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Test: NEET 2019 Past Year Paper - NEET MCQ


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Test: NEET 2019 Past Year Paper - Question 1

In which of the following processes, heat is neither absorbed nor released by a system?​

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 1
  • An adiabatic process is defined as a process in which no heat transfer takes place. This does not mean that the temperature is constant, but rather that no heat is transferred into or out from the system.
  • Heating in a called adiabatic condition occurs when the pressure of a gas is increased by the work done on it. An example of adiabatic heating is that of a heat engine piston that compresses a gas contained within a cylinder. Gas compression leads to a temperature rise.
Test: NEET 2019 Past Year Paper - Question 2

Increase in temperature of a gas filled in a container would lead to :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 2

Increase in temperature would lead to the
increase in kinetic energy of gas (assuming
far as to be ideal) as 

Test: NEET 2019 Past Year Paper - Question 3

The total energy of an electron in an atom in an orbit is –3.4 eV. Its kinetic and potential energies are, respectively:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 3

In Bohr's model of H atom

∴ K.E. = 3.4 eV
U = –6.8 eV

Test: NEET 2019 Past Year Paper - Question 4

The correct Boolean operation represented by the circuit diagram drawn is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 4

From the given logic circuit LED will glow,
when voltage across LED is high.

Truth Table

This is output of NAND gate.

Test: NEET 2019 Past Year Paper - Question 5

A block of mass 10 kg is in contact against the inner wall of a hollow cylindrical drum of radius 1 m. The coefficient of friction between the block and the inner wall of the cylinder is 0.1. The minimum angular velocity needed for the cylinder to keep the block stationary when the cylinder is vertical and rotating about its axis, will be : (g 10 m/s2 )

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 5

For equilibrium of the block limiting friction
fL≥ mg
⇒ μN ≥ mg

Test: NEET 2019 Past Year Paper - Question 6

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in
nature. After the collision the fraction of energy lost by the colliding body A is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 6

Fractional loss of KE of colliding body

Test: NEET 2019 Past Year Paper - Question 7

The speed of a swimmer in still water is 20 m/s. The speed of river water is 10 m/s andis flowing due east. If he is standing on the south bank and wishes to cross the river along the shortest path, the angle at which he should make his strokes w.r.t. north is given by :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 7

VSR = 20m/s
VRG =  10m/s

sin θ = 10/20

sin θ = 1/2

θ = 300 west

Test: NEET 2019 Past Year Paper - Question 8

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 8



The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

Test: NEET 2019 Past Year Paper - Question 9

The displacement of a particle executing simple harmonic motion is given by
y = A0+ Asinωt + Bcosωt
Then the amplitude of its oscillation is given by :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 9

y = A0+ Asinωt + Bsinωt
Equate SHM

y' = y – A= Asinωt + Bcosωt
Resultant amplitude

Test: NEET 2019 Past Year Paper - Question 10

A 800 turn coil of effective area 0.05 m2 is kept perpendicular to a magnetic field 5 × 10–5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 10

Magnetic field B = 5 × 10–5 T
Number of turns in coil N = 800
Area of coil A = 0.05 m2
Time taken to rotate Δt = 0.1 s
Initial angle θ1 = 0°
Final angle θ2= 90°

Change in magnetic flux Δφ
= NBAcos90° –NBAcos0°
= – NBA
= – 800 × 5 × 10–5 × 0.05
= – 2 × 10–3 weber

Test: NEET 2019 Past Year Paper - Question 11

Average velocity of a particle executing SHM in one complete vibration is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 11

In one complete vibration, displacement is zero. So, average velocity in one complete vibration

Test: NEET 2019 Past Year Paper - Question 12

A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of 2.5 × 10-2 N/m. The pressure inside the bubble equals at a point Z0 below the free surface of water in a container. Taking g = 10 m/s2, density of water = 103 kg/m3, the value of Z0 is 

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 12

Excess pressure = 4T/R, Gauge pressure

Test: NEET 2019 Past Year Paper - Question 13

A copper rod of 88 cm and an aluminium rod of unknown length have their increase in length independent of increase in temperature. The length of aluminium rod is:
(αCu = 1.7 × 10-5 K-1 and αAl = 2.2 × 10-5 K-1)

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 13

αCuLCu = αAlLAl
1.7 × 10–5 × 88 cm = 2.2 × 10-5 × LAl

Test: NEET 2019 Past Year Paper - Question 14

The unit of thermal conductivity is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 14

