3×mgy (using (1))

S − y = 3y

∴ y = S/4 .......(2)

NEET Minor Test - 2 - Question 4

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body A is

Detailed Solution for NEET Minor Test - 2 - Question 4
Fractional loss of KE of colliding body,

NEET Minor Test - 2 - Question 5

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when

Detailed Solution for NEET Minor Test - 2 - Question 5

We know that,

The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

NEET Minor Test - 2 - Question 6

A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be

Detailed Solution for NEET Minor Test - 2 - Question 6
Coefficient of Restitution (e) -

Ratio of relative velocity after collision to relative velocity before collision.

Let velocity of 4m mass is v after collision

then mv = 4mv

v = v/4v

= 1/4

= 0.25

NEET Minor Test - 2 - Question 7

Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50ms−1. Take 'g' constant with a value 10ms−2. The work done by the

(i) gravitational force and the

(ii) resistive force of air is

Detailed Solution for NEET Minor Test - 2 - Question 7
Here

m = 1g = 10−3kg,h = 1km = 1000m. v = 50ms−1, g = 10ms−2

(i) The work done by the gravitational force

= mgh = 10−3 × 10 × 1000 = 10J

(ii) The total work done by gravitational force and the resistive force of air is equal to change in kinetic energy of rain drop

NEET Minor Test - 2 - Question 8

Two identical balls A and B having velocities of 0.5ms−1 and 0.3ms−1 respectively collide elastically in one dimension. The velocities of B and A after the collision respectively will be

Detailed Solution for NEET Minor Test - 2 - Question 8
Masses of the balls are same and collision is elastic, so their velocity will be interchanged after collision.

∴ va = +uB = −0.3ms−1 and vB = vA = 0.5ms−1

NEET Minor Test - 2 - Question 9

A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8×10−4J by the end of the second revolution after the beginning of the motion?

Detailed Solution for NEET Minor Test - 2 - Question 9

Here,m = 10g = 10−2kg

R = 6.4cm = 6.4 × 10−2m, Kf = 8 × 10−4J

Ki = 0, at = ?

Using work energy theorem,

Work done by all the forces = Change in KE

NEET Minor Test - 2 - Question 10

What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that can complete the loop?

Detailed Solution for NEET Minor Test - 2 - Question 10
The minimum velocity with which a body of mass m must enter a vertical loop of radius R so that can complete the loop = √5gR
NEET Minor Test - 2 - Question 11

The heart of a man pump s 5 litres of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13. × 103kg/m3 and g=10m/s2 then the power of heart in watt is

Detailed Solution for NEET Minor Test - 2 - Question 11
Here, Volume of blood pumped by man’s heart,

V = 5 litres = 5 × 10−3m3 (∵ 1 litre =10−3m3)

Time in which this volume of blood pumps,

t = 1 min = 60 s

Pressure at which the blood pumps,

P = 150mm of Hg = 0.15 m of Hg

=

(∵ P = hρg)

∴ Power of the heart = PV / t

=

= 1.70W

NEET Minor Test - 2 - Question 12

On a frictionless surface, a block of mass M moving at speed v collides elastically with another block of same mass M which is initially at rest. After collision the first block moves at an angle 0 to its initial direction and has a speed v/3. The second block's speed after the collision

Detailed Solution for NEET Minor Test - 2 - Question 12
The situation is shown in the figure.

Let V be speed of second block after the collision.

As the collision is elastic, so kinetic energy is conserved.

According to conservation of kinetic energy,

NEET Minor Test - 2 - Question 13

Two particles of masses m1,m2 move with initial velocities u1 and u2.On collision, one of the particles get excited to higher level, after absorbing energy e. If final velocities of particles be v1 and v2 then we must have

Detailed Solution for NEET Minor Test - 2 - Question 13

Using energy conservation principle:

Initial energy is only in form of kinetic energy

final energy is in form of kinetic energy and potential energy ( excitation energy)

equation (i) and (ii)

Hence correct answer is option A.

