NEET Mock Test - 7 - NEET MCQ

Where μ₀ is the permeability of free space. Consider a circular loop of wire of radius r carrying a current I. Consider a current element dl of the loop.

The direction of dl is along the tangent, so dl ⊥ r. From Biot Savart law, magnetic field at the centre O due to this current element is

The magnetic field due to all such current elements will point into the plane of paper at the centre O. Hence the total magnetic field at the centre O is

For a coil of N turns,

The first excitation energy

K.E_max = 125 − 122.4 = 2.6  eV

Hence, 90  eV90  eV electron cannot excite it.

F = −k(x − ℓ) ⇒ where k = mω²

or qE = −mω²(x − ℓ) ⇒ At x = ℓ, E = 0

To the right of x = ℓ,E is −ve, so towards left and to the left of x = ℓ E is +ve.

V_min : θ = 180°

V_min : θ = 0°

Step 1: Find dimension of Planck's constant

Step 2: Find dimension of kinetic energy

[E] = [ML²T^-2]

Step 3: Find dimension of electric potential

[V] = [W/Q] = [ML²T^-2/AT] = [ML²A^-1T^-3]

The law of conservation of linear momentum gives

m₁v₁ + m₂v₂ = 0 or

Since de Broglie wavelength λ = h/(mv), we will have

= 1.0, which is choice (3).

H₂ + I₂ → 2HI

When 1 mole of H₂ and 1 mole of I₂ reacts, 2 moles of HI are formed in the same time interval.

Thus the rate may be expressed as

The negative sign signifies a decrease in concentration of the reactant with increase of time. But reaction rate reported will be positive.

KP for NH₄HS = P × P = P₂

Also given, 2P = 60 cm

∴ P=30 cm

KP = 30 × 30 = 900 cm²

Now, in the presence of NH₃,

C(CH₃)₄

Explanation:
In compound C(CH₃)₄, also known as tetramethylmethane or neopentane, each carbon atom is bonded only to other carbon atoms and hydrogen atoms. The oxidation state of carbon in this compound is -4 for the central carbon atom and -3 for the four methyl group carbon atoms. Hydrogen atoms have an oxidation state of +1. There are no atoms with a zero oxidation state in this compound.

In contrast, the other compounds listed contain atoms with zero oxidation states:
1. C₃O₂ - The carbon atoms in the middle have an oxidation state of zero.
2. Na₂S₄O₆ - The central sulfur atoms in the S4O6 group have an oxidation state of zero.
3. CaOCI₂ - The oxygen atom in the OCl group has an oxidation state of zero.

Ageing may be defined as the progressive deterioration in the structure and function of the cells, tissues and organs of the organism with an advancing age. The metabolic activity declines due to ageing.

Plastids are double membranous structures. Plastids are of three types: Chloroplast, leucoplast, chromoplast.

Chloroplasts contain its own DNA protein-synthesising machinery.

Leucoplast are of three types: amyloplast, proteinoplast and elaioplast. Amyloplasts can synthesize and store starch. Proteinoplasts store proteins but can not synthesise. Elaioplasts store lipids.

Leucoplasts are colourless plastids which generally occur near the nucleus in non-green cells and possess internal lamellae.

The classification system in biology consists of a hierarchy of ranks, which, from most general to most specific, are:

1. Domain
2. Kingdom
3. Phylum (or Division, in the case of plants)
4. Class
5. Order
6. Family
7. Genus
8. Species

Each rank represents a group of organisms that share common characteristics. The higher the rank, the more general the shared characteristics. The lower the rank, the more specific the shared characteristics.

In this case, the question is asking which of the given options is less general in characters compared to the genus. Since species is the next rank below genus in the classification system, it means that species will have more specific shared characteristics than genus. Therefore, species is less general in characters compared to the genus.

(2) Reproductive phase – It is the time when a human organism sexually reproduces.

(3) Senescent phase – It is the time when an organism grows older and loses the reproductive capacity.