The heat current related to difference of temperature across the length l of a conductor of area A is
 (K = coefficient of thermal conductivity)

Unit of K = Wm–1 K–1

Test: NEET 2019 Past Year Paper - Question 15

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 15


U = 1/2 ((work done by gravity)

Test: NEET 2019 Past Year Paper - Question 16

A disc of radius 2 m and mass 100 kg rolls on a horizontal floor. Its centre of mass has speed of 20 cm/s. How much work is needed to stop it?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 16

Work required = change in kinetic energy Final KE = 0
Initial KE 

|ΔKE| = 3 J

Test: NEET 2019 Past Year Paper - Question 17

In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where  will be

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 17

Given

 

= 2% + 1%+ 1%+ 12%
= 16%

Test: NEET 2019 Past Year Paper - Question 18

A body weighs 200 N on the surface of the earth. How much will it weigh half way down to the centre of the earth ?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 18


Acceleration due to gravity at a depth d from surface of earth

Where g = acceleration due to gravity at earth's surface
Multiplying by mass 'm' on both sides of (1)

Test: NEET 2019 Past Year Paper - Question 19

Which colour of the light has the longest wavelength?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 19

Red has the longest wavelength among the given options.

Test: NEET 2019 Past Year Paper - Question 20

A solid cylinder of mass 2 kg and radius 4 cm is rotating about its axis at the rate of 3 rpm. The torque required to stop after 2π revolutions is

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 20

Work energy theorem.

θ = 2π revolution    
= 2π × 2π = 4π2 rad



Test: NEET 2019 Past Year Paper - Question 21

The radius of circle, the period of revolution, initial position and sense of revolution are indicated in the fig.

y - projection of the radius vector of rotating particle P is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 21

At t = 0, y displacement is maximum, so equation will be cosine function.

T = 4 s

y = a cosωt

Test: NEET 2019 Past Year Paper - Question 22

A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 22


Charge Q will be distributed over the surface of hollow metal sphere. (i) For r < R (inside)
By Gauss law, 
⇒ Ein = 0  (∵ qen = 0)
(ii) For r > R (outside)


Test: NEET 2019 Past Year Paper - Question 23

In which of the following devices, the eddy current effect is not used?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 23

Electric heater does not involve Eddy currents. It uses Joule's heating effect.

Test: NEET 2019 Past Year Paper - Question 24

Six similar bulbs are connected as shown in the figure with a DC source of emf E and zero internal resistance.
The ratio of power consumption by the bulbs when (i) all are glowing and (ii) in the situation when two from section A and one from section B are glowing, will be :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 24

(i) All bulbs are glowing


(ii) Two from section A and one from section B are glowing.

Test: NEET 2019 Past Year Paper - Question 25

At a point A on the earth's surface the angle of dip σ = + 25°. At a point B on the earth's surface the angle of dip, σ = - 25°. We can interpret that :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 25

point A is located in the Northern hemisphere and point B is located in the southern hemisphere.
basically, angle of dip is the angle made by resultant earth's magnetic field from horizontal.

  • angle of dip at equator is considered as zero.
  • angle of dip in northern hemisphere is considered as positive.
  • angle o dip in southern hemisphere is considered as negative.

here, at point A on the earth's surface,
angle of dip is +25° (i.e., positive) so, point A is located in the Northern hemisphere
and point B on the earth's surface, angle of dip is -25° (i.e., negative) so, point B is located in he southern hemisphere.

Test: NEET 2019 Past Year Paper - Question 26

A force F = 20 + 10 y acts on a particle in y direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 26

Work done by variable force is

Test: NEET 2019 Past Year Paper - Question 27

Pick the wrong answer in the context with rainbow.

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 27

Rainbow can't be observed when observer faces towards sun.