NEET Minor Test - 2 - Question 14

A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three pieces. Two pieces, each of mass (m) move perpendicular to each other with equal speeds (v). The total kinetic energy generated due to explosion is

Detailed Solution for NEET Minor Test - 2 - Question 14
pi = pf

NEET Minor Test - 2 - Question 15

A particle with total energy E is moving in a potential energy region U(x). Motion of the particle is restricted to the region when

Detailed Solution for NEET Minor Test - 2 - Question 15

As the particle is moving in a potential energy region.

∴ Kinetic energy > 0

And, total energy E = K.E. + P.E

⇒ U(x) < E

NEET Minor Test - 2 - Question 16

The potential energy of a particle in a force field is

where A and B are positive constants and r is the distance of particle from the center of the field. For stable equilibrium, the distance of the particle is

Detailed Solution for NEET Minor Test - 2 - Question 16
here,

For equilibrium, dU/dr = 0

For stable equilibrium, d2U/dr2 > 0

So for stable equilibrium, the distance of the particle is = 2A/B

NEET Minor Test - 2 - Question 17

Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v and along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction

Detailed Solution for NEET Minor Test - 2 - Question 17

According to law of conservation of linear momentum along x-axis, we get

m1 × 0 + m2 × v = m1v′cosθ

m2v = m1v′cosθ ......(i)

According to law of conservation of linear momentum long y-axis, we get

Divide (ii) by (i), we get

tanθ = −1/2 or θ = tan−1(−1/2) to the x-axis

NEET Minor Test - 2 - Question 18

The potential energy of a system increases if work is done

Detailed Solution for NEET Minor Test - 2 - Question 18
When work is done upon a system by a conservative force then its potential energy increases.
NEET Minor Test - 2 - Question 19

A particle of mass m is released from rest and follows a parabolic path as shown. Assuming that the displacement of the mass from the origin is small, which graph correctly depicts the position of the particle as a function of time?

Detailed Solution for NEET Minor Test - 2 - Question 19
When the displacement of the mass from the origin is small, this

graph correctly depicts the position of the particle as a function of time.

NEET Minor Test - 2 - Question 20

A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to a mass of 3m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is

Detailed Solution for NEET Minor Test - 2 - Question 20

According to conservation of momentum, we get

where v′ is the final velocity after collision

NEET Minor Test - 2 - Question 21

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia IA and IB is

Detailed Solution for NEET Minor Test - 2 - Question 21

NEET Minor Test - 2 - Question 22

A solid homogeneous sphere is moving on a rough horizontal surface, partly rolling and partly sliding. During this kind of motion of the sphere

Detailed Solution for NEET Minor Test - 2 - Question 22
Angular momentum about point of contact is conserved because torque due to friction about point of contact will be zero.
NEET Minor Test - 2 - Question 23

A sphere of mass m and radius r rolls on a horizontal plane without slipping with the speed u. Now, if it rolls up vertically, the maximum height it would attain will be

Detailed Solution for NEET Minor Test - 2 - Question 23
The rolling sphere has rotational as well as translational kinetic energy.

∴ Kinetic energy =

From conservation of energy

NEET Minor Test - 2 - Question 24

The wheels on the old-time bicycle shown in the diagram have radii of 60.0 cm. and 10.0 cm. If the larger wheel is rotating at 12.0 rad s-1, what is the angular speed of the smaller wheel?

Detailed Solution for NEET Minor Test - 2 - Question 24
The linear velocity of both wheels will be the same

60 × 12 = 10×ω

NEET Minor Test - 2 - Question 25

Angular momentum is conserved

Detailed Solution for NEET Minor Test - 2 - Question 25
According to the law of conservation of angular momentum, if there is no external torque on the system, then the angular momentum remains constant.
NEET Minor Test - 2 - Question 26

If the earth shrinks such that its mass does not change but radius decreases to one-quarter of its original value then one complete day will take

Detailed Solution for NEET Minor Test - 2 - Question 26
We know that angular momentum of the spin = Iω

By the conservation of angular momentum

NEET Minor Test - 2 - Question 27

A solid sphere rolls down two different inclined planes of same height, but of different inclinations. In both cases,

Detailed Solution for NEET Minor Test - 2 - Question 27
In pure rolling, mechanical energy remains conserved. Therefore, when heights of inclines are equal, speed of sphere will be same in both the cases. But as acceleration down the plane, a ∝ sinθ therefore, acceleration and time of descent will be different
NEET Minor Test - 2 - Question 28

The angular speed of rotating rigid body is increased from 4ω to 5ω keeping moment of inertia constant. The percentage increase in its K.E is -

Detailed Solution for NEET Minor Test - 2 - Question 28

% increase K.E. =

NEET Minor Test - 2 - Question 29

The radius of a solid sphere is R and its density D. When it is made to rotate about an axis passing through any diameter of sphere, expression for its moment of inertia is

Detailed Solution for NEET Minor Test - 2 - Question 29

NEET Minor Test - 2 - Question 30

The equation τ = Iα is valid about which of the following?

Detailed Solution for NEET Minor Test - 2 - Question 30
The equation τ = Iα is valid about COM or axis of rotation but not about any other point.
NEET Minor Test - 2 - Question 31

A disc of radius 2m and mass 200kg is acted upon by a torque 100N-m. Its angular acceleration would be

Detailed Solution for NEET Minor Test - 2 - Question 31

F = ma
a = Wr
So, F = mwr
a = wr = acceleration
m = 200kg
F = 100 n-m, r = 2m, w = to be calculated
100 = 200 x w2

NEET Minor Test - 2 - Question 32

A solid sphere and a solid cylinder of same mass are rolled down on two inclined planes of heights h1 and h2 respectively. If at the bottom of the plane the two objects have same linear velocities, then the ratio of h1 : h2 is

Detailed Solution for NEET Minor Test - 2 - Question 32
In case of pure rolling,

for solid sphere and 1/2 for solid cylinder

At the bottom, both have the same linear velocities, i.e., they have the same translational kinetic energies

NEET Minor Test - 2 - Question 33

A particle of mass m moves along line PC with velocity ν as shown. What is the angular momentum of the particle about P?

Detailed Solution for NEET Minor Test - 2 - Question 33
The particle moves with linear velocity vv along line PC. The line of motion is through P. Hence angular momentum is zero.
NEET Minor Test - 2 - Question 34

A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is

Detailed Solution for NEET Minor Test - 2 - Question 34
L = mr2 ω. For given m and ω, L ∝ r2. If r is halved, the angular momentum L becomes one-fourth.
NEET Minor Test - 2 - Question 35

Two point masses of 0.3 kg and 0.7 kg are fixed at the ends of a rod of length 1.4 m and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum, is located at a distance of

Detailed Solution for NEET Minor Test - 2 - Question 35

Work done W = 1/2Iω2

if x is the distance of mass 0.3 kg from the centre of mass, we will have,

For work to be minimum, the moment of inertia (I)I

should be minimum,

or

or

= 0.98

NEET Minor Test - 2 - Question 36

Calculate the work done by a car against gravity in moving along a straight horizontal road. The mass of the car is 400 kg and the distance moved is 2 m.

Detailed Solution for NEET Minor Test - 2 - Question 36
Force of gravity acts on the car vertically downward while the car is moving along the horizontal road, i.e., the angle between them is 90°.

Work done by the car against gravity,

W = Fscos90° = 0

NEET Minor Test - 2 - Question 37

The potential energy for a conservative system is given by U = ax2 – bx, where aa and bb are positive constants. The law of the force governing the system is

Detailed Solution for NEET Minor Test - 2 - Question 37

In a conservative field F = -dU / dr

∴ F = −d / dx(ax2 − bx) = b − 2ax

NEET Minor Test - 2 - Question 38

The average energy consumed by a human being in a day is

Detailed Solution for NEET Minor Test - 2 - Question 38
The average energy consumed by a human being in a day is

NEET Minor Test - 2 - Question 39

The kilowatt-hour is the unit of

Detailed Solution for NEET Minor Test - 2 - Question 39
Kilowatt is the unit of power and hour is the unit of time,

The basic definition of power is rate of change of work done or energy with respect to time.

Power × Time = Energy

Kilowatt-hour is the unit of energy.