Test: NEET 2019 Past Year Paper - Question 28

A cylindrical conductor of radius R is carrying a constant current. The plot of the magnitude of the magnetic field. B with the distance d from the centre of the conductor, is correctly represented by the figure :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 28


Inside (d < R) Magnetic field inside conductor

or B = Kd ...(i)
Straight line passing through origin
At surface (d = R)
 ...(ii)
Maximum at surface
Outside (d > R)

Test: NEET 2019 Past Year Paper - Question 29

Two particles A and B are moving in uniform circular motion in concentric circles of radii rA and rB with speed vA and vB respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 29


Test: NEET 2019 Past Year Paper - Question 30

Two similar thin equi-convex lenses, of focal length f each, are kept coaxially in contact with each other such that the focal length of the combination is F1. When the space between the two lenses is filled with glycerine (which has the same refractive index (μ = 1.5) as that of glass) then the equivalent focal length is F2. The ratio F1 :  F2 will be :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 30



Equivalent focal length in air 
When glycerin is filled inside, glycerin lens behaves like a diverging lens of focal length (–f)

Test: NEET 2019 Past Year Paper - Question 31

In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 31


At i = ic, refracted ray  grazes  with the surface.
So angle of refraction is 90°.

Test: NEET 2019 Past Year Paper - Question 32

Two parallel infinite line charges with linear charge densities +λ C/m and λl C/m are placed at a distance of 2R in free space. What is the electric field mid-way between the two line charges?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 32



Electric field due to line charge (1)

Electric field due to line charge (2)

Test: NEET 2019 Past Year Paper - Question 33

For a p-type semiconductor, which of the following statements is true ?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 33

In p-type semiconductor, an intrinsic semiconductor is doped with trivalent impurities, that creates deficiencies of valence electrons called holes which are majority charge carriers.

Test: NEET 2019 Past Year Paper - Question 34

Which of the following acts as a circuit protection device?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 34

Fuse wire has less melting point so when excess current  flows, due to heat produced in it, it melts.

Test: NEET 2019 Past Year Paper - Question 35

A parallel plate capacitor of capacitance 20 mF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 35

Capacitance of capacitor C = 20 mF
= 20 × 10-6 F
Rate of change of potential 

 ic = 20 × 10–6 × 3
= 60 × 10–6 A
= 60 μA
As we know that id = ic = 60 mA

Test: NEET 2019 Past Year Paper - Question 36

In the circuits shown below, the readings of the voltmeters and the ammeters will be

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 36

For ideal voltmeter, resistance is infinite and for the ideal ammeter, resistance is zero.

Test: NEET 2019 Past Year Paper - Question 37

α-particle consists of :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 37

α-particle is nucleus of Helium which has two protons and two neutrons.

Test: NEET 2019 Past Year Paper - Question 38

An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) : (me = 9 × 10–31 kg)

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 38

For an electron accelerated through a potential V

Test: NEET 2019 Past Year Paper - Question 39

When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.
Then x1 : x2 will be:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 39



Test: NEET 2019 Past Year Paper - Question 40

A small hole with area of cross-section 2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g = 10 m/s2, the rate of flow of water through the open hole would be nearly

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 40


Rate of liquid flow

Test: NEET 2019 Past Year Paper - Question 41

Two point charges A and B, having charges +Q and –Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 41



If 25% of charge of A transferred to B then

Test: NEET 2019 Past Year Paper - Question 42

Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rH : ra will be :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 42

Test: NEET 2019 Past Year Paper - Question 43

A particle moving with velocity  is acted by three forces shown by the vector triangle PQR.
The velocity of the particle will :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 43


As forces are forming closed loop in same order


Test: NEET 2019 Past Year Paper - Question 44

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 44


Initial potential energy at earths surface is

Final potential energy at height h = R

As work done = Change in PE
∴ W = Uf – Ui
 (∵ GM = gR2)

Test: NEET 2019 Past Year Paper - Question 45

In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? (μwater = 4/3)

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 45

In air angular fringe width 
Angular fringe width in water

Test: NEET 2019 Past Year Paper - Question 46

Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is
(Given that 1 L bar = 100 J)

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 46

∴ Wirr = – Pext ΔV
= – 2 bar × (0.25 – 0.1) L
= – 2 × 0.15 L-bar
= – 0.30 L-bar
= – 0.30 × 100 J
= – 30 J

Test: NEET 2019 Past Year Paper - Question 47

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 47

Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)

= 18/4
= 9/2
So formula of compound will be 

C9A12 ⇒ C3A4

Test: NEET 2019 Past Year Paper - Question 48

pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is:

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 48


pH = 9 Hence pOH = 14 – 9 = 5
[OH] = 10–5 M

Thus Ksp = [Ca2+][OH]2

Test: NEET 2019 Past Year Paper - Question 49

The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber's process is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 49