NEET Minor Test - 2 - Question 40

For inelastic collision between two spherical rigid bodies

Detailed Solution for NEET Minor Test - 2 - Question 40
In an inelastic collision, the particles do not regain their shape and size completely after collision. Some fraction of mechanical energy is retained by the colliding particles in the form of deformation potential energy. Thus the kinetic energy of particles no longer remains conserved. However, in the absence of external forces, law of conservation of linear momentum still holds good.
NEET Minor Test - 2 - Question 41

A shell of mass m is at rest initially. It explodes into three fragments having mass in the ratio 2 : 2 : 1. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is

Detailed Solution for NEET Minor Test - 2 - Question 41

Momentum of the system would remain conserved.

Initial momentum =0

Final momentum should also be zero.

Let masses be 2m,2m, and m

Momentum along x-direction =

Net momentum =

Now, 2√2mv = mv′

v′ = 2√2v

NEET Minor Test - 2 - Question 42

Two objects of mass 10kg and 20kg respectively are connected to the two ends of a rigid rod of length 10m with negligible mass. The distance of the center of mass of the system from the 10kg mass is

Detailed Solution for NEET Minor Test - 2 - Question 42

= 200 / 30

= 20 /3m

NEET Minor Test - 2 - Question 43

An energy of 484J is spent in increasing the speed of a flywheel from 60rpm to 360rpm. The moment of inertia of the flywheel is

Detailed Solution for NEET Minor Test - 2 - Question 43

ωi = 60rpm = 60 × 2π/60 = 2π rad/5

ωf = 360rpm = 360 × 2π/60 = 12π rad/5

Energy spent =

NEET Minor Test - 2 - Question 44

From a circular ring of mass ' M and radius ' R ' an arc corresponding to a 90° sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is ' K times ′MR2 '. Then the value of ' K is

Detailed Solution for NEET Minor Test - 2 - Question 44
Given that,

Mass of Ring = M; Radius of Ring = R

Now 90° arc is removed from circular ring, then mass removed = M/4

Mass of remaining portion = 3M/4

Moment of inertia of remaining part = ∫d mr2

So the value of K is 3/4

NEET Minor Test - 2 - Question 45

A disc of radius 2m and mass 100kg rolls on a horizontal floor. Its centre of mass has speed of 20cm∕s. How much work is needed to stop it?

Detailed Solution for NEET Minor Test - 2 - Question 45
Required work done = −(Kf − Ki)

= 0 + Ki = Ki

=

NEET Minor Test - 2 - Question 46

The given graph is a representation of kinetics of a reaction.

The y and x axes for zero and first order reactions, respectively are

Detailed Solution for NEET Minor Test - 2 - Question 46

- For zero order reaction

r = k[A]0

r = k (constant)

hence, ' y ' as 'rate' and ' x ' as concentration will give desired graph.

- For first order reaction

hence, ' y ' as 't 1 s. and ' x ' as concentration will give desired graph.

NEET Minor Test - 2 - Question 47

The half life of a first order reaction is 2000 years. If the concentration after 8000 years is 0.02M, then the initial concentration was:

Detailed Solution for NEET Minor Test - 2 - Question 47

= 4, (no. of half lives)

= 0.02 × 24 = 0.32M

NEET Minor Test - 2 - Question 48

For a reaction A → B, enthalpy of reaction is −4.2kJmol−1 and enthalpy of activation is 9.6kJmol−1. The correct potential energy profile for the reaction is shown in option.

Detailed Solution for NEET Minor Test - 2 - Question 48

ΔHrxn = (Ea)f − (Ea)b

−4.2 = (Ea)f − (Ea)b

−4.2 = 9.6 − (Ea)b

(Ea)b = 9.6 + 4.2 = 13.8kJmol−1

Since reaction is exothermic, so possible graph is (2) only.

Also (Ea)f < (Ea)b, so answer is option (2)

NEET Minor Test - 2 - Question 49

The rate constant for a first order reaction is 4.606 × 10−3s−1. The time required to reduce 2.0 g of the reactant to 0.2g is:

Detailed Solution for NEET Minor Test - 2 - Question 49
First order rate equation is

NEET Minor Test - 2 - Question 50

If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by

Detailed Solution for NEET Minor Test - 2 - Question 50
For 1st order reaction,

=

NEET Minor Test - 2 - Question 51

A first order reaction has a rate constant of 2.303× 10−3s−1. The time required for 40gof this reactant to reduce to 10g will be [ Given that log102 = 0.3010]

Detailed Solution for NEET Minor Test - 2 - Question 51
For a first order reaction,

= 602s

NEET Minor Test - 2 - Question 52

The correct difference between first and second order reactions is that

Detailed Solution for NEET Minor Test - 2 - Question 52
For the first order reaction,

which is independent of initial concentration [A]0.