Haber's process

20 moles need to be produced
2 moles of NH3 → 3 moles of H2
Hence 20 moles of  moles of H2

Test: NEET 2019 Past Year Paper - Question 50

For an ideal solution, the correct option is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 50

For ideal solution,
Δmix H = 0
Δmix S > 0
Δmix G < 0
Δmix V = 0

Test: NEET 2019 Past Year Paper - Question 51

For a cell involving one electron E°cell = 0.59 V at 298 K, the equilibrium constant for the cell reaction is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 51


(At equilibrium, Q = Keq and Ecell = 0)
 (from equation (i))

Test: NEET 2019 Past Year Paper - Question 52

Among the following, the one that is not a green house gas is

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 52

Fact
SO2 (g) is not a greenhouse gas.

Test: NEET 2019 Past Year Paper - Question 53

The number of sigma (s) and pi (p) bonds in pent-2-en-4-yne is

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 53


Number of σ bonds = 10
and number of π bonds = 3

Test: NEET 2019 Past Year Paper - Question 54

Which of the following diatomic molecular species has only π bonds according to Molecular Orbital Theory?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 54

MO configuration C2 is:

Test: NEET 2019 Past Year Paper - Question 55

Which of the following reactions are disproportionation reaction?
(a) 2Cu+ → Cu2++ Cu0
(b) 
(c) 
(d) 

Select the correct option from the following

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 55

Disproportionation
Disproportionation
 ∴ Not a disproportionation

Test: NEET 2019 Past Year Paper - Question 56

Among the following, the narrow spectrum antibiotic is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 56

Penicillin G is a narrow spectrum antibiotic. It is used for the specific infection when the causative organism is known and will not kill as many of the normal microorganisms as a broad spectrum antibiotic in the body.

Test: NEET 2019 Past Year Paper - Question 57

The correct order of the basic strength of methyl substituted amines in aqueous solution is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 57

In aqueous solution, electron donating inductive effect, solvation effect (H-bonding) and steric hindrance all together affect basic strength of substituted amines
Basic character :

Test: NEET 2019 Past Year Paper - Question 58

Which mixture of the solutions will lead to the formation of negatively charged colloidal [Agl]l sol ?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 58

Generally charge present on the colloid is due to adsorption of common ion from dispersion medium. Millimole of KI is maximum in option (2) (50 × 2 = 100) so act as solvent and anion I is adsorbed by the colloid AgI formed

Test: NEET 2019 Past Year Paper - Question 59

Conjugate base for acids H2O and HF are :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 59


HF on loss of ion becomes is the conjugate base of HF
Example :

Test: NEET 2019 Past Year Paper - Question 60

Which will make basic buffer?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 60


This is basic solution due to NaOH.
This is not basic buffer.

Hydrolysis of salt takes place.
This is not basic buffer.

This is basic buffer

⇒ Neutral solution

Test: NEET 2019 Past Year Paper - Question 61

The compound that is most difficult to protonate is :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 61

Due to involvement of lone pair of electrons in resonance in phenol, it will have positive charge (partial), hence incoming proton will not be able to attack easily.

Test: NEET 2019 Past Year Paper - Question 62

The most suitable reagent for the following conversion, is :​

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 62

Test: NEET 2019 Past Year Paper - Question 63

Which of the following species is NOT stable?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 63

Due to presence of d-orbital in Si, Ge and Sn they form species like SiF62–, [GeCl6]2–, [Sn(OH)6]2–
SiCl62– does not exist because six large chloride ions cannot be accommodated around Si4+ due to limitation of its size.

Test: NEET 2019 Past Year Paper - Question 64

Which of the following is an amphoteric hydroxide?

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 64

Be(OH)2 amphoteric in nature, since it can react both with acid and base
Be(OH)2 + 2HCl → BeCl2 + 2H2O Be(OH)2 + 2NaOH → Na2 [Be(OH)4]

Test: NEET 2019 Past Year Paper - Question 65

The structure of intermediate A in the following reaction, is

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 65

Test: NEET 2019 Past Year Paper - Question 66

The manganate and permanganate ions are tetrahedral, due to :

Detailed Solution for Test: NEET 2019 Past Year Paper - Question 66

Manganate (MnO42–) : 
⇒ π-bonds are of dπ-pπ type
Permanganate (MnO4) : 
⇒ π-bonds are of dπ-pπ type