For second order reaction,

Half-life depends on initial concentration of reactant.

NEET Minor Test - 2 - Question 53

Mechanism of a hypothetical reaction X2 + Y2 → 2XY, is given below :

(i) X2 ⇌ X + X (fast)

(ii) X + Y2 → XY + Y (slow)

(iii) X + Y → XY (fast)

The overall order of the reaction will be

Detailed Solution for NEET Minor Test - 2 - Question 53

X2 ⇌ X + X (fast)

X + Y2 → XY + Y (slow)

Slow step is the rate determining step.

Rate = k[X][Y2] ...(i)

Equilibrium constant for fast step, K = [X]2 / [X2]

[X] = √K[X2]

By substituting [X] in equation (i), we get

Rate =

∴ Order of reaction = 1/2 + 1 = 3/2

= 1.5

NEET Minor Test - 2 - Question 54

The decomposition of phosphine (PH3) on tungsten at low pressure is a first-order reaction. It is because the

Detailed Solution for NEET Minor Test - 2 - Question 54
At low pressure, rate is proportional to the surface coverage and is of first order while at high pressure, it follows zero order kinetics due to complete coverage of surface area.
NEET Minor Test - 2 - Question 55

The addition of a catalyst during a chemical reaction alters which of the following quantities?

Detailed Solution for NEET Minor Test - 2 - Question 55
A catalyst provides an alternate path to the reaction which has lower activation energy.
NEET Minor Test - 2 - Question 56

When initial concentration of a reactant is doubled in a reaction its half-life period is not affected. The order of the reaction is

Detailed Solution for NEET Minor Test - 2 - Question 56
Half-life period of a first order reaction is independent or initial concentration,

NEET Minor Test - 2 - Question 57

What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20°C to 35°C? (R = 8.314Imol−1K−1)

Detailed Solution for NEET Minor Test - 2 - Question 57

k2 = 2k1

T1 = 20 + 273 = 293K or T2 = 35 + 273 = 308K

R = 8.314Jmol−1K−1

Ea = 34673Jmol−1 or 34.7kJmol−1
NEET Minor Test - 2 - Question 58

In a zero-order reaction for every 10°C rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will become

Detailed Solution for NEET Minor Test - 2 - Question 58
At 10°C rise, rate increases by 2.

= 29 = 512 times

NEET Minor Test - 2 - Question 59

The unit of rate constant for a zero order reaction is

Detailed Solution for NEET Minor Test - 2 - Question 59
The units are molL−1s−1
NEET Minor Test - 2 - Question 60

Which one of the following statements for the order of a reaction is incorrect?

Detailed Solution for NEET Minor Test - 2 - Question 60
Order of a reaction is not always whole number. It can be zero, or fractional also.
NEET Minor Test - 2 - Question 61

A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :

Detailed Solution for NEET Minor Test - 2 - Question 61
The number of moles of ions produced by 1 mole of ionic compound = i

Applying,

ΔTf = i × Kf × m

0.00732 = i × ×1.86 × 0.002

Thus number of ions = 2

NEET Minor Test - 2 - Question 62

he boiling point of 0.2 mol kg-1 solution of X in water is greater than an equimolal solution of Y in water. Which one of the following statements is true in this case?

Detailed Solution for NEET Minor Test - 2 - Question 62
ΔTb = i Kb.m

Kb and mm are constant for solutions of X and Y. Greater ΔTb for solution X implies that ii (Van't Hoff factor) for X > 1 i.e., X undergoes dissociation.

NEET Minor Test - 2 - Question 63

Which of the following compounds corresponds Van't Hoff factor (i) to be equal to 2 for dilute solution?

Detailed Solution for NEET Minor Test - 2 - Question 63
Van't hoff factor

i = αn + (1 α)

MgSO4 ⟶ Mg+2 + SO42-

i = 2

NEET Minor Test - 2 - Question 64

Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:

Detailed Solution for NEET Minor Test - 2 - Question 64
Mole fraction of ether in the liquid mixture = (1 – 0.457) = 0.543

Partial pressure of ether = 0.543 ×443.5 = 240.78 mm

NEET Minor Test - 2 - Question 65

The boiling point of pure water is 373.15 K. If 32.5 g of KCN is dissolved in 100 mL of H2O, then what is the boiling point of the solution? (Assume that molarity =molality)

(Kb for H2O = 0.52 K kg mol−1)(Molar mass of KCN = 65 gm mol−1)

Detailed Solution for NEET Minor Test - 2 - Question 65

ΔTb = i × m × Kb

∴ Tb = 373.15 + 5.2 = 378.35 K

or Tb = (378.35 − 273.15) = 105.20C

NEET Minor Test - 2 - Question 66

Which of the following associated with isotonic solutions is not correct?

Detailed Solution for NEET Minor Test - 2 - Question 66
The solutions having the same osmatic pressure are called isotonic solution. They may not have same weight concentrations
NEET Minor Test - 2 - Question 67

A solution having 4 g of polyvinyl chloride polymer in one litre of dioxane was found to have an osmotic pressure of 4.1×10-4 atmatm at 27℃. The approximate molecular weight of the polymer is:

Detailed Solution for NEET Minor Test - 2 - Question 67

Given, weight of PVC, w= 4 g

Volume of solution, V=1 LV=1 L

Osmotic pressure, π = 4.1 × 10−4

Temperature, T = 27℃ = 27 + 273= 300 K

Applying π V = n RT

Or πV = w/M RT(M = molecular weight )

∴ M = 2.4 × 105

NEET Minor Test - 2 - Question 68

100 g of liquid A (molar mass: 140 g mol-1) was dissolved in 1000 g of liquid B (molar mass:180 g mol-1). The vapour pressure of pure liquid B was found to be 500 torr. What will be the vapour pressure of pure liquid A and its vapour pressure in the solution, respectively, if the total vapour pressure of the solution is 475 torr?

Detailed Solution for NEET Minor Test - 2 - Question 68

= 280.7 × 0.11 = 32 torr

NEET Minor Test - 2 - Question 69

The strongest reducing agent is:

Detailed Solution for NEET Minor Test - 2 - Question 69
H2S in the strongest reducing agent among these as the oxidation state of S is minimum in H2S i.e., –2.
NEET Minor Test - 2 - Question 70

Two solutions with same solute-solvent system exerts osmotic pressures of 6 atm 2 atm at 300 K, respectively. If these are separated by a semipermeable membrane, which would be observed?

Detailed Solution for NEET Minor Test - 2 - Question 70
Osmotic movement of solvent occurs from dilute (lower osmotic pressure) to concentrated (higher osmotic pressure) solution.
NEET Minor Test - 2 - Question 71

The right option for the statement "Tyndall effect is exhibited by", is:

Detailed Solution for NEET Minor Test - 2 - Question 71
• Tyndall effect is exhibited by colloidal solution only.

• Among the given options, Urea, NaCl and Glucose solutions are true solutions, so cannot show Tyndall effect.

• Starch solution is a colloidal solution therefore can show Tyndall effect.

NEET Minor Test - 2 - Question 72

Which mixture of the solutions will lead to the formation of negatively charged colloidal [AgI]I sol?

Detailed Solution for NEET Minor Test - 2 - Question 72

Generally charge present on the colloid is due to adsorption of common ion from dispersion medium.

Millimole of KI is maximum in option (2) (50 × 2 = 100)

so act as solvent and anion I is adsorbed by the colloid Agl formed

NEET Minor Test - 2 - Question 73

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of As2S3 are given below:

I. (NaCl) = 52,

II. (BaCl2) = 0.69,

III. (MgSO4) = 0.22

The correct order of their coagulating power is

Detailed Solution for NEET Minor Test - 2 - Question 73
Coagulating power ∝ 1/Coagulationvalue

Lower the coagulation value, higher is the coagulating power so, the correct order is : III > II > I

NEET Minor Test - 2 - Question